Equation 10-12: pH = ½ (pKa₁ + pKa2) is applicable for which of the following solutions? I. 1.0 x 10-3 M H3PO4 pka3 = 12.375] II. 1.0 x 10-3 M H2SO3 III. 1.0 x 108 M H2SO3 IV. 1.0 x 10-8 M H2C2O4 [pKa₁ = 2.148; pKa2 = 7.198; [pKa₁ = 1.857; pKa2 = 7.172] [pKa₁ = 1.857; pKa2 = 7.172] [pKa₁ = 1.250; pKa2 = 4.266] a. Il only b. II and IV c. IV only d. I only e. I, II, III, and IV f. Ill only g. I, II, and IV The pH of 0.050 M K₂HPO4 is Use the pKa values given in Question 9. The pH of 0.050 M K3PO4 is Use the information given in Question 9 for H3PO4. Hint: A quadratic equation is involved.
Equation 10-12: pH = ½ (pKa₁ + pKa2) is applicable for which of the following solutions? I. 1.0 x 10-3 M H3PO4 pka3 = 12.375] II. 1.0 x 10-3 M H2SO3 III. 1.0 x 108 M H2SO3 IV. 1.0 x 10-8 M H2C2O4 [pKa₁ = 2.148; pKa2 = 7.198; [pKa₁ = 1.857; pKa2 = 7.172] [pKa₁ = 1.857; pKa2 = 7.172] [pKa₁ = 1.250; pKa2 = 4.266] a. Il only b. II and IV c. IV only d. I only e. I, II, III, and IV f. Ill only g. I, II, and IV The pH of 0.050 M K₂HPO4 is Use the pKa values given in Question 9. The pH of 0.050 M K3PO4 is Use the information given in Question 9 for H3PO4. Hint: A quadratic equation is involved.
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Chapter1: Chemical Foundations
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![Equation 10-12: pH = ½ (pKa₁ + pKa2) is applicable for which
of the following solutions?
I. 1.0 x 10-3 M H3PO4
pka3 = 12.375]
II. 1.0 x 10-3 M H2SO3
III. 1.0 x 108 M H2SO3
IV. 1.0 x 10-8 M H2C2O4
[pKa₁ = 2.148; pKa2 = 7.198;
[pKa₁ = 1.857; pKa2 = 7.172]
[pKa₁ = 1.857; pKa2 = 7.172]
[pKa₁ = 1.250; pKa2 = 4.266]
a. Il only
b. II and IV
c. IV only
d. I only
e. I, II, III, and IV
f. Ill only
g. I, II, and IV
The pH of 0.050 M K₂HPO4 is
Use the pKa values given in Question 9.
The pH of 0.050 M K3PO4 is
Use the information given in Question 9 for H3PO4.
Hint: A quadratic equation is involved.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2480c5c0-690d-472b-9712-65962b3732cd%2F6ea01398-8f5e-421a-90dc-89a8ccd143c6%2Fnl3mz1i_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Equation 10-12: pH = ½ (pKa₁ + pKa2) is applicable for which
of the following solutions?
I. 1.0 x 10-3 M H3PO4
pka3 = 12.375]
II. 1.0 x 10-3 M H2SO3
III. 1.0 x 108 M H2SO3
IV. 1.0 x 10-8 M H2C2O4
[pKa₁ = 2.148; pKa2 = 7.198;
[pKa₁ = 1.857; pKa2 = 7.172]
[pKa₁ = 1.857; pKa2 = 7.172]
[pKa₁ = 1.250; pKa2 = 4.266]
a. Il only
b. II and IV
c. IV only
d. I only
e. I, II, III, and IV
f. Ill only
g. I, II, and IV
The pH of 0.050 M K₂HPO4 is
Use the pKa values given in Question 9.
The pH of 0.050 M K3PO4 is
Use the information given in Question 9 for H3PO4.
Hint: A quadratic equation is involved.
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