For a 8.40×10-² M solution of H₂CO3, calculate both the pH and the CO3²- ion concentration. H₂CO3 + H₂O HCO3 + H₂0 H3O+ + HCO3¯ Kal 4.2x10-7 H3O+ + CO3²- Ka2 = 4.8x10-11 pH = [CO32-] = M
For a 8.40×10-² M solution of H₂CO3, calculate both the pH and the CO3²- ion concentration. H₂CO3 + H₂O HCO3 + H₂0 H3O+ + HCO3¯ Kal 4.2x10-7 H3O+ + CO3²- Ka2 = 4.8x10-11 pH = [CO32-] = M
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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![For a 8.40x10-2 M solution of H₂CO3, calculate both the pH and the CO32- ion
concentration.
H₂CO3 + H₂O H3O+ + HCO3 Kal = 4.2x 10-7
HCO3 + H₂0
H3O+ + CO3²-
Ka2 = 4.8x10-11
=
pH =
[CO32-] =
M](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb6d50391-92c3-428f-a052-8385218d41f0%2Ffd671462-c53b-492f-b195-81499118a6b3%2F78s2l3j_processed.jpeg&w=3840&q=75)
Transcribed Image Text:For a 8.40x10-2 M solution of H₂CO3, calculate both the pH and the CO32- ion
concentration.
H₂CO3 + H₂O H3O+ + HCO3 Kal = 4.2x 10-7
HCO3 + H₂0
H3O+ + CO3²-
Ka2 = 4.8x10-11
=
pH =
[CO32-] =
M
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