Question 13 Determine the pH of a 0.65 M solution of HCO,K. The value of Ka for HCOOH is 1.8 x 10. 2 NEXT > Based on the given values, set up ICE table in order to determine the unknown. HCOO (aq) H̟O(1) OH(aq) HCOOH(aq) + Initial (M) Change (M) Equilibrium (M) 5 RESET 0.65 1.8 x 104 0.33 +x -x +2x -2x 0.65 + x 0.65 - x 0.65 + 2x 0.65 - 2x 1.8 x 104 + x 1.8 x 10-x 1.8 x 10 + 2x 1.8 x 10-2x
Question 13 Determine the pH of a 0.65 M solution of HCO,K. The value of Ka for HCOOH is 1.8 x 10. 2 NEXT > Based on the given values, set up ICE table in order to determine the unknown. HCOO (aq) H̟O(1) OH(aq) HCOOH(aq) + Initial (M) Change (M) Equilibrium (M) 5 RESET 0.65 1.8 x 104 0.33 +x -x +2x -2x 0.65 + x 0.65 - x 0.65 + 2x 0.65 - 2x 1.8 x 104 + x 1.8 x 10-x 1.8 x 10 + 2x 1.8 x 10-2x
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
Transcribed Image Text:Question 13
Determine the pH of a 0.65 M solution of HCO,K. The value of Ka for HCOOH is
1.8 x 104.
1
2
NEXT
>
Based on the given values, set up ICE table in order to determine the unknown.
HCOO (aq)
H̟O(1)
OH(aq)
HCOOH(aq)
+
Initial (M)
Change (M)
Equilibrium (M)
5 RESET
0.65
1.8 x 104
0.33
+x
-x
+2x
-2x
0.65 + x
0.65 - x
0.65 + 2x
0.65 - 2x
1.8 x 10* + x
1.8 x 10-x
1.8 x 10* + 2x
1.8 x 10-2x
![Determine the pH of a 0.65 M solution of HCO,K. The value of Ka for HCOOH is
1.8 x 10.
PREV
1
3
NEXT
Based on your ICE table and definition of Kb, set up the expression for Kb in order to determine
the unknown. Do not combine or simplify terms.
K,
%3D
5 RESET
[0]
[0.65]
[1.8 x 10)
[0.33]
[x]
[2x]
[2x]?
[0.65 + x]
[0.65 - x]
[0.65 + 2x]
[0.65 - 2x]
[1.8 x 10* + x]
(1.8 × 10* - x]
[1.8 x 10* + 2x]
[1.8 x 10*- 2x]
1.8 × 10*
1.8 x 1010
5.6 x 1011](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb3c12dbc-7691-49ef-84dd-9e94ae22700e%2Fb57d2598-5f9f-4002-94d8-8c665fb4b3f8%2F3ng0h2k_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Determine the pH of a 0.65 M solution of HCO,K. The value of Ka for HCOOH is
1.8 x 10.
PREV
1
3
NEXT
Based on your ICE table and definition of Kb, set up the expression for Kb in order to determine
the unknown. Do not combine or simplify terms.
K,
%3D
5 RESET
[0]
[0.65]
[1.8 x 10)
[0.33]
[x]
[2x]
[2x]?
[0.65 + x]
[0.65 - x]
[0.65 + 2x]
[0.65 - 2x]
[1.8 x 10* + x]
(1.8 × 10* - x]
[1.8 x 10* + 2x]
[1.8 x 10*- 2x]
1.8 × 10*
1.8 x 1010
5.6 x 1011
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