Determine the number of grams of NH Br needed to prepare an aqueous solution at a specific pH by constructing an ICE table, writing the equilibrium constant expression, and using this information to determine the initial grams of NH Br required. The Kb of NH, is 1.8 × 10%. Complete Parts 1-3 before submitting your answer. 1 2 3 NEXT > An unknown quantity of NH Br is dissolved in 1.00 L of water to produce a solution with a pH = 5.16. Let x represent the original concentration of NH* in the water. Fill in the ICE table with the appropriate value for each involved species to determine concentrations of all reactants and products. Initial (M) Change (M) Equilibrium (M) NH,(aq) + H₂O(1) = HO*(aq) Xx 0 -6.9 × 10€ x-6.9 × 10-6 NH,(aq) 0 6.9 × 10€ 6.9 x 10 6.9 × 10-6 6.9 × 10€ RESET 0.5x 0 1.00 5.16 1.8 x 10-5 x 2x -x -2x -0.5x 6.9 x 100 -6.9 x 10* 0.709 -0.709 x+6.9 x 10-6 x-6.9 x 10-6 x +0.709 x-0.709 MacBook Air

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Determine the number of grams of NH Br needed to prepare an aqueous solution
at a specific pH by constructing an ICE table, writing the equilibrium constant
expression, and using this information to determine the initial grams of NH Br
required. The Kb of NH, is 1.8 × 10%. Complete Parts 1-3 before submitting your
answer.
1
2
3
NEXT >
An unknown quantity of NH Br is dissolved in 1.00 L of water to produce a solution with a pH =
5.16. Let x represent the original concentration of NH* in the water. Fill in the ICE table with the
appropriate value for each involved species to determine concentrations of all reactants and
products.
Initial (M)
Change (M)
Equilibrium (M)
NH,(aq)
+
H₂O(1)
x
-6.9 × 10€
x-6.9 × 10-6
=
HO*(aq)
0
NH,(aq)
0
6.9 × 10-6
6.9 x 10
6.9 × 10-6
6.9 × 10€
RESET
0
1.00
5.16
1.8 x 10-5
x
2x
0.5x
-x
-2x
-0.5x
6.9 × 10-0
-6.9 × 10*
0.709
-0.709
x+6.9 x 10-6
x-6.9 x 10-6
x +0.709
x-0.709
MacBook Air
Transcribed Image Text:Determine the number of grams of NH Br needed to prepare an aqueous solution at a specific pH by constructing an ICE table, writing the equilibrium constant expression, and using this information to determine the initial grams of NH Br required. The Kb of NH, is 1.8 × 10%. Complete Parts 1-3 before submitting your answer. 1 2 3 NEXT > An unknown quantity of NH Br is dissolved in 1.00 L of water to produce a solution with a pH = 5.16. Let x represent the original concentration of NH* in the water. Fill in the ICE table with the appropriate value for each involved species to determine concentrations of all reactants and products. Initial (M) Change (M) Equilibrium (M) NH,(aq) + H₂O(1) x -6.9 × 10€ x-6.9 × 10-6 = HO*(aq) 0 NH,(aq) 0 6.9 × 10-6 6.9 x 10 6.9 × 10-6 6.9 × 10€ RESET 0 1.00 5.16 1.8 x 10-5 x 2x 0.5x -x -2x -0.5x 6.9 × 10-0 -6.9 × 10* 0.709 -0.709 x+6.9 x 10-6 x-6.9 x 10-6 x +0.709 x-0.709 MacBook Air
Determine the number of grams of NH Br needed to prepare an aqueous solution
at a specific pH by constructing an ICE table, writing the equilibrium constant
expression, and using this information to determine the initial grams of NH Br
required. The Kb of NH, is 1.8 × 105. Complete Parts 1-3 before submitting your
answer.
PREV
1
2
3
NEXT
>
Based on your ICE table and the definition of Kb, set up the expression for Ka in order to
determine the unknown concentration. Each reaction participant must be represented by one tile.
Do not combine terms.
Ka
=
RESET
[0]
[1.00]
[5.16]
[1.8 × 105]
[x]
[2x]
[0.5x]
[6.9 x 10%]
[0.709]
[x+6.9 x 10-6]
[x - 6.9 × 10-6]
[x + 0.709]
[x-0.709]
0
1.8 × 10-5
4.7
5.6 x 10.10
1.8 × 10-19
Transcribed Image Text:Determine the number of grams of NH Br needed to prepare an aqueous solution at a specific pH by constructing an ICE table, writing the equilibrium constant expression, and using this information to determine the initial grams of NH Br required. The Kb of NH, is 1.8 × 105. Complete Parts 1-3 before submitting your answer. PREV 1 2 3 NEXT > Based on your ICE table and the definition of Kb, set up the expression for Ka in order to determine the unknown concentration. Each reaction participant must be represented by one tile. Do not combine terms. Ka = RESET [0] [1.00] [5.16] [1.8 × 105] [x] [2x] [0.5x] [6.9 x 10%] [0.709] [x+6.9 x 10-6] [x - 6.9 × 10-6] [x + 0.709] [x-0.709] 0 1.8 × 10-5 4.7 5.6 x 10.10 1.8 × 10-19
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