Determine the pH of a solution of HC3H5O2 by constructing an ICE table, writing the equilibrium constant expression, and using this information to determine the pH. The Ka of HC3H5O2 is 1.3 x 10-5. Complete Parts 1-3 before submitting your answer. 2 3 NEXT > A 0.100 M aqueous solution of HC3H5O2 is prepared. Fill in the ICE table with the appropriate value for each involved species to determine concentrations of all reactants and products. Initial (M) Change (M) Equilibrium (M) HC3H5O2(aq) H₂O(1) 10 H3O*(aq) C3H5O2 (aq) RESET +2x 0 0.100 1.3 x 10-5 0.200 +x -x -2x 0.100 + x 0.100-x 0.100 + 2x 0.100 - 2x 1.3 x 10-5 + x 1.3 x 10-5 - x 1.3 x 10-5 + 2x 1.3 x 10-5-2x APR 3 Stv A MacBook Air 9 Determine the pH of a solution of HC3H5O2 by constructing an ICE table, writing the equilibrium constant expression, and using this information to determine the pH. The Ka of HC3H5O2 is 1.3 x 105. Complete Parts 1-3 before submitting your answer. < PREV 1 2 3 NEXT > Based on your ICE table and the definition of Ka, set up the expression for Ka in order to determine the unknown. Each reaction participant must be represented by one tile. Do not combine terms. Ka = [0] [0.100] [0.100-x] [0.100 + 2x] [1.3 x 10-5] [0.100 -2x] APR [0.200] [x] = 1.3 x 10-5 [2x] RESET [2x]² [0.100+x] [1.3 x 10-5+x] [1.3 x 10-x] [1.3 x 105+2x] [1.3 x 10-5-2x] Ntv A MacBook Air
Determine the pH of a solution of HC3H5O2 by constructing an ICE table, writing the equilibrium constant expression, and using this information to determine the pH. The Ka of HC3H5O2 is 1.3 x 10-5. Complete Parts 1-3 before submitting your answer. 2 3 NEXT > A 0.100 M aqueous solution of HC3H5O2 is prepared. Fill in the ICE table with the appropriate value for each involved species to determine concentrations of all reactants and products. Initial (M) Change (M) Equilibrium (M) HC3H5O2(aq) H₂O(1) 10 H3O*(aq) C3H5O2 (aq) RESET +2x 0 0.100 1.3 x 10-5 0.200 +x -x -2x 0.100 + x 0.100-x 0.100 + 2x 0.100 - 2x 1.3 x 10-5 + x 1.3 x 10-5 - x 1.3 x 10-5 + 2x 1.3 x 10-5-2x APR 3 Stv A MacBook Air 9 Determine the pH of a solution of HC3H5O2 by constructing an ICE table, writing the equilibrium constant expression, and using this information to determine the pH. The Ka of HC3H5O2 is 1.3 x 105. Complete Parts 1-3 before submitting your answer. < PREV 1 2 3 NEXT > Based on your ICE table and the definition of Ka, set up the expression for Ka in order to determine the unknown. Each reaction participant must be represented by one tile. Do not combine terms. Ka = [0] [0.100] [0.100-x] [0.100 + 2x] [1.3 x 10-5] [0.100 -2x] APR [0.200] [x] = 1.3 x 10-5 [2x] RESET [2x]² [0.100+x] [1.3 x 10-5+x] [1.3 x 10-x] [1.3 x 105+2x] [1.3 x 10-5-2x] Ntv A MacBook Air
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Can you please fill out the ice table and find the Ka
Transcribed Image Text:Determine the pH of a solution of HC3H5O2 by constructing an ICE table, writing
the equilibrium constant expression, and using this information to determine the
pH. The Ka of HC3H5O2 is 1.3 x 10-5. Complete Parts 1-3 before submitting your
answer.
2
3
NEXT
>
A 0.100 M aqueous solution of HC3H5O2 is prepared. Fill in the ICE table with the appropriate
value for each involved species to determine concentrations of all reactants and products.
Initial (M)
Change (M)
Equilibrium (M)
HC3H5O2(aq)
H₂O(1)
10
H3O*(aq)
C3H5O2 (aq)
RESET
+2x
0
0.100
1.3 x 10-5
0.200
+x
-x
-2x
0.100 + x
0.100-x
0.100 + 2x
0.100 - 2x
1.3 x 10-5 + x
1.3 x 10-5 - x
1.3 x 10-5 + 2x
1.3 x 10-5-2x
APR
3
Stv A
MacBook Air
9
![Determine the pH of a solution of HC3H5O2 by constructing an ICE table, writing
the equilibrium constant expression, and using this information to determine the
pH. The Ka of HC3H5O2 is 1.3 x 105. Complete Parts 1-3 before submitting your
answer.
<
PREV
1
2
3
NEXT
>
Based on your ICE table and the definition of Ka, set up the expression for Ka in order to
determine the unknown. Each reaction participant must be represented by one tile. Do not
combine terms.
Ka
=
[0]
[0.100]
[0.100-x]
[0.100 + 2x]
[1.3 x 10-5]
[0.100 -2x]
APR
[0.200]
[x]
= 1.3 x 10-5
[2x]
RESET
[2x]²
[0.100+x]
[1.3 x 10-5+x] [1.3 x 10-x] [1.3 x 105+2x] [1.3 x 10-5-2x]
Ntv A
MacBook Air](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F42021111-4ced-4c6f-84e9-5b1969157ec2%2F6b04346a-93a6-4247-bafd-011c03a12544%2F7bxldsn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Determine the pH of a solution of HC3H5O2 by constructing an ICE table, writing
the equilibrium constant expression, and using this information to determine the
pH. The Ka of HC3H5O2 is 1.3 x 105. Complete Parts 1-3 before submitting your
answer.
<
PREV
1
2
3
NEXT
>
Based on your ICE table and the definition of Ka, set up the expression for Ka in order to
determine the unknown. Each reaction participant must be represented by one tile. Do not
combine terms.
Ka
=
[0]
[0.100]
[0.100-x]
[0.100 + 2x]
[1.3 x 10-5]
[0.100 -2x]
APR
[0.200]
[x]
= 1.3 x 10-5
[2x]
RESET
[2x]²
[0.100+x]
[1.3 x 10-5+x] [1.3 x 10-x] [1.3 x 105+2x] [1.3 x 10-5-2x]
Ntv A
MacBook Air
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