A 25.0 mL aliquot of 0.0480 M EDTA was added to a 50.0 mL solution containing an unknown concentration of V³+. All of the V³+ present in the solution formed a complex with EDTA, leaving an excess of EDTA in solution. This solution was back- titrated with a 0.0330 M Ga³+ solution until all of the EDTA reacted, requiring 10.0 mL of the Ga³+ solution. What was the original concentration of the V3+ solution? [V³+] = M

A 25.0 mL aliquot of 0.0480 M EDTA was added to a 50.0 mL solution containing an unknown concentration of V³+. All of the V³+ present in the solution formed a complex with EDTA, leaving an excess of EDTA in solution. This solution was back- titrated with a 0.0330 M Ga³+ solution until all of the EDTA reacted, requiring 10.0 mL of the Ga³+ solution. What was the original concentration of the V3+ solution? [V³+] = M

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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ter answ Aqueo us sulfurous acid (H2S03) was made by dissolving 0.200 L of sulfur dioxide gas at 19°C and 745 mm Hg in water to yield 500.0 mL of solutio n. The acid solution required 17.6 mL of so dium hydroxide solution to reach the titration end point. What was the molarity of the sodium hy droxide solution? M NaOH IID $4 7. CO
Inbo (534) Conv I Balar b Ansv Post CHE 101 C X The bartl bartl bartl Cher Unkr O Sear E I ma G what app.101edu.co/# Bryant's Gmail Cascadia Canvas Lo... T GSBA Scholarship L... HOMEGROWN TRA... Learn Touch Typing... C The Science of Well... Investor360° ® Login ClickUp Reading list >> Question 31 of 40 Submit A 35.0 mL solution of NaOH is neutralized with 26.5 mL of 0.250 M HCI. What is the concentration of the original NaOH solution? | M 1 4 C 7 8 9 +/- х 100 + 11:15 PM e Type here to search 59°F 8/26/2021 LO (8)
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