2) Analysis of dissolved Ni in solution may be accomplished by complexation with DMG (dimethylglyoxime) via:.Ni²+ (aq) + 2 DMG (aq) ---------> Ni(DMG)2(s)red precipitate(Ni(DMG)2=288.91 g/mol)Excess DMG was added to 25.00 mL of a Ni²+ solution and produced 0.145 g Ni(DMG)2. What is the [Ni2+] in the originalsolution?

Given:Mass of Ni(DMG)2 = 0.145 g (3 significant figures)Volume of Ni2+ solution…

Answered: 2) Analysis of dissolved Ni in solution…

Chemical Principles in the Laboratory

11th Edition

ISBN:9781305264434

Author:Emil Slowinski, Wayne C. Wolsey, Robert Rossi

Publisher:Emil Slowinski, Wayne C. Wolsey, Robert Rossi

Chapter27: Relative Stabilities Of Complex Ions And Precipitates Prepared From Solutions Of Copper(ii)

Section: Chapter Questions

Problem 1ASA

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V15.
1. (Total 20 pts) Calculate a predominance diagram showing the solubility of Spertiniite - a rare Cu(II) hydroxide mineral, Cu(OH)2(s) - as a function of pH by plotting the logarithm of the concentration of each copper species against pH assuming the solution is in contact with Spertiniite. Consider only the following aqueous species: Cu²+; CuOH+; Cu(OH)2; Cu(OH)3. A. Write the reactions that form the aqueous species from Cu(OH)2(s) and the corresponding equilibrium relations. The equilibrium constants for the formation of the 4 aqueous species listed above are 108.68; K₂ = 100.98; K3 = 10–5; K4 = 10-18.2. (10 pt) B. Write the mass balance equation for the solution. (3 pt) C. Plot the total concentration of the dissolved species in a predominance diagram and indicate on the diagram the regions where the solution is oversaturated and undersaturated with Cu(II). Hint: The diagram can be drawn by hand. (7 pt) K₁ =
250.0 ml of the mineral water sample was precipitated with potassium sodium tetraphenyl bromate: K+ + B(C6H5)4-  KB(C6H5)(s). The precipitate was filtered, washed and dissolved in an organic solvent. An excess of HgY2- was added to the solution: 4 HgY2- + B(C6H5)4- +4H2O  H3BO3 + 4C6H5Hg+ + 4HY3- + OH-. The liberated EDTA was titrated with 0.05581 M Mg 2+ solution, which consumed 29.64 mL. Calculate the potassium concentration [mg/l] in the sample.
8.00mL aqueous suspension of elemental selenium is treated with 24.00mL ammonia 0.045M AgNO3 The reaction is as follows: 6Ag (NH3) 2 ++ 3Se (s) + 3H2O → 2Ag2Se (s) + Ag2SeO3 (s) + 6NH4 + After this reaction is completed, nitric acid is added to dissolve Ag2SeO3. However, Ag2Se does not dissolve during this time. Ag + consisting of dissolved Ag2SeO3 and the excess of the reagent requires 13.43mL 0.01294M KSCN in a Volhard titration. How many milligrams of Se are in each milliliter of sample? (Se = 78.96g / mol)
A 100-mL sulfide-containing water sample was titrated with 12.15 mL of 0.041 M AgNO3 to determine its S²- content. The titration resulted to the formation of Ag2S precipitate. Calculate the concentration of sulfides in ppm H₂S. (MW (g/mol): AgNO3=169.9; S=32.1; Ag2S=247.8; H₂S-34.1) Express your answer with 2 decimal places and do not encode the units.
a) What mass of Fe(NH4)2(SO4)2•2H2O(s) is required to prepare a 500 mL solution containing 100 ppm (m:v) in Fe? b) Using this stock solution, what aliquot must be used to prepare calibration solutions, 100 mL volume, of the following concentrations: 0.100 ppm, 0.500 ppm, 2.00 ppm, 4.00 ppm, and 7.00 ppm.
112. Solutions of sodium thiosulfate are used to dissolve unexposed AgBr (Kp and-white film. What mass of AgBr can dissolve in 1.00 L of 0.500 M Na,S,O;? Ag* reacts with S,O,- to form a complex ion: = 5.0 × 10-13) in the developing process for black- Ag*(aq) + 2S,O;²-(aq) = Ag(S,O;),-(aq) K = 2.9 X 1013
find ksp and solubility ONLY for the following blank items
1
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Directions: Solve the problem with a complete step-by-step solution. A 100.0-mL sample of brackish water was made ammoniacal, and the sulfide it contained was titrated with 16.47 mL of 0.02310 M AgNO3. The analytical reaction is 2Ag+ + S2- ---> Ag2S (s)Calculate the concentration of H2S in the water in parts per million, cppm.
I got 0.626. That was incorrect. How much potassium oxalate can be added to 156.0 mL of 0.5 M [Cu(NH3)4]Cl2 before a precipitate of CuC2O4 begins to form? Ksp(CuC2O4)=2.9x10-8 and Kf(Cu(NH3)42+)=1.1x1012 Include 3 significant figures

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