A 25.00 mL sample containing an unknown amount of Al and Pb* required 15.40 mL of 0.05788 M EDTA to reach the end point. A 50.00 mL sample of the unknown was then treated with F to mask the Al. To the 50.00 mL sample, 25.00 mL of 0.05788 M EDTA was added. The excess EDTA was then titrated with 0.02329 M Mn. A total of 27.5 ml. was required to reach the methylthymol blue end point. Determine pAl and pPb?+ in the unknown sample.
A 25.00 mL sample containing an unknown amount of Al and Pb* required 15.40 mL of 0.05788 M EDTA to reach the end point. A 50.00 mL sample of the unknown was then treated with F to mask the Al. To the 50.00 mL sample, 25.00 mL of 0.05788 M EDTA was added. The excess EDTA was then titrated with 0.02329 M Mn. A total of 27.5 ml. was required to reach the methylthymol blue end point. Determine pAl and pPb?+ in the unknown sample.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![A 25.00 mL sample containing an unknown amount of AI* and Pb+ required 15.40 mL of 0.05788 M EDTA to reach the end
point. A 50.00 mL sample of the unknown was then treated with F to mask the Al+. To the 50.00 mL sample, 25.00 mL of
0.05788 M EDTA was added. The excess EDTA was then titrated with 0.02329 M Mn2+. A total of 27.5 mL was required to
reach the methylthymol blue end point. Determine pAl+ and pPh?+ in the unknown sample.
PAI+](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffac5963e-6bf5-47f0-ba2c-8b89935f9f8b%2Fdebb9daa-571a-41eb-abea-1dd1b312e470%2F74n0i2m_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A 25.00 mL sample containing an unknown amount of AI* and Pb+ required 15.40 mL of 0.05788 M EDTA to reach the end
point. A 50.00 mL sample of the unknown was then treated with F to mask the Al+. To the 50.00 mL sample, 25.00 mL of
0.05788 M EDTA was added. The excess EDTA was then titrated with 0.02329 M Mn2+. A total of 27.5 mL was required to
reach the methylthymol blue end point. Determine pAl+ and pPh?+ in the unknown sample.
PAI+
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