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Please solve question 9 only. If it cannot be done without the values from the earlier parts, please substitute the values with another variable (such as X, Y, Z), make them explicit in the working out, and solve it through. It would help me a lot even if I only saw the working out for this question

Please solve question 9 only. If it cannot be done without the values from the earlier parts, please substitute the values with another variable (such as X, Y, Z), make them explicit in the working out, and solve it through. It would help me a lot even if I only saw the working out for this question

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Please solve question 9 only. If it cannot be done without the values from the earlier parts, please substitute the values with another variable (such as X, Y, Z), make them explicit in the working out, and solve it through. It would help me a lot even if I only saw the working out for this question.

In a reaction, 80.0 mL of 0.160 M HPro was reacted with 20.0 mL of 0.140 M NaOH. (Na* is a spectator ion and has been omitted.) HPro (aq) + OH-(aq) → H2O (1) + Pro- (aq) 6) Identify the limiting reagent, and find the concentrations of HPro, NaOH, and NaPro at the end of this "big change" reaction. (The LR concentration will be zero.) 7) Using your values of HPrO and NaPro in the answer to the previous problem, plug into the Ka equation to solve for the value of [H*]. 8) Calculate the pH of this final solution. 9) Write the dissociation reaction for the weak base LiPro (Pro'-) in water. 10) Write the mass action expression for this equation, which is equal to K. 11) Since Kw = Ka × Kb., solve for the mathematical value of Kb. 12) Calculate the following values for a 0.138 M Ca(Pro)2 solution: (a) the [OH] in a 0.138 M Ca(Pro)2 solution. (Use an "ICE" table) (b) the pH of a 0.138 M Ca(Pro)2 solution.
Transcribed Image Text:In a reaction, 80.0 mL of 0.160 M HPro was reacted with 20.0 mL of 0.140 M NaOH. (Na* is a spectator ion and has been omitted.) HPro (aq) + OH-(aq) → H2O (1) + Pro- (aq) 6) Identify the limiting reagent, and find the concentrations of HPro, NaOH, and NaPro at the end of this "big change" reaction. (The LR concentration will be zero.) 7) Using your values of HPrO and NaPro in the answer to the previous problem, plug into the Ka equation to solve for the value of [H*]. 8) Calculate the pH of this final solution. 9) Write the dissociation reaction for the weak base LiPro (Pro'-) in water. 10) Write the mass action expression for this equation, which is equal to K. 11) Since Kw = Ka × Kb., solve for the mathematical value of Kb. 12) Calculate the following values for a 0.138 M Ca(Pro)2 solution: (a) the [OH] in a 0.138 M Ca(Pro)2 solution. (Use an "ICE" table) (b) the pH of a 0.138 M Ca(Pro)2 solution.
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