Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Did I calculate the first atom economy correctly? Is H2SO4 the catalyst which would mean I would not include it in the denominator?
![### Understanding Atom Economy in Organic Synthesis
#### Reaction 1: Dehydration of 2-Methyl-2-butanol
**Equation:**
\[ \text{2-Methyl-2-butanol} \xrightarrow{\text{Heat, H}_2\text{SO}_4} \text{2-Methyl-1-butene} + \text{2-Methyl-2-butene} + \text{H}_2\text{O} \]
- **Molecular Weight of Reactants:**
- 2-Methyl-2-butanol: 88.15 g/mol
- **Molecular Weights of Products:**
- 2-Methyl-1-butene: 70.13 g/mol
**Atom Economy Calculation:**
\[
\text{Atom Economy} = \left(\frac{\text{Sum of Molecular Weight of Desired Products}}{\text{Sum of Molecular Weight of Reactants}}\right) \times 100
\]
\[
= \left(\frac{70.13 \, \text{g/mol}}{88.15 \, \text{g/mol}}\right) \times 100 = 79.5\%
\]
#### Reaction 2: Dehydrohalogenation of 2-Iodo-2-methylbutane
**Equation:**
\[ \text{2-Iodo-2-methylbutane} \xrightarrow{\text{Heat, KOtBu}} \text{2-Methyl-1-butene} + \text{2-Methyl-2-butene} \]
- **Molecular Weight of Reactant:**
- 2-Iodo-2-methylbutane: 198.05 g/mol
- **Molecular Weight of Additional Reagent:**
- KOtBu: 112.12 g/mol
- **Molecular Weight of Desired Product:**
- 2-Methyl-1-butene: 70.13 g/mol
**Atom Economy Calculation:**
\[
= \left(\frac{70.13 \, \text{g/mol}}{198.05 \, \text{g/mol} + 112.12 \, \text{g/mol}}\right) \times 100 = 22.6\%
\]
### Conclusion
The first reaction, dehydrating 2-Methyl-2-butanol, has a higher](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb0d56cf4-ae0c-4387-a2fc-13a29f1b7e32%2F6ac7ea0f-872d-4394-9729-8186b536f54f%2F1rdfqb9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Understanding Atom Economy in Organic Synthesis
#### Reaction 1: Dehydration of 2-Methyl-2-butanol
**Equation:**
\[ \text{2-Methyl-2-butanol} \xrightarrow{\text{Heat, H}_2\text{SO}_4} \text{2-Methyl-1-butene} + \text{2-Methyl-2-butene} + \text{H}_2\text{O} \]
- **Molecular Weight of Reactants:**
- 2-Methyl-2-butanol: 88.15 g/mol
- **Molecular Weights of Products:**
- 2-Methyl-1-butene: 70.13 g/mol
**Atom Economy Calculation:**
\[
\text{Atom Economy} = \left(\frac{\text{Sum of Molecular Weight of Desired Products}}{\text{Sum of Molecular Weight of Reactants}}\right) \times 100
\]
\[
= \left(\frac{70.13 \, \text{g/mol}}{88.15 \, \text{g/mol}}\right) \times 100 = 79.5\%
\]
#### Reaction 2: Dehydrohalogenation of 2-Iodo-2-methylbutane
**Equation:**
\[ \text{2-Iodo-2-methylbutane} \xrightarrow{\text{Heat, KOtBu}} \text{2-Methyl-1-butene} + \text{2-Methyl-2-butene} \]
- **Molecular Weight of Reactant:**
- 2-Iodo-2-methylbutane: 198.05 g/mol
- **Molecular Weight of Additional Reagent:**
- KOtBu: 112.12 g/mol
- **Molecular Weight of Desired Product:**
- 2-Methyl-1-butene: 70.13 g/mol
**Atom Economy Calculation:**
\[
= \left(\frac{70.13 \, \text{g/mol}}{198.05 \, \text{g/mol} + 112.12 \, \text{g/mol}}\right) \times 100 = 22.6\%
\]
### Conclusion
The first reaction, dehydrating 2-Methyl-2-butanol, has a higher
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