Did I calculate the first atom economy correctly? Is H2SO4 the catalyst which would mean I would not include it in the denominator?

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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Did I calculate the first atom economy correctly? Is H2SO4 the catalyst which would mean I would not include it in the denominator?

### Understanding Atom Economy in Organic Synthesis

#### Reaction 1: Dehydration of 2-Methyl-2-butanol

**Equation:**

\[ \text{2-Methyl-2-butanol} \xrightarrow{\text{Heat, H}_2\text{SO}_4} \text{2-Methyl-1-butene} + \text{2-Methyl-2-butene} + \text{H}_2\text{O} \]

- **Molecular Weight of Reactants:**  
  - 2-Methyl-2-butanol: 88.15 g/mol

- **Molecular Weights of Products:**  
  - 2-Methyl-1-butene: 70.13 g/mol

**Atom Economy Calculation:**

\[ 
\text{Atom Economy} = \left(\frac{\text{Sum of Molecular Weight of Desired Products}}{\text{Sum of Molecular Weight of Reactants}}\right) \times 100 
\]

\[ 
= \left(\frac{70.13 \, \text{g/mol}}{88.15 \, \text{g/mol}}\right) \times 100 = 79.5\%
\]

#### Reaction 2: Dehydrohalogenation of 2-Iodo-2-methylbutane

**Equation:**

\[ \text{2-Iodo-2-methylbutane} \xrightarrow{\text{Heat, KOtBu}} \text{2-Methyl-1-butene} + \text{2-Methyl-2-butene} \]

- **Molecular Weight of Reactant:**  
  - 2-Iodo-2-methylbutane: 198.05 g/mol

- **Molecular Weight of Additional Reagent:**  
  - KOtBu: 112.12 g/mol

- **Molecular Weight of Desired Product:**  
  - 2-Methyl-1-butene: 70.13 g/mol

**Atom Economy Calculation:**

\[
= \left(\frac{70.13 \, \text{g/mol}}{198.05 \, \text{g/mol} + 112.12 \, \text{g/mol}}\right) \times 100 = 22.6\%
\]

### Conclusion

The first reaction, dehydrating 2-Methyl-2-butanol, has a higher
Transcribed Image Text:### Understanding Atom Economy in Organic Synthesis #### Reaction 1: Dehydration of 2-Methyl-2-butanol **Equation:** \[ \text{2-Methyl-2-butanol} \xrightarrow{\text{Heat, H}_2\text{SO}_4} \text{2-Methyl-1-butene} + \text{2-Methyl-2-butene} + \text{H}_2\text{O} \] - **Molecular Weight of Reactants:** - 2-Methyl-2-butanol: 88.15 g/mol - **Molecular Weights of Products:** - 2-Methyl-1-butene: 70.13 g/mol **Atom Economy Calculation:** \[ \text{Atom Economy} = \left(\frac{\text{Sum of Molecular Weight of Desired Products}}{\text{Sum of Molecular Weight of Reactants}}\right) \times 100 \] \[ = \left(\frac{70.13 \, \text{g/mol}}{88.15 \, \text{g/mol}}\right) \times 100 = 79.5\% \] #### Reaction 2: Dehydrohalogenation of 2-Iodo-2-methylbutane **Equation:** \[ \text{2-Iodo-2-methylbutane} \xrightarrow{\text{Heat, KOtBu}} \text{2-Methyl-1-butene} + \text{2-Methyl-2-butene} \] - **Molecular Weight of Reactant:** - 2-Iodo-2-methylbutane: 198.05 g/mol - **Molecular Weight of Additional Reagent:** - KOtBu: 112.12 g/mol - **Molecular Weight of Desired Product:** - 2-Methyl-1-butene: 70.13 g/mol **Atom Economy Calculation:** \[ = \left(\frac{70.13 \, \text{g/mol}}{198.05 \, \text{g/mol} + 112.12 \, \text{g/mol}}\right) \times 100 = 22.6\% \] ### Conclusion The first reaction, dehydrating 2-Methyl-2-butanol, has a higher
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