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Ignment for Limiting Reactant 1. A student adds 25.27 mL of a 0.250 M Na;SO, solution to another solution containing 2.00 grams of BaClh solid (dissolved). Given the following unbalanced equation, what mass of precipitate (BasO,) should have been formed, based on the limiting reactant? BaCla (ag)

Ignment for Limiting Reactant 1. A student adds 25.27 mL of a 0.250 M Na;SO, solution to another solution containing 2.00 grams of BaClh solid (dissolved). Given the following unbalanced equation, what mass of precipitate (BasO,) should have been formed, based on the limiting reactant? BaCla (ag)

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120 CHM 1025L: Post-laboratory Assignment for Limiting Reactant 1. A student adds 25.27 ml. of a 0.250 M Na;SO4 solution to another solution containing 2.00 grams of BaCla solid (dissolved). Given the following unbalanced equation, what mass of precipitate (BaSO) should have been formed, based on the limiting reactant? BaCl2 (aq) + _Na2SO4 (aq) → _BaSO4 (s) + NACI (aq) v toll Daz soys s.27 hb n of Nazsoy weigho Baclz 2.so gm muve Nazsoy e 0.150 × 2s.2a 0.75 M -0.0184s hole Bacla : Bad > 2.5ogn Badz : 0.012o mores 6.0120 boT x Z33.30egibrot 2.80 gy 2. A student adds 250. mL of deionized water (H2O) to a sample containing 75.00 grams of sodium solid. Given the following unbalanced equation, what mass of sodium hydroxide should have been formed, based on the limiting reactant? Given: the density of water at room temperature is 0.998 g/mL. First, please balance the reaction. HINT: Since water is not a solution, molarity does not apply. Water is a pure liquid, and you’ll need to use the density to first convert volume to mass. _H2 (g) 2 Na (s) + 2 H2O (1) → 2 NAOH (aq) + Reacoion: z mol itzo muss Gf Na 125.0og aso omL 5.427 heレtax :s.437 moi Hzo Volume HzO : Density of HzO : 6.998 g mne Da- lim. Reac Quna :S.437 mal ५9.58) moles = 22.99$/mol.13.8s hol T8.02 g/mol mules at NaoH mm: 40.0gmol muss of Daot prouluced : 5.437 bnot x 4ougsaol :Cマ.5g pa円 Muss Ne - 12s.00g A lomic mus 3:22.49g Imul moles of Na = 2s.00g 6.437)nol
Transcribed Image Text:120 CHM 1025L: Post-laboratory Assignment for Limiting Reactant 1. A student adds 25.27 ml. of a 0.250 M Na;SO4 solution to another solution containing 2.00 grams of BaCla solid (dissolved). Given the following unbalanced equation, what mass of precipitate (BaSO) should have been formed, based on the limiting reactant? BaCl2 (aq) + _Na2SO4 (aq) → _BaSO4 (s) + NACI (aq) v toll Daz soys s.27 hb n of Nazsoy weigho Baclz 2.so gm muve Nazsoy e 0.150 × 2s.2a 0.75 M -0.0184s hole Bacla : Bad > 2.5ogn Badz : 0.012o mores 6.0120 boT x Z33.30egibrot 2.80 gy 2. A student adds 250. mL of deionized water (H2O) to a sample containing 75.00 grams of sodium solid. Given the following unbalanced equation, what mass of sodium hydroxide should have been formed, based on the limiting reactant? Given: the density of water at room temperature is 0.998 g/mL. First, please balance the reaction. HINT: Since water is not a solution, molarity does not apply. Water is a pure liquid, and you’ll need to use the density to first convert volume to mass. _H2 (g) 2 Na (s) + 2 H2O (1) → 2 NAOH (aq) + Reacoion: z mol itzo muss Gf Na 125.0og aso omL 5.427 heレtax :s.437 moi Hzo Volume HzO : Density of HzO : 6.998 g mne Da- lim. Reac Quna :S.437 mal ५9.58) moles = 22.99$/mol.13.8s hol T8.02 g/mol mules at NaoH mm: 40.0gmol muss of Daot prouluced : 5.437 bnot x 4ougsaol :Cマ.5g pa円 Muss Ne - 12s.00g A lomic mus 3:22.49g Imul moles of Na = 2s.00g 6.437)nol
119 TRIAL 2: Using either Option 1 or Option 2 in the sample calculations, determine both uhe theoretical yield of NaCl in your reaction for trial 2, and indicate which reactant (HCI or NazCO3) was the limiting reactant. Dae Cos Theoretical Yield of NaCl, Trial 2 Limiting Reactant for Trial 2 Considering the mass of residue you actually recovered in trial 2, what was the percent yield of this reaction? Percent Yield of NaCl (trial 2) Error Analysis - TRIAL 2 Comment briefly on why you think your percent yield was not 100%. If your percent yield was greater than 100%, what other substance(s) may have been present in the residue? If your percent yield was less than 100%, what may have happened to the NaCl product?
Transcribed Image Text:119 TRIAL 2: Using either Option 1 or Option 2 in the sample calculations, determine both uhe theoretical yield of NaCl in your reaction for trial 2, and indicate which reactant (HCI or NazCO3) was the limiting reactant. Dae Cos Theoretical Yield of NaCl, Trial 2 Limiting Reactant for Trial 2 Considering the mass of residue you actually recovered in trial 2, what was the percent yield of this reaction? Percent Yield of NaCl (trial 2) Error Analysis - TRIAL 2 Comment briefly on why you think your percent yield was not 100%. If your percent yield was greater than 100%, what other substance(s) may have been present in the residue? If your percent yield was less than 100%, what may have happened to the NaCl product?
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