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Pentaborane B5H9(s) burns vigorously in O2 to give B203(s) and H20(1). Calculate AHpxn for the combustion of 5.00 mol of B5HC AH*f[B203(s)] = -1,273.5 kJ/mol AH°f[B5H9(s)] =73.2 kJ/mol AH°f[H20(1)] =-285.8 kJ/mol

Pentaborane B5H9(s) burns vigorously in O2 to give B203(s) and H20(1). Calculate AHpxn for the combustion of 5.00 mol of B5HC AH*f[B203(s)] = -1,273.5 kJ/mol AH°f[B5H9(s)] =73.2 kJ/mol AH°f[H20(1)] =-285.8 kJ/mol

Chemistry: Principles and Practice
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 5.50QE
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-9,090 kJ 45,400 kJ - 8,790 kJ - 45,400 kJ - 22,700 kJ B.. Next
Transcribed Image Text:-9,090 kJ 45,400 kJ - 8,790 kJ - 45,400 kJ - 22,700 kJ B.. Next
Pentaborane B5H9(s) burns vigorously in 02 to give B203(s) and H20(1). Calculate AHpxn for the combustion of 5.00 mol of B5H9. AH°f[B203(s)] =-1,273.5 kJ/mol AH°f[B5H9(s)] =73.2 kJ/mol AH°f[H20(1)] = -285.8 kJ/mol Multiple Choice - 9,090 kJ 45,400 kJ - 8,790 kJ - 45,400 kJ
Transcribed Image Text:Pentaborane B5H9(s) burns vigorously in 02 to give B203(s) and H20(1). Calculate AHpxn for the combustion of 5.00 mol of B5H9. AH°f[B203(s)] =-1,273.5 kJ/mol AH°f[B5H9(s)] =73.2 kJ/mol AH°f[H20(1)] = -285.8 kJ/mol Multiple Choice - 9,090 kJ 45,400 kJ - 8,790 kJ - 45,400 kJ
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