CuBr. Cui63.5/223k100=28.4%omg Br: 19.9 *2-159.8/223.3x100 - 71.6%img Na OH Na: 25.0/40x (60-57.5% ng 0.16.0/40x160:40% mg Hil.0/40x100 :2.5% mg I4;1,0.8=8/68.1x100-11.77,4g 3:32.1/68.1x1G0 = 47.1% ng
CuBr. Cui63.5/223k100=28.4%omg Br: 19.9 *2-159.8/223.3x100 - 71.6%img Na OH Na: 25.0/40x (60-57.5% ng 0.16.0/40x160:40% mg Hil.0/40x100 :2.5% mg I4;1,0.8=8/68.1x100-11.77,4g 3:32.1/68.1x1G0 = 47.1% ng
Chemistry by OpenStax (2015-05-04)
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Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter11: Solutions And Colloids
Section: Chapter Questions
Problem 50E: A sample of an organic compound (a nonelectrolyte) weighing 1.35 g lowered the freezing point of...
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Question
![Balavei
TyAsoffecochions
Cu Br.
Cui 63.5/22381I00 -2R.4%mg
23a aBr: 19.9 *2-159.8/223.3xlo0 - 71.6%mg
2 Na OH
40alud Na: 25.0/40x100:57.5% mg
0.16.0/40x160:40% mg
Hi1.0/40x100:2.5%. mg
3 NH)S
(4:1,0.8=8/68lx(00-11.7%,ng
5:32.1/68.111I00:47.1% ng
4 No Sa
2.2gl4 N:14.0x2-28192.2 X1U : 30.4%i mg v
5:32.1x2=64.2142.2 x1C0 =69.6.1.ag
5K MA O4
58 lul Ki 39,1/158 x100-27.7%, mg
Mn:54,9/156x160=34.7%, my
0:16.0x4-64/158160-40.5 hmng
6HCI
SGal Hil.0/36.5x(60-2.7% mg
C1:35.5/36.5x100=97.3%. my
Mg (NO)2
Ma 24.3 /124K100-19.6lo
N:14.0x2-24/124x100=22.6%. mg
mg](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff7a3ca96-cb42-4200-9dbf-65bbd400c6a8%2Fc5c14109-c5f4-4193-b3a1-13658f9b60e8%2F2vgjv6c_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Balavei
TyAsoffecochions
Cu Br.
Cui 63.5/22381I00 -2R.4%mg
23a aBr: 19.9 *2-159.8/223.3xlo0 - 71.6%mg
2 Na OH
40alud Na: 25.0/40x100:57.5% mg
0.16.0/40x160:40% mg
Hi1.0/40x100:2.5%. mg
3 NH)S
(4:1,0.8=8/68lx(00-11.7%,ng
5:32.1/68.111I00:47.1% ng
4 No Sa
2.2gl4 N:14.0x2-28192.2 X1U : 30.4%i mg v
5:32.1x2=64.2142.2 x1C0 =69.6.1.ag
5K MA O4
58 lul Ki 39,1/158 x100-27.7%, mg
Mn:54,9/156x160=34.7%, my
0:16.0x4-64/158160-40.5 hmng
6HCI
SGal Hil.0/36.5x(60-2.7% mg
C1:35.5/36.5x100=97.3%. my
Mg (NO)2
Ma 24.3 /124K100-19.6lo
N:14.0x2-24/124x100=22.6%. mg
mg
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Note: As per our guidelines, we are supposed to answer only the first three questions (i.e. 1 to 3 ). Kindly repost other questions separately.
Standard data:
- The molar mass of CuBr2 = 223.3 g/mol
- The molar mass of NaOH = 40 g/mol
- The molar mass of (NH4)2S = 68.1 g/mol
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