Given that the reaction of C2H4 (g) + 3 O, (g) → 2 CO2 (g) + 2 H20 (1) AH = -1411 kJ What would AH be for 2 CO2 (g) + 2 H20 (1) → C,H4 (g) + 3 02 (g) O 1411 J O-1411 J -1411 kJ

Chemistry: The Molecular Science
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Chapter4: Energy And Chemical Reactions
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**Reaction Thermodynamics: Analyzing ΔH**

Given the reaction:

\[ \text{C}_2\text{H}_4 (g) + 3 \text{O}_2 (g) \rightarrow 2 \text{CO}_2 (g) + 2 \text{H}_2\text{O} (l) \]

This reaction has an enthalpy change (\( \Delta H \)) of \(-1411 \text{ kJ}\).

**Determine \(\Delta H\) for the reverse reaction:**

\[ 2 \text{CO}_2 (g) + 2 \text{H}_2\text{O} (l) \rightarrow \text{C}_2\text{H}_4 (g) + 3 \text{O}_2 (g) \]

**Options:**
- \(1411 \text{ J}\)
- \(-1411 \text{ J}\)
- \(-1411 \text{ kJ}\)
- \(1411 \text{ kJ}\)

**Explanation:**

The enthalpy change for the reverse reaction is the opposite of the forward reaction because the direction of the energy change is reversed.

Thus, \(\Delta H\) for the reverse reaction is \(1411 \text{ kJ}\).
Transcribed Image Text:**Reaction Thermodynamics: Analyzing ΔH** Given the reaction: \[ \text{C}_2\text{H}_4 (g) + 3 \text{O}_2 (g) \rightarrow 2 \text{CO}_2 (g) + 2 \text{H}_2\text{O} (l) \] This reaction has an enthalpy change (\( \Delta H \)) of \(-1411 \text{ kJ}\). **Determine \(\Delta H\) for the reverse reaction:** \[ 2 \text{CO}_2 (g) + 2 \text{H}_2\text{O} (l) \rightarrow \text{C}_2\text{H}_4 (g) + 3 \text{O}_2 (g) \] **Options:** - \(1411 \text{ J}\) - \(-1411 \text{ J}\) - \(-1411 \text{ kJ}\) - \(1411 \text{ kJ}\) **Explanation:** The enthalpy change for the reverse reaction is the opposite of the forward reaction because the direction of the energy change is reversed. Thus, \(\Delta H\) for the reverse reaction is \(1411 \text{ kJ}\).
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