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2. Set the two equations equal and isolate In Ksp on one side of the equals sign by dividing both sides by (-RT). AG=RTIn Ksp=AH-TAS/-RT AG= In KSR-AH-TAS/-RT| 3. Create a graph using Excel plotting In Ksp on the y-axis and 1/T (make sure the units for temperature are Kelvin) on the x-axis. I In KSP 0 0.0029 -0.5 -1 -1.5 -2 -2.5 -3 -3.5 -4 -4.5 -5 0.003 0.0031 0.0032 1/T 0.0033 0.0034 0.0035 y=-2738x+5.075 R² = 0.9845 0.0036 a. Use the value obtained for the slope of the graph to solve for AH° using the equation derived in Question 2.

2. Set the two equations equal and isolate In Ksp on one side of the equals sign by dividing both sides by (-RT). AG=RTIn Ksp=AH-TAS/-RT AG= In KSR-AH-TAS/-RT| 3. Create a graph using Excel plotting In Ksp on the y-axis and 1/T (make sure the units for temperature are Kelvin) on the x-axis. I In KSP 0 0.0029 -0.5 -1 -1.5 -2 -2.5 -3 -3.5 -4 -4.5 -5 0.003 0.0031 0.0032 1/T 0.0033 0.0034 0.0035 y=-2738x+5.075 R² = 0.9845 0.0036 a. Use the value obtained for the slope of the graph to solve for AH° using the equation derived in Question 2.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Equilibrium Thermodynamics Analysis** 2. Set the two equations equal and isolate ln Ksp on one side of the equals sign by dividing both sides by (-RT). \[ \Delta G = -RT \ln K_{sp} = \Delta H - T \Delta S / -RT \] \[ \Delta G = \ln K_{sp} = \Delta H - T \Delta S / -RT \] 3. Create a graph using Excel plotting ln Ksp on the y-axis and 1/T (make sure the units for temperature are Kelvin) on the x-axis. **Graph Explanation:** - The x-axis represents \(1/T\) with values ranging from approximately 0.0029 to 0.0036. - The y-axis represents ln Ksp, with values ranging from -5 to 0. - Data points are plotted showing a linear relationship. - The line of best fit is displayed with the equation: \( y = -2738x + 5.075 \). - The \( R^2 \) value is 0.9845, indicating a strong correlation between the variables. a. Use the value obtained for the slope of the graph to solve for \(\Delta H^\circ\) using the equation derived in Question 2.
Transcribed Image Text:**Equilibrium Thermodynamics Analysis** 2. Set the two equations equal and isolate ln Ksp on one side of the equals sign by dividing both sides by (-RT). \[ \Delta G = -RT \ln K_{sp} = \Delta H - T \Delta S / -RT \] \[ \Delta G = \ln K_{sp} = \Delta H - T \Delta S / -RT \] 3. Create a graph using Excel plotting ln Ksp on the y-axis and 1/T (make sure the units for temperature are Kelvin) on the x-axis. **Graph Explanation:** - The x-axis represents \(1/T\) with values ranging from approximately 0.0029 to 0.0036. - The y-axis represents ln Ksp, with values ranging from -5 to 0. - Data points are plotted showing a linear relationship. - The line of best fit is displayed with the equation: \( y = -2738x + 5.075 \). - The \( R^2 \) value is 0.9845, indicating a strong correlation between the variables. a. Use the value obtained for the slope of the graph to solve for \(\Delta H^\circ\) using the equation derived in Question 2.
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Step 1: Describing equation of straight line

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straight y equals mx plus straight c

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straight m equals slope space of space straight space line straight c equals straight y minus intercept

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