STARTING AMOUNT X What is the change in enthalpy in joules when 5.44 x 104 mol of AgCl solid dissolves in water according to the following chemical equation: AgCl(s) Ag (aq) + Cl(aq) AH = 65.5 KJ ADD FACTOR x( ) ANSWER RESET S
Thermochemistry
Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that occur as a result of reactions or chemical changes in a substance.
Exergonic Reaction
The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.
![**Title: Calculating the Change in Enthalpy**
**Context: Thermochemistry in Solution Reactions**
**Question 20 of 37**
**Problem Statement:**
Calculate the change in enthalpy in joules when 5.44 × 10⁻⁴ moles of AgCl solid dissolves in water according to the following chemical equation:
\[ \text{AgCl(s)} \rightarrow \text{Ag}^+(\text{aq}) + \text{Cl}^-(\text{aq}) \]
**Given Data:**
- ΔH = 65.5 kJ/mol (Enthalpy change)
**Solution Steps:**
1. **Identify the Known Values:**
- Moles of AgCl = 5.44 × 10⁻⁴ mol
- ΔH (for 1 mol) = 65.5 kJ/mol
2. **Apply the Formula:**
- Change in enthalpy (ΔH) for the reaction = Moles of AgCl × ΔH per mole
3. **Perform the Calculation:**
- First, convert ΔH from kJ to J: 65.5 kJ/mol = 65,500 J/mol
- Calculate the enthalpy change for 5.44 × 10⁻⁴ mol:
\[
\Delta H = 5.44 \times 10^{-4} \text{ mol} \times 65,500 \text{ J/mol} = \text{Result in Joules}
\]
**Interactive Diagram Explanation:**
- **Starting Amount:** A section where input for initial quantities is placed.
- **Multiplication Section:** To perform calculations using conversion factors.
- **Answer Section:** Where the computed change in enthalpy is displayed.
- **Additional Tools:**
- Add Factor: Simplifies calculations by pre-set values.
- Reset: Clears inputs for new calculations.
This exercise is aimed at enhancing understanding of energy changes during chemical reactions in solution, fostering proficiency in unit conversions and applying thermochemical principles.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F666339bd-14dd-4c40-813f-ce47e9ed2199%2F7c784a55-5248-47fc-9865-3f462b97d5f5%2Fvco6yzu_processed.png&w=3840&q=75)
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