Homework Help is Here – Start Your Trial Now!
Science
Chemistry
3. Calculate the standard enthalphy of acetylene (CH2) form its elements: CH2) 2C(graphite)+ H2() The equations for each step are as follows: C(graphite) + O2(8) H2e) + 2C2H+ 502(8) CO2() AH = -393.5 kJ AH=-285.8 kJ %3D %3D 2 4CO2+ 2HO) AH=-2598.8 kJ %3D 4. The standard enthalpy of formation of hexane can be determined indirectly. Calculate the standard enthalpy of formation of hexane using the enthalpies of combustion (in kJ/mol) given just below. 19 CH14(0) + 6CO) + 7H;Ou) AH = -4163.0 kJ -> 2 Ceruphite) + Oz(g) CO2(e) AH = -393.5 kJ > H2) +O2e) AH = -285.8 kJ ->

3. Calculate the standard enthalphy of acetylene (CH2) form its elements: CH2) 2C(graphite)+ H2() The equations for each step are as follows: C(graphite) + O2(8) H2e) + 2C2H+ 502(8) CO2() AH = -393.5 kJ AH=-285.8 kJ %3D %3D 2 4CO2+ 2HO) AH=-2598.8 kJ %3D 4. The standard enthalpy of formation of hexane can be determined indirectly. Calculate the standard enthalpy of formation of hexane using the enthalpies of combustion (in kJ/mol) given just below. 19 CH14(0) + 6CO) + 7H;Ou) AH = -4163.0 kJ -> 2 Ceruphite) + Oz(g) CO2(e) AH = -393.5 kJ > H2) +O2e) AH = -285.8 kJ ->

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
See similar textbooks
icon
Related questions
icon
Concept explainers
Question
100%
CH() + 202e) Ceraphite) +O2(g) CO2() 2H2+O2e) AH=-393.5 kJ AH--571.6 kJ AH=-890.4 kJ 2H2O) -> CO) + 2H;Ou) 3. Calculate the standard enthalphy of acetylene (C2H2) form its elements: C:H) 2C(graphite)+ +H2(s) The equations for each step are as follows: C(graphite) + O2(8) Hue) + Oe 2C2He + 5O2e) CO2(s) AH =-393.5 kJ AH=-285.8 kJ 2. 4CO2) + 2HOu) AH=-2598.8 kJ 4. The standard enthalpy of formation of hexane can be determined indirectly. Calculate the standard enthalpy of formation of hexane using the enthalpies of combustion (in kJ/mol) given just below. 19 AH=-4163.0 kJ CH140 6CO2) + 7H;Ou) + 2. AH =-393.5 kJ %3D CO2e) Ceraphite) + O2(g) H2ie +O2e) AH =-285.8 kJ H2Oay
Transcribed Image Text:CH() + 202e) Ceraphite) +O2(g) CO2() 2H2+O2e) AH=-393.5 kJ AH--571.6 kJ AH=-890.4 kJ 2H2O) -> CO) + 2H;Ou) 3. Calculate the standard enthalphy of acetylene (C2H2) form its elements: C:H) 2C(graphite)+ +H2(s) The equations for each step are as follows: C(graphite) + O2(8) Hue) + Oe 2C2He + 5O2e) CO2(s) AH =-393.5 kJ AH=-285.8 kJ 2. 4CO2) + 2HOu) AH=-2598.8 kJ 4. The standard enthalpy of formation of hexane can be determined indirectly. Calculate the standard enthalpy of formation of hexane using the enthalpies of combustion (in kJ/mol) given just below. 19 AH=-4163.0 kJ CH140 6CO2) + 7H;Ou) + 2. AH =-393.5 kJ %3D CO2e) Ceraphite) + O2(g) H2ie +O2e) AH =-285.8 kJ H2Oay
Date: Year & Section: Exercise 1: Problem Solving: Solve the following problems with complete solution 1. Carbon occurs in two forms: graphite and diamond. Given the equation: CO2(e) CO2(e) Calculate the AH for the conversion of graphite to diamond: AH=-393.5 kJ C(eraphite) + Ozig) C(diamond) + Ozg) %3D AH3-395.4 kJ -> C(graphite) C(diamond) 2. Calculate for the change in enthalpy of: C(eraphite) + 2H22) Given the following information: Cigraphite) + O2(e) 2HM) + O2(g) CHe) + 202e) CH(e) AH=-393.5 kJ CO2(e) 2H;O) AH=-571.6 kJ AH = -890.4 kJ CO2e) + 2H2Ou)
Transcribed Image Text:Date: Year & Section: Exercise 1: Problem Solving: Solve the following problems with complete solution 1. Carbon occurs in two forms: graphite and diamond. Given the equation: CO2(e) CO2(e) Calculate the AH for the conversion of graphite to diamond: AH=-393.5 kJ C(eraphite) + Ozig) C(diamond) + Ozg) %3D AH3-395.4 kJ -> C(graphite) C(diamond) 2. Calculate for the change in enthalpy of: C(eraphite) + 2H22) Given the following information: Cigraphite) + O2(e) 2HM) + O2(g) CHe) + 202e) CH(e) AH=-393.5 kJ CO2(e) 2H;O) AH=-571.6 kJ AH = -890.4 kJ CO2e) + 2H2Ou)
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer
Knowledge Booster
Thermochemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY
SEE MORE TEXTBOOKS