Using the following heat of combustions CH;OH(1) + 0,(g)CO(g) + 2H;O(1) 4,H° = -726.4 kJ mol- %3D C(graphite) + O,(g) CO(g) 4,H° = -393.5 kJ mol 4,H° = -285.8 kJ mol %3D (1)O°H (3°0 + (3)°H

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What is the enthalpy of ethanol in Kj/mol: C(graphite) + 2H2+ 1/2 O2 -> CH3OH
Using the following heat of combustions
CH;OH(1) + }0,(g)→CO-(g) + 2H,0(1)
C(graphite) + O,(g) →CO(g)
4,H° = -726.4 kJ mol
%3D
4H° = -393.5 kJ mol
4,H° = -285.8 kJ mol-
%3D
(1)O°H- (3F0 + (3)°H
Transcribed Image Text:Using the following heat of combustions CH;OH(1) + }0,(g)→CO-(g) + 2H,0(1) C(graphite) + O,(g) →CO(g) 4,H° = -726.4 kJ mol %3D 4H° = -393.5 kJ mol 4,H° = -285.8 kJ mol- %3D (1)O°H- (3F0 + (3)°H
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