Using only following ArxnH° values: kJ 4 NH3 (g) + 5 O2 (g) → 4 NO (g)+ 6 H2O (£) ArxnH° = -1170 mol kJ 2 NO (g) + O2 (g) → 2 NO2 (g) ArxnH° = -114- mol kJ 3 NO2 (g) + H2O (() → 2 HNO; (() + NO (g) ArxnH° = -72- mol Calculate Arxn H° for NH3 (g) + 2 O2 (g) → HNO3 (() + H2O (C) Calculate Arxn H° for the same reaction using A;H° values from the thermodynamic table

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Calculate enthalpy using the following reactions: 

 

7.
Using only following ArxnH° values:
kJ
4 NH3 (g) + 5 O2 (g) → 4 NO (g) + 6 H2O (l)
Arxn H° = -1170
mol
kJ
2 NO (g) + O2 (g) → 2 NO2 (g)
Arxn H° = -114-
mol
kJ
3 NO2 (g) + H2O (l) → 2 HNO; (() + NO (g)
Arxn H° = -72
mol
Calculate Arxn H° for NH3 (g) + 2 O2 (g) → HNO3 (() + H2O (C)
Calculate Arxn H° for the same reaction using A;H° values from the thermodynamic table
Transcribed Image Text:7. Using only following ArxnH° values: kJ 4 NH3 (g) + 5 O2 (g) → 4 NO (g) + 6 H2O (l) Arxn H° = -1170 mol kJ 2 NO (g) + O2 (g) → 2 NO2 (g) Arxn H° = -114- mol kJ 3 NO2 (g) + H2O (l) → 2 HNO; (() + NO (g) Arxn H° = -72 mol Calculate Arxn H° for NH3 (g) + 2 O2 (g) → HNO3 (() + H2O (C) Calculate Arxn H° for the same reaction using A;H° values from the thermodynamic table
Expert Solution
Step 1

Our desired equation is:

NH3(g) + 2O2(g)   ----> HNO3(l) + H2O(l)

We have to arrange the given equations in such a way that, we get "NH3(g) + 2O2(g)" on the reactant side and "HNO3(l) + H2O(l)" on the product side.

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