Calculate the change in enthalpy for the reaction below using the following data table. 2B5H9(1) + 1202(g) → 5B,03(s) + 9H20(1)

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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Calculate the change in enthalpy for the reaction below using the following data table.
2B5H9(1) + 1202(g) → 5B,03(s) + 9H20(1)
Substance
Heats of formation, AH;
B;H9 (1)
73.2
B,03 (s)
-1263.6
H20(1)
-285.8
a
- 8743 kj
8743 kj
- 9036.6 kj
d
9036.6 kj
e
NONE OF THE ABOVE
Transcribed Image Text:Calculate the change in enthalpy for the reaction below using the following data table. 2B5H9(1) + 1202(g) → 5B,03(s) + 9H20(1) Substance Heats of formation, AH; B;H9 (1) 73.2 B,03 (s) -1263.6 H20(1) -285.8 a - 8743 kj 8743 kj - 9036.6 kj d 9036.6 kj e NONE OF THE ABOVE
Using the heats of formation of hydrazine, N2H4(I) and ammonia, NH3(g). Calculate the enthalpy of decomposition of hydrazine. The
heat of formation, AH°¡ of N,H3(1) is 50.42 kJ/mol and NH3(g) is -46.3 kJ/mol.
3N2H4(1) → 4NH3(8) + N2(8)
a
336.46 kj
- 336.46 kj
-33.94 kj
33.94 kj
e
- 96.72
Transcribed Image Text:Using the heats of formation of hydrazine, N2H4(I) and ammonia, NH3(g). Calculate the enthalpy of decomposition of hydrazine. The heat of formation, AH°¡ of N,H3(1) is 50.42 kJ/mol and NH3(g) is -46.3 kJ/mol. 3N2H4(1) → 4NH3(8) + N2(8) a 336.46 kj - 336.46 kj -33.94 kj 33.94 kj e - 96.72
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