6. From the following heats of combustion,AH° = -3119.6 kJ/mol kJ/molCH3OH(1) + 1/2O2(g) → CO2(g) + 2H2O(I)C(graphite) + 0,(g) → co,(g)H2 (g) + 1/202(g) → H2O1)AH:° = -393.5 kJ/molAH.º= -285.8 kJ/molCalculate the enthalpy of formation of methanol from its elements:C(graphite) + 2H,(g) + 1/2O2(g) → CH;OH (g)

Answered: Image /qna-images/answer/2f4d0d6a-87d6-4b5f-afaa-a2617b44e386.jpg

From the following heats of combustion, AH:° = -3119.6 kJ/mol kJ/mol AH:° = -393.5 kJ/mol AH:º= -285.8 kJ/mol CH3OH(1) + 1/2O2(g) → CO2(g) + 2H2O{1) C(graphite) + 0,(g) → Co,(g) H2 (g) + 1/202(g) → H2O1) culate the enthalpy of formation of methanol from its elements: C(graphite) + 2H,(9) + 1/2O2(g) → CH,OH (g)

From the following heats of combustion, AH:° = -3119.6 kJ/mol kJ/mol AH:° = -393.5 kJ/mol AH:º= -285.8 kJ/mol CH3OH(1) + 1/2O2(g) → CO2(g) + 2H2O{1) C(graphite) + 0,(g) → Co,(g) H2 (g) + 1/202(g) → H2O1) culate the enthalpy of formation of methanol from its elements: C(graphite) + 2H,(9) + 1/2O2(g) → CH,OH (g)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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