Calculate the heat (in kJ) associated with the cooling of 303 g of mercury from 86.8°C to 12.0°C.kJ From the following heats of combustion,3CH3OH(1) +02(g) → CO:(g) + 2H,0(1)AH =-726.4 kJ/molrxnC(graphite) + O2(g) → CO,(g)AH=-393.5 kJ/molrxn1H2(g) +02(g) → H2O(1)AH° =-285.8 kJ/molrxnCalculate the enthalpy of formation of methanol (CH3OH) from its elements:C(graphite) + 2H,(E) + 02(g) → CH3OH(1)kJ/mol

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From the following heats of combustion, CH3OH(1) + 02(g) → CO;(g) + 2H,O(1) AH =-726.4 kJ/mol rxn C(graphite) + O2(g) → CO:(g) AH =-393.5 kJ/mol rxn H;(g) + 0;g) → H,0(1) AH° =-285.8 kJ/mol rxn Calculate the enthalpy of formation of methanol (CH3OH) from its elements: C(graphite) + 2H¿(g) +;02g) → CH3OH(O kJ/mol

From the following heats of combustion, CH3OH(1) + 02(g) → CO;(g) + 2H,O(1) AH =-726.4 kJ/mol rxn C(graphite) + O2(g) → CO:(g) AH =-393.5 kJ/mol rxn H;(g) + 0;g) → H,0(1) AH° =-285.8 kJ/mol rxn Calculate the enthalpy of formation of methanol (CH3OH) from its elements: C(graphite) + 2H¿(g) +;02g) → CH3OH(O kJ/mol

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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