Consider the dissolution reactions below for the simple salts NaCl (s). AgCl (s), and CaCl2 (s). The AG values for the formation of their aqueous ions is also given. (i) (iii) (iv) NaCl Na (aq) + Cl(aq) AG = -9.1 kJ mol¹ AgCl Ag (aq) + Cl(aq) AG = +55.6 kJ mol-¹ CaCl2 Ca²+ (aq) + 2Cl(aq) AG = -67.98 kJ mol-¹ Given the AG values, roughly sketch the Gibbs function vs the extent of the reaction for each of the dissolution reactions. Calculate the Keq for the respective salts at 298 K. Explain your answer using the Ke obtained. When NaCl is dissolved in water. The temperature of the solution goes down. The opposite is seen when dissolving CaCl2 in water. The temperature of the solution increases. Fully explain why this happens. How will the AG of the dissolution of the salts change with increasing temperature?
Consider the dissolution reactions below for the simple salts NaCl (s). AgCl (s), and CaCl2 (s). The AG values for the formation of their aqueous ions is also given. (i) (iii) (iv) NaCl Na (aq) + Cl(aq) AG = -9.1 kJ mol¹ AgCl Ag (aq) + Cl(aq) AG = +55.6 kJ mol-¹ CaCl2 Ca²+ (aq) + 2Cl(aq) AG = -67.98 kJ mol-¹ Given the AG values, roughly sketch the Gibbs function vs the extent of the reaction for each of the dissolution reactions. Calculate the Keq for the respective salts at 298 K. Explain your answer using the Ke obtained. When NaCl is dissolved in water. The temperature of the solution goes down. The opposite is seen when dissolving CaCl2 in water. The temperature of the solution increases. Fully explain why this happens. How will the AG of the dissolution of the salts change with increasing temperature?
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Transcribed Image Text:Consider the dissolution reactions below for the simple salts NaCl (s), AgCl (s), and
CaCl2 (s). The AG values for the formation of their aqueous ions is also given.
(i)
(iv)
NaCl = Na (aq) + Cl(aq)
AG = -9.1 kJ mol ¹
AgCl = Ag*(aq) + Cl(aq)
AG = +55.6 kJ mol-¹
CaCl2 = Ca²+ (aq) + 2Cl(aq) AG = -67.98 kJ mol-¹
Given the AG values, roughly sketch the Gibbs function vs the extent of
the reaction for each of the dissolution reactions.
Calculate the Keq for the respective salts at 298 K. Explain your answer
using the Ke obtained.
When NaCl is dissolved in water. The temperature of the solution goes
down. The opposite is seen when dissolving CaCl2 in water. The
temperature of the solution increases. Fully explain why this happens.
How will the AG of the dissolution of the salts change with increasing
temperature?
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