7-Given the following data for graphite and diamond at 298K. S°(diamond) = 0.58 cal/mole deg %3D S'(graphite) = 1.37 cal/mole deg AHP CO2(from graphite) = -94.48 kilocalories/mole AHƒ CO2(from diamond) = -94.03 kilocalories/mole Consider the change: C(graphite) = C(diamond) at 298K and 1 atmosphere. (a) What are the values of AS° and AH° for the conversion of graphite to diamond. (b) Perform a calculation to show whether it is thermodynamically feasible to produce diamond from graphite at 298K and 1 atmosphere. (c) For the reaction, calculate the equilibrium constant Keq at 298K
7-Given the following data for graphite and diamond at 298K. S°(diamond) = 0.58 cal/mole deg %3D S'(graphite) = 1.37 cal/mole deg AHP CO2(from graphite) = -94.48 kilocalories/mole AHƒ CO2(from diamond) = -94.03 kilocalories/mole Consider the change: C(graphite) = C(diamond) at 298K and 1 atmosphere. (a) What are the values of AS° and AH° for the conversion of graphite to diamond. (b) Perform a calculation to show whether it is thermodynamically feasible to produce diamond from graphite at 298K and 1 atmosphere. (c) For the reaction, calculate the equilibrium constant Keq at 298K
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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part b and c
Transcribed Image Text:7-Given the following data for graphite and diamond at 298K.
S°(diamond) = 0.58 cal/mole deg
S°(graphite) = 1.37 cal/mole deg
AHƒ CO2(from graphite) = -94.48 kilocalories/mole
%3D
AH? CO2(from diamond) = -94.03 kilocalories/mole
Consider the change: C(graphite) = C(diamond) at 298K and 1 atmosphere.
(a) What are the values of AS° and AH® for the conversion of graphite to diamond.
(b) Perform a calculation to show whether it is thermodynamically feasible to produce
diamond from graphite at 298K and 1 atmosphere.
(c) For the reaction, calculate the equilibrium constant Keq at 298K
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