None Please provide formulas for each of the Question inthe variants. These are from Life Insurance and LifeAnnuitiesa) 21.84.7933.8b) A and A44c) ä757d) 734e) ä (2)57:1544

The formulas you provided are a mix of calculations and data points:a) 21.8 / 4.79 This is a simple…

Answered: Please provide formulas for each of the…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Use and modify some/all the reactions provided to form the indicated overall reaction according to Hess' Law. • If a reaction is not used in your Hess' Law process, include that indication by multiplying the reaction by "0" • If no modification is needed and the reaction is applied as written below, include that indication by multiplying the reaction by "1" • Use whole numbers and simple fractions (such as "2" or "1/2", not 0.5) and negative signs (such as "-2") where needed Then calculate and report the enthalpy change (in kJ) for the overall reaction in the indicated blank, including units with your written value and rounded to 1 decimal place. Overall Reaction: CS2(1) + 302(g) → CO2(g) + 2SO2(g) Rxn # Reaction ΔΗ° (kJ) 1 C(s) → C(g) 716.67 2 C(s) + O2(g) → CO2(g) -393.5 3 3Fe(s) +202(g) → Fe3O4(s) -1118 4 C(s) + 2S(s) → CS2(1) 87.9 5 CH4(g) + O2(g) → CO₂(g) + H₂O(g) -882.0 6 S(s) + O2(g) → SO2(g) -296.8 N2(g) + 4H2(g) + Cl2(g) → 2NH4Cl(g) -629.1 7
With the information provided answer C
stru Wh
Is there a reason those sig figs are wrong or are my calculations just completely off?
Calculate (triangle)G for: C2H4 (g) + H2O (g) -> C2H5OH(g)
Which of the following gases consist of molecules containing four or more atoms? Rn O NO O CO Ar Kr CO2 Хе H,S HF H, F, N, sO, Ne HCN Cl, NO, CH, Не Sa HCI MacBook Pro
Rb₂O(s) +____H₂O(1)→ Co2(CO3)3(s) + heat → 3_H₂O(1) + 1_As2O5(s) →➜ NaClO3(s) + heat → (110q000 sd, opt! 2 H3 As 0, 4 Ini Siyoda canl Mg(s) + H₂SO4(aq) → Myson noileupo unor ton boonstad to out + H₂ Om adami zogasdo ne
Please don't providehandwritten solution ....
ORT SHEET Heat of Neutralization EXPERIMENT elemsboomfchg lom 12 A. Heat Capacity of Calorimeter 1. Temp. of calorimeter and water before mixing 2. Temp. of warm water °C 22.0 39,0 30.3 3. Maximum temp. determined from your curve °C 4. Heat lost by warm water (temp decrease x °C 50.0 g x 4.184 J/K-g) = 02), 5. Heat gained by cooler water (temp. increase x 50.0 g x 4.184 J/K-g) = 30,3 22.0)x 13626J s0.0gmpi S0.0gy 6. Heat gained by the calorimeter [(4) – (5)] = 7. Heat capacity of calorimeter: heat gained by the calorimeter temperature increase J/K 3. Heat of Neutralization of HCl-NaOH 22.2 22.2. °C . Temp. of calorimeter and NaOH Temp. of HCI AT determined from your curve after adding HC1 °C to the NaOH Heat gained by solution (temperature increase x ON 100 g x 4.184 J/K-g) = 9977.8J %3D Heat gained by calorimeter (temperature increase x heat capacity of calorimeter) = J %3D Total joules released by reaction [(3) + (4)] = Tight O 2018 Pearson Education, Inc.
Is 10b more than one product? Not sure the way it is written.
[References] Given the following data СэНа (9) + 302(9) — 2 СО2(9) + 2Н,0() 2C2 H6 (g) + 702(9) → 4 CO2(g) + 6H2O(1) 2H2 (g) + O2 (g) → 2H2 O(1) ΔΗ -1411.0 kJ AH = -3119.8 kJ AH=-571.7 kJ calculate A H for the reaction C2H4 (9) + H2 (g) → C2H6 (9) ΔΗΞ kJ Submit Answer Try Another Version 3 item attempts remaining
▼ Part B 2NO3(aq) +8H(aq) + 6e 3Fe(s) + 2NO3 (aq) +8H+ (aq) 3Fe(s)→→3Fe²+ (aq) + 6e →>> 2NO(g) + 4H₂0 (1) →3Fe²+ (aq) + 2NO(g) + 4H₂O(1) IVE ΑΣΦ Calculate El using the tabulated standard electrode potentials at 25 °C. cell Express your answer in volts to three significant figures. Eeell= 1.21 SWE Submit Previous Answers Request Answer 2+ X Incorrect; Try Again; 4 attempts remaining ? V stontiol buoubtrooting the electro na

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Please provide formulas for each of the Question in the variants. These are from Life Insurance and Life Annuities a) 21.84.7933.8 b) A and A 44 c) ä757 d) 734 e) ä (2) 57:15 44