СоНа (9) + 302(9) —> 2 СО2(9) + 2H20(1) 2С2H6 (9) + 702(э) — 4 СО2(9) + 6H20() 2H (9) + О2(9) 2H20() ДН%3 —1411.0 kJ ΔΗ=-3119.8 kJ %3D ΔΗ=-571.7 kJ calculate A H for the reaction C2H4 (9) + H2 (9) → C2H6 (g) ΔΗ kJ

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[References]
Given the following data
СэНа (9) + 302(9) — 2 СО2(9) + 2Н,0()
2C2 H6 (g) + 702(9) → 4 CO2(g) + 6H2O(1)
2H2 (g) + O2 (g) → 2H2 O(1)
ΔΗ -1411.0 kJ
AH = -3119.8 kJ
AH=-571.7 kJ
calculate A H for the reaction
C2H4 (9) + H2 (g) → C2H6 (9)
ΔΗΞ
kJ
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Transcribed Image Text:[References] Given the following data СэНа (9) + 302(9) — 2 СО2(9) + 2Н,0() 2C2 H6 (g) + 702(9) → 4 CO2(g) + 6H2O(1) 2H2 (g) + O2 (g) → 2H2 O(1) ΔΗ -1411.0 kJ AH = -3119.8 kJ AH=-571.7 kJ calculate A H for the reaction C2H4 (9) + H2 (g) → C2H6 (9) ΔΗΞ kJ Submit Answer Try Another Version 3 item attempts remaining
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∆H is calculated for various reactions is to determine whether the reaction is exothermic (loses energy and gives off heat) or endothermic (gains energy and absorbs heat).

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