d) An additional 12 hours of time available for the second machine, at no cost to the firm, are going to increase the objective value by response to two decimal places). dollars (round your Maximize contribution = 4x₁ + 4x2 +7x3 1X₁ +7X2 +4X3 ≤ 80 2X1 + 1X2 +7X3 ≤ 84 8X1 + 4X2 + 1X3 ≤ 80 X1, X2, X3 ≥0 (C₁: hours on machine 1) (C2: hours on machine 2) (C3: hours on machine 3) a) Using a computer software for solving LP, the optimal solution achieved is: ✗₁ = 6.25 (round your response to two decimal places). X25.11 (round your response to two decimal places). X3 9.48 (round your response to two decimal places). Contribution (objective value) = 111.86 (round your response to two decimal places). b) Machine 1 has 0 hours of unused time available at the optimal solution (round your response to two decimal places). Machine 2 has 0 hours of unused time available at the optimal solution (round your response to two decimal places). Machine 3 has 0 hours of unused time available at the optimal solution (round your response to two decimal places). c) An additional hour of time available for third machine, is worth 0.26 dollars to the firm (round your response to two decimal places).
d) An additional 12 hours of time available for the second machine, at no cost to the firm, are going to increase the objective value by response to two decimal places). dollars (round your Maximize contribution = 4x₁ + 4x2 +7x3 1X₁ +7X2 +4X3 ≤ 80 2X1 + 1X2 +7X3 ≤ 84 8X1 + 4X2 + 1X3 ≤ 80 X1, X2, X3 ≥0 (C₁: hours on machine 1) (C2: hours on machine 2) (C3: hours on machine 3) a) Using a computer software for solving LP, the optimal solution achieved is: ✗₁ = 6.25 (round your response to two decimal places). X25.11 (round your response to two decimal places). X3 9.48 (round your response to two decimal places). Contribution (objective value) = 111.86 (round your response to two decimal places). b) Machine 1 has 0 hours of unused time available at the optimal solution (round your response to two decimal places). Machine 2 has 0 hours of unused time available at the optimal solution (round your response to two decimal places). Machine 3 has 0 hours of unused time available at the optimal solution (round your response to two decimal places). c) An additional hour of time available for third machine, is worth 0.26 dollars to the firm (round your response to two decimal places).
Practical Management Science
6th Edition
ISBN:9781337406659
Author:WINSTON, Wayne L.
Publisher:WINSTON, Wayne L.
Chapter12: Queueing Models
Section12.3: The Exponential Distribution
Problem 3P
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
Transcribed Image Text:d) An additional 12 hours of time available for the second machine, at no cost to the firm, are going to increase the objective value by
response to two decimal places).
dollars (round your

Transcribed Image Text:Maximize contribution =
4x₁ + 4x2 +7x3
1X₁ +7X2 +4X3 ≤ 80
2X1 + 1X2 +7X3 ≤ 84
8X1 + 4X2 + 1X3 ≤ 80
X1, X2, X3 ≥0
(C₁: hours on machine 1)
(C2: hours on machine 2)
(C3: hours on machine 3)
a) Using a computer software for solving LP, the optimal solution achieved is:
✗₁
= 6.25 (round your response to two decimal places).
X25.11 (round your response to two decimal places).
X3 9.48 (round your response to two decimal places).
Contribution (objective value) = 111.86 (round your response to two decimal places).
b) Machine 1 has 0 hours of unused time available at the optimal solution (round your response to two decimal places).
Machine 2 has 0 hours of unused time available at the optimal solution (round your response to two decimal places).
Machine 3 has 0 hours of unused time available at the optimal solution (round your response to two decimal places).
c) An additional hour of time available for third machine, is worth 0.26 dollars to the firm (round your response to two decimal places).
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