Listeria, like all bacteria, emit small molecules as waste products or for signaling. Here we will consider a "race" between a Listeria bacterium (about 1 um across) and a chemical signal it emits while inside a much larger (~ 15 µm) mammalian cell. Suppose the Listeria bacterium, when at one end of the mammalian cell, emits a pulse of signaling molecules which begin diffusing through the mammalian cell. The Listeria then moves along a straight line from one end of the mammalian cell to the other. a. Write down the equation for the rms distance, assuming the diffusion is three-dimensional. Explain in words what the rms distance means (that is, what it tells us about a diffusion process).

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**Understanding Bacterial Movement and Diffusion in a Mammalian Cell**

**Introduction:**

Listeria, like all bacteria, emit small molecules as waste products or for signaling. This example considers a "race" between a Listeria bacterium (about 1 μm across) and a chemical signal it emits while inside a much larger (~15 μm) mammalian cell. Suppose the Listeria bacterium, when at one end of the mammalian cell, emits a pulse of signaling molecules which then begin diffusing through the mammalian cell. The Listeria then moves in a straight line from one end of the mammalian cell to the other.
 
**Problem and Parameters:**

1. **Equation for rms distance in three dimensions:**
    - **Explanation:** The root mean square (rms) distance is a statistical measure of the average distance a particle will travel due to diffusion over a given time period in three-dimensional space. It is given by the formula:
      \[
      \text{rms distance} = \sqrt{6Dt}
      \]
      where \(D\) is the diffusion constant and \(t\) is time. The rms distance tells us how far on average a diffusing particle will travel from its origin. It provides insight into the efficiency and speed of the diffusion process.

2. **Calculation for signal molecules' diffusion time:**
    - **Given:** 
      - **Diffusion constant (D):** 200 μm\(^2\)/s
      - **Distance to travel:** 15 μm (diameter of the mammalian cell)

    - **Calculation:**
      Rearrange the equation for rms distance to solve for time (\(t\)):
      \[
      t = \frac{(\text{rms distance})^2}{6D} = \frac{(15 \, \mu m)^2}{6 \, \times \, 200 \, \mu m^2/s} = \frac{225 \, \mu m^2}{1200 \, \mu m^2/s} = \frac{225}{1200} \text{s} \approx 0.1875 \text{s}
      \]
    - **Conclusion:** It takes approximately 0.1875 seconds for the signaling molecules to diffuse across the mammalian cell.

**Graphical Representation:**

On the right, there is an image of a mamm
Transcribed Image Text:**Understanding Bacterial Movement and Diffusion in a Mammalian Cell** **Introduction:** Listeria, like all bacteria, emit small molecules as waste products or for signaling. This example considers a "race" between a Listeria bacterium (about 1 μm across) and a chemical signal it emits while inside a much larger (~15 μm) mammalian cell. Suppose the Listeria bacterium, when at one end of the mammalian cell, emits a pulse of signaling molecules which then begin diffusing through the mammalian cell. The Listeria then moves in a straight line from one end of the mammalian cell to the other. **Problem and Parameters:** 1. **Equation for rms distance in three dimensions:** - **Explanation:** The root mean square (rms) distance is a statistical measure of the average distance a particle will travel due to diffusion over a given time period in three-dimensional space. It is given by the formula: \[ \text{rms distance} = \sqrt{6Dt} \] where \(D\) is the diffusion constant and \(t\) is time. The rms distance tells us how far on average a diffusing particle will travel from its origin. It provides insight into the efficiency and speed of the diffusion process. 2. **Calculation for signal molecules' diffusion time:** - **Given:** - **Diffusion constant (D):** 200 μm\(^2\)/s - **Distance to travel:** 15 μm (diameter of the mammalian cell) - **Calculation:** Rearrange the equation for rms distance to solve for time (\(t\)): \[ t = \frac{(\text{rms distance})^2}{6D} = \frac{(15 \, \mu m)^2}{6 \, \times \, 200 \, \mu m^2/s} = \frac{225 \, \mu m^2}{1200 \, \mu m^2/s} = \frac{225}{1200} \text{s} \approx 0.1875 \text{s} \] - **Conclusion:** It takes approximately 0.1875 seconds for the signaling molecules to diffuse across the mammalian cell. **Graphical Representation:** On the right, there is an image of a mamm
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