Are these answers correct? It's all for one problem where the E. coli chromosome contains 4,641,652 bp. In the replication of the E. coli chromosome, about how many Okazaki fragments would be formed? Assume the averageOkazaki fragment is 1,500 nucleotides long.number of Okazaki fragments: 3094What factors are required to link together newly synthesized Okazaki fragments in the lagging strand?DNA ligaseDnaG proteinDNA polymerase ISingle-stranded DNA-binding protein (SSB)DNA polymerase III O Macmillan LearningThe E. coli chromosome contains 4,641,652 bp.How many turns of the double helix must be unwound during replication of the E. coli chromosome?number of turns: 4.42 x105How long would it take (in minutes) to replicate the E. coli chromosome at 37 °C if two replication forks proceeded from theorigin? Assume replication occurs at a rate of 1,000 bp/s.replication time: 39Under some conditions E. coli cells can divide every 20 min. How might this be possible?A new round of replication begins before the previous one is completed.The chromosome has two origins, each proceeding bidirectionally to yield four replication forks.E. coli cells use multiple types of DNA polymerases to replicate the chromosome.E. coli cells do not replicate their genome before dividing.min

Prokaryotes have evolved to contain simple genomes. Thus, they are more efficient in replicating…

In the replication of the E. coli chromosome, about how many Okazaki fragments would be formed? Assume the average Okazaki fragment is 1,500 nucleotides long. number of Okazaki fragments: 3094 What factors are required to link together newly synthesized Okazaki fragments in the lagging strand? DNA ligase DnaG protein DNA polymerase I Single-stranded DNA-binding protein (SSB) DNA polymerase III

In the replication of the E. coli chromosome, about how many Okazaki fragments would be formed? Assume the average Okazaki fragment is 1,500 nucleotides long. number of Okazaki fragments: 3094 What factors are required to link together newly synthesized Okazaki fragments in the lagging strand? DNA ligase DnaG protein DNA polymerase I Single-stranded DNA-binding protein (SSB) DNA polymerase III

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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Similar questions

Compare the melting temperature of a 1-kb segment of DNA containing20% A residues to that of a 1-kb segment containing 30% A residues under the same conditions.
b) Among the progeny from the Hfr3 mating above, you find one that has the genotype: Abc de F Draw out the gene transfer and crossover(s) that produced this outcome: c) Among the progeny from the Hfr3 mating above, you find one that has the genotype: A B c d e f Draw out the gene transfer and crossover(s) that produced this outcome:
This shows where EcoR1 cuts, where HindIII cuts, and where BstEII cuts. Given that the entire chromosome is 48,502 base pairs (as it says), figure out the fragment sizes you will expect if you cut it with EcoR1, or with HindIII, or with BseEII. Draw a map like the example attached " Show the sizes of each piece. Color code it according to which enzyme cut it.
Are the following base sequences sticky or not sticky? Each piece is written 5′ to 3′.(a) TTAGC and GCTAA(b) CGTACG and CCTTCG
Second, Question 2
A molecule of composition5′-AAAAAAAAAAA-3′3′-TTTTTTTTTTTTT-5′is replicated in a solution containing unlabeled (notradioactive) GTP, CTP, and TTP plus adenine nucleoside triphosphate with all its phosphorus atoms in theform of the radioactive isotope 32P. Will both daughtermolecules be radioactive? Explain. Then repeat thequestion for the molecule5′-ATATATATATATAT-3′3′-TATATATATATATA-5′
Assuming that 145 base pairs of DNA wrap around the histone octamer 1.75 times, estimate the radius of the histone octamer. Assume 3.4 Å per base pair and simplify the calculation by assuming that the wrapping is in two rather than three dimensions and neglecting the thickness of the DNA.
Question 4. Given the probability that a restriction enzyme will cut DNA if the recognition sequence for the enzyme is 5'-GGATCC-3' and the GC content is 60%, c) Which of the following will lead to DNA cutting more frequently? Choose all that apply. O Increasing the AT content to 60% O Using a seven base cutter with the sequence 5'-GGATCCC-3' O Using a five base cutter with the sequence 5'-GGACC-3' O Increasing the GC content to 70% O Decreasing the GC content to 50%
Compute the PERCENT IDENTITY for the following pairwise sequence alignment. ACTGATGGGGG--AGACGTA ||||| ... I ||||||| ACTG--AAAAGCTAGACGTA
A plot showing the % of denautration as a function of temperature for a melting point of a DNA sample under 0.12 M NaCl gives an equation of a line of Y= 0.0074 X - 0.044 (Where Y is the % of denautration and X is the temperature in degree C) This is all the information that was given. 1. Calcuate the melting point of this DNA in degree C
In your own words, explain why 5’-CG-3’ dinucleotides are much rarer than we expect them to be in our genome.