In the replication of the E. coli chromosome, about how many Okazaki fragments would be formed? Assume the average Okazaki fragment is 1,500 nucleotides long. number of Okazaki fragments: 3094 What factors are required to link together newly synthesized Okazaki fragments in the lagging strand? DNA ligase DnaG protein DNA polymerase I Single-stranded DNA-binding protein (SSB) DNA polymerase III
In the replication of the E. coli chromosome, about how many Okazaki fragments would be formed? Assume the average Okazaki fragment is 1,500 nucleotides long. number of Okazaki fragments: 3094 What factors are required to link together newly synthesized Okazaki fragments in the lagging strand? DNA ligase DnaG protein DNA polymerase I Single-stranded DNA-binding protein (SSB) DNA polymerase III
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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Are these answers correct? It's all for one problem where the E. coli chromosome contains 4,641,652 bp.

Transcribed Image Text:In the replication of the E. coli chromosome, about how many Okazaki fragments would be formed? Assume the average
Okazaki fragment is 1,500 nucleotides long.
number of Okazaki fragments: 3094
What factors are required to link together newly synthesized Okazaki fragments in the lagging strand?
DNA ligase
DnaG protein
DNA polymerase I
Single-stranded DNA-binding protein (SSB)
DNA polymerase III

Transcribed Image Text:O Macmillan Learning
The E. coli chromosome contains 4,641,652 bp.
How many turns of the double helix must be unwound during replication of the E. coli chromosome?
number of turns: 4.42 x105
How long would it take (in minutes) to replicate the E. coli chromosome at 37 °C if two replication forks proceeded from the
origin? Assume replication occurs at a rate of 1,000 bp/s.
replication time: 39
Under some conditions E. coli cells can divide every 20 min. How might this be possible?
A new round of replication begins before the previous one is completed.
The chromosome has two origins, each proceeding bidirectionally to yield four replication forks.
E. coli cells use multiple types of DNA polymerases to replicate the chromosome.
E. coli cells do not replicate their genome before dividing.
min
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Step 1: DNA Replication in prokaryotes
VIEWStep 2: A) number of okazaki fragments
VIEWStep 3: B) linking Okazaki fragments
VIEWStep 4: C) number of turns to unwind in E coli chromosome
VIEWStep 5: D) time taken to replicate entire E coli chromosome
VIEWStep 6: E) How E coli completes replication in 20 mins
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