In Figure 8-15, what do you think would be the effect of a A to G mutation in the branch point residue of the intron? (Two answers.) The U5 snRNP would bind to the A that is now the first residue of the intron, and splicing would proceed normally. The U1 snRNP would be unable to bind to the intron, which would prevent intron splicing from occurring. The U1 snRNP would might find a nearby GU and use that for splicing, which would allow splicing to occur but would have consequences on translation. The U2 snRNP would be unable to bind to the branch point, which would prevent intron splicing from occurring. The U2 snRNP might find another nearby A and use that for the branch point, which might allow normal intron splicing. The hydroxyl from the branch point A would be unable to complete its transesterification reaction, and intron splicing would come to a halt.

Human Heredity: Principles and Issues (MindTap Course List)
11th Edition
ISBN:9781305251052
Author:Michael Cummings
Publisher:Michael Cummings
Chapter9: Gene Expression And Gene Regulation
Section: Chapter Questions
Problem 16QP: Given the following tRNA anticodon sequence, derive the mRNA and the DNA template strand. Also,...
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Pre-MRNA
A/C A G
GU AG A GU
CU A/G A C/U
NC AG G
Frequency of
occurrence (%)
70 60 80
100 100 95 70 80 45
80 90 80
100 80
80 100 100 60
15-45 bases
In Figure 8-15, what do you think would be the effect of a A to G mutation in the
branch point residue of the intron? (Two answers.)
The U5 snRNP would bind to the A that is now the first residue of the intron,
and splicing would proceed normally.
The U1 snRNP would be unable to bind to the intron, which would prevent
intron splicing from occurring.
The U1 snRNP would might find a nearby GU and use that for splicing, which
would allow splicing to occur but would have consequences on translation.
The U2 snRNP would be unable to bind to the branch point, which would
prevent intron splicing from occurring.
The U2 snRNP might find another nearby A and use that for the branch point,
which might allow normal intron splicing.
The hydroxyl from the branch point A would be unable to complete its
transesterification reaction, and intron splicing would come to a halt.
Transcribed Image Text:Pre-MRNA A/C A G GU AG A GU CU A/G A C/U NC AG G Frequency of occurrence (%) 70 60 80 100 100 95 70 80 45 80 90 80 100 80 80 100 100 60 15-45 bases In Figure 8-15, what do you think would be the effect of a A to G mutation in the branch point residue of the intron? (Two answers.) The U5 snRNP would bind to the A that is now the first residue of the intron, and splicing would proceed normally. The U1 snRNP would be unable to bind to the intron, which would prevent intron splicing from occurring. The U1 snRNP would might find a nearby GU and use that for splicing, which would allow splicing to occur but would have consequences on translation. The U2 snRNP would be unable to bind to the branch point, which would prevent intron splicing from occurring. The U2 snRNP might find another nearby A and use that for the branch point, which might allow normal intron splicing. The hydroxyl from the branch point A would be unable to complete its transesterification reaction, and intron splicing would come to a halt.
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