I’m trying so hard to figure out this for my homework for biology but I don’t understand it and it’s giving me a hard time It asks student bought a newly enzyme by the standard procedure. He dissolved 50mg of the enzyme on 100 mL water and used 10mL for the assay. He adds the enzyme to the substrate and collected the absorbance data as specified intervals. Calculate the specific activity of the enzyme at 5 minutes absorbance was 0.345 and 10 min absorbance was 0.645. For standard curve Y=0.238x

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