II 3 II 3 4 5 6 IV 2 3 4 5 6 7 1 2 3 [Source: D. Stambolian, R. A. Lewis, K. Buetow, A. Bond, and R. Nussbaum. 1990. American Journal of Human Genetics 47:15.] 4 1. On the basis of this pedigree, what do you think is the most likely mode of inheritance for Nance-Horan syndrome? o. If couple III-7 and III-8 have another child, what is the probability that he child will have Nance-Horan syndrome? . If III-2 and III-7 were to mate, what is the probability that one of their children would have Nance-Horan syndrome? %3D

II 3 II 3 4 5 6 IV 2 3 4 5 6 7 1 2 3 [Source: D. Stambolian, R. A. Lewis, K. Buetow, A. Bond, and R. Nussbaum. 1990. American Journal of Human Genetics 47:15.] 4 1. On the basis of this pedigree, what do you think is the most likely mode of inheritance for Nance-Horan syndrome? o. If couple III-7 and III-8 have another child, what is the probability that he child will have Nance-Horan syndrome? . If III-2 and III-7 were to mate, what is the probability that one of their children would have Nance-Horan syndrome? %3D

Name: The following pedigree illustrates the inheritance of Nance–Horan synd
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Description: The following pedigree illustrates the inheritance of Nance–Horan syndrome, a rare genetic condition in which affected people have cataracts and abnormally shaped teeth. II3II345 6IV23 45 6 71 2 3[Source: D. Stambolian, R. A. Lewis, K. Buetow, A. Bon

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter10: From Proteins To Phenotypes

Section: Chapter Questions

Problem 1CS: A couple was referred for genetic counseling because they wanted to know the chances of having a...

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BIU A- == 三E 12 - Match each of the following examples to the appropriate type of non-Mendelian inheritance. 1. A homozygous recessive genotype for the gene that encodes phenylalanine hydroxylase (which breaks down the amino acid phenylalanine) causes lighter skin color, a musty odor, differences in intellectual development, and seizures. 2. In pea plants, alleles of Gene W control flower color, with the dominant allele (W) leading to purple flower.color, and the recessive allele (w) leading to white flower color. Usually, a genotype of WW or Ww leads to purple flowers. However, when Gene C is homozygous recessive, WW or Ww plants always have white flowers. 3. In mallard ducks, feather coloring is controlled by Gene F. A dominant allele (F) leads to green head feathers, while a recessive allele (f) leads to brown head feathers. In male mallards, inheritance of one or more F alleles always leads to the green head feather trait. But female mallards always have brown head feathers,…
The following pedigree illustrates the inheritance of ringed hair, a condition in which each hair is differentiated into light and dark zones. What mode or modes of inheritance are possible for the ringed-hair trait in this family?
*22. Dent disease is a rare disorder of the kidney in which reabsorption of filtered solutes is impaired and there is progressive renal failure. R. R. Hoopes and colleagues studied mutations associated with Dent disease in the following family (R. R. Hoopes et al. 2005. American Journal of Human Genetics 76:260-267): II 2 3 4 5 II 3 4 5 6 7 8 IV a. On the basis of this pedigree, what is the most likely mode of inheritance for the disease? Explain your reasoning. b. Based your answer to part a, give the most likely genotypes for all family members in the pedigree.
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For the following problems, please choose from the following modes of inheritance: autosomal dominant, autosomal recessive, X-linked dominant, X-linked recessive 8080 50 OTO ㅁㅇㅇㅁ I. What is the most likely mode of inheritance portrayed in the pedigree above?
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F1 result Wild-type Mutant P: Wild type female x mutant male 0 258 P: wild type male x mutant female 0 193 F2 result Wild type Mutant F1 male x F1 female 268 205 what is the most likely mode of inheritance? 1. What is the Chi-square value for F2?
6) For the pedigree shown below, answer the following questions. I II III a) What type of inheritance is shown? Explain how you know. b) The genotype of individual I -2 is The genotype of individual II -1 is
1 III IV Lactose tolerant female Lactose intolerant female 3 Recessive 3 Recessive 6 Lactose tolerant male Lactose intolerant male Dominant 8 9 10 7 8 Dominant Figure 2. Pedigree of Family A. (Adapted from a figure in Enattah, N. S., et al. 2002 Nature Genetics 30: 233-237.) 1. Based on the pedigree above, which of the following terms are appropriate for describing the inheritance of the lactose-intolerance trait (filled-in symbols)? Check all that apply. X-linked Family A 9 11 ? Unknown phenotype Deceased X-linked 2. Which of the following terms are appropriate for describing the inheritance of the lactose-tolerance trait (empty symbols)? Mark all that apply. Autosomal Autosomal You decide you need more data to find out if your model for inheritance of lactose intolerance holds up. You examine three additional pedigrees from the Finnish study.
What feature(s) of this pedigree indicate(s) dominant inheritance?
A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What is the chance that this couple will have a child with two copies of the dominant mutant gene? What is the chance that the child will have normal height?
A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. Should the parents be concerned about the heterozygous condition as well as the homozygous mutant condition?