he propensity to develop retinal cancer can run in pedigrees of certain families. You have learned about the role of the retinoblastoma (Rb) protein in the cell cycle. A heterozygous individual (genotype = Rbm / Rb+) that inherits a mutant allele of the Rb gene (Rbm) as well as a normal allele of the Rb gene (Rb+) is at significant risk for developing cancer of the retina. The best explanation for this is that… A. the Rb(m) allele is dominant to the Rb(+) allele. B. a mutation in the Rb(+) allele can result in a Rb(m) / Rb(m) genotype in certain cells. C. the retina is frequently exposed to UV rays D. the Rb(m) allele directly converts the Rb(+) allele to another Rb(m) allele. E. the cells of the retina carry more than two copies of the Rb gene
he propensity to develop retinal cancer can run in pedigrees of certain families. You have learned about the role of the retinoblastoma (Rb) protein in the cell cycle. A heterozygous individual (genotype = Rbm / Rb+) that inherits a mutant allele of the Rb gene (Rbm) as well as a normal allele of the Rb gene (Rb+) is at significant risk for developing cancer of the retina. The best explanation for this is that… A. the Rb(m) allele is dominant to the Rb(+) allele. B. a mutation in the Rb(+) allele can result in a Rb(m) / Rb(m) genotype in certain cells. C. the retina is frequently exposed to UV rays D. the Rb(m) allele directly converts the Rb(+) allele to another Rb(m) allele. E. the cells of the retina carry more than two copies of the Rb gene
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
Section: Chapter Questions
Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...
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The propensity to develop retinal cancer can run in pedigrees of certain families. You have learned about the role of the retinoblastoma (Rb) protein in the cell cycle. A heterozygous individual (genotype = Rbm / Rb+) that inherits a mutant allele of the Rb gene (Rbm) as well as a normal allele of the Rb gene (Rb+) is at significant risk for developing cancer of the retina. The best explanation for this is that…
A. the Rb(m) allele is dominant to the Rb(+) allele.
B. a mutation in the Rb(+) allele can result in a Rb(m) / Rb(m) genotype in certain cells.
C. the retina is frequently exposed to UV rays
D. the Rb(m) allele directly converts the Rb(+) allele to another Rb(m) allele.
E. the cells of the retina carry more than two copies of the Rb gene
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