he propensity to develop retinal cancer can run in pedigrees of certain families. You have learned about the role of the retinoblastoma (Rb) protein in the cell cycle. A heterozygous individual (genotype = Rbm / Rb+) that inherits a mutant allele of the Rb gene (Rbm) as well as a normal allele of the Rb gene (Rb+) is at significant risk for developing cancer of the retina. The best explanation for this is that… A. the Rb(m) allele is dominant to the Rb(+) allele. B. a mutation in the Rb(+) allele can result in a Rb(m) / Rb(m) genotype in certain cells. C. the retina is frequently exposed to UV rays D. the Rb(m) allele directly converts the Rb(+) allele to another Rb(m) allele. E. the cells of the retina carry more than two copies of the Rb gene
he propensity to develop retinal cancer can run in pedigrees of certain families. You have learned about the role of the retinoblastoma (Rb) protein in the cell cycle. A heterozygous individual (genotype = Rbm / Rb+) that inherits a mutant allele of the Rb gene (Rbm) as well as a normal allele of the Rb gene (Rb+) is at significant risk for developing cancer of the retina. The best explanation for this is that… A. the Rb(m) allele is dominant to the Rb(+) allele. B. a mutation in the Rb(+) allele can result in a Rb(m) / Rb(m) genotype in certain cells. C. the retina is frequently exposed to UV rays D. the Rb(m) allele directly converts the Rb(+) allele to another Rb(m) allele. E. the cells of the retina carry more than two copies of the Rb gene
Human Heredity: Principles and Issues (MindTap Course List)
11th Edition
ISBN:9781305251052
Author:Michael Cummings
Publisher:Michael Cummings
Chapter11: Genome Alterations: Mutation And Epigenetics
Section: Chapter Questions
Problem 16QP: Familial retinoblastoma, a rare autosomal dominant defect, arose in a large family that had no prior...
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The propensity to develop retinal cancer can run in pedigrees of certain families. You have learned about the role of the retinoblastoma (Rb) protein in the cell cycle. A heterozygous individual (genotype = Rbm / Rb+) that inherits a mutant allele of the Rb gene (Rbm) as well as a normal allele of the Rb gene (Rb+) is at significant risk for developing cancer of the retina. The best explanation for this is that…
A. the Rb(m) allele is dominant to the Rb(+) allele.
B. a mutation in the Rb(+) allele can result in a Rb(m) / Rb(m) genotype in certain cells.
C. the retina is frequently exposed to UV rays
D. the Rb(m) allele directly converts the Rb(+) allele to another Rb(m) allele.
E. the cells of the retina carry more than two copies of the Rb gene
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