Human Heredity: Principles and Issues (MindTap Course List)
11th Edition
ISBN: 9781305251052
Author: Michael Cummings
Publisher: Cengage Learning
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Chapter 4, Problem 21QP
Analysis of X-Linked Dominant and Recessive Traits
As a genetic counselor investigating a genetic disorder in a family, you are able to collect a four-generation pedigree that details the inheritance of the disorder in question. Analyze the information in the pedigree to determine whether the trait is inherited as:
- a. autosomal dominant
- b. autosomal recessive
- c. X-linked dominant
- d. X-linked recessive
- e. Y-linked
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Pedigree chart
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Please explain I don’t think this is autosomal dominant as female are more affected than male and please explain B part of the question well.
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Chapter 4 Solutions
Human Heredity: Principles and Issues (MindTap Course List)
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Ch. 4 - Pedigree Analysis Is a Basic Method in Human...Ch. 4 - Analysis of Autosomal Recessive and Dominant...Ch. 4 - Analysis of Autosomal Recessive and Dominant...Ch. 4 - Use the following information to respond to the...Ch. 4 - Analysis of Autosomal Recessive and Dominant...Ch. 4 - Analysis of Autosomal Recessive and Dominant...Ch. 4 - A proband female with an unidentified disease...Ch. 4 - Analysis of Autosomal Recessive and Dominant...Ch. 4 - Prob. 12QPCh. 4 - Analysis of Autosomal Recessive and Dominant...Ch. 4 - Analysis of Autosomal Recessive and Dominant...Ch. 4 - Analysis of X-Linked Dominant and Recessive Traits...Ch. 4 - Prob. 16QPCh. 4 - Analysis of X-Linked Dominant and Recessive Traits...Ch. 4 - Analysis of Autosomal Recessive and Dominant...Ch. 4 - Analysis of X-Linked Dominant and Recessive Traits...Ch. 4 - Analysis of X-Linked Dominant and Recessive Traits...Ch. 4 - Analysis of X-Linked Dominant and Recessive Traits...Ch. 4 - Analysis of X-Linked Dominant and Recessive Traits...Ch. 4 - Prob. 23QPCh. 4 - Prob. 24QPCh. 4 - Variations in Phenotype Expression Define...Ch. 4 - Prob. 26QPCh. 4 - Variations in Phenotype Expression A genetic...Ch. 4 - Variations in Phenotype Expression Explain how...
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- Analysis of X-Linked Dominant and Recessive Traits The following is a pedigree for a common genetic trait. Analyze the pedigree to determine whether the trait is inherited as: a. autosomal dominant b. autosomal recessive c. X-linked dominant d. X-linked recessive e. Y-linkedarrow_forwardA couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What is the chance that this couple will have a child with two copies of the dominant mutant gene? What is the chance that the child will have normal height?arrow_forwardA couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. Should the parents be concerned about the heterozygous condition as well as the homozygous mutant condition?arrow_forward
- A couple was referred for genetic counseling because they wanted to know the chances of having a child with dwarfism. Both the man and the woman had achondroplasia (MIM 100800), the most common form of short-limbed dwarfism. The couple knew that this condition is inherited as an autosomal dominant trait, but they were unsure what kind of physical manifestations a child would have if it inherited both mutant alleles. They were each heterozygous for the FGFR3 (MIM 134934) allele that causes achondroplasia. Normally, the protein encoded by this gene interacts with growth factors outside the cell and receives signals that control growth and development. In achrodroplasia, a mutation alters the activity of the receptor, resulting in a characteristic form of dwarfism. Because both the normal and mutant forms of the FGFR3 protein act before birth, no treatment for achrondroplasia is available. The parents each carry one normal allele and one mutant allele of FGRF3, and they wanted information on their chances of having a homozygous child. The counsellor briefly reviewed the phenotypic features of individuals with achondroplasia. These include facial features (large head with prominent forehead; small, flat nasal bridge; and prominent jaw), very short stature, and shortening of the arms and legs. Physical examination and skeletal X-ray films are used to diagnose this condition. Final adult height is approximately 4 feet. Because achondroplasia is an autosomal dominant condition, a heterozygote has a 1-in-2, or 50%, chance of passing this trait to his or her offspring. However, about 75% of those with achondroplasia have parents of average size who do not carry the mutant allele. In these cases, achondroplasia is due to a new mutation. In the couple being counseled, each individual is heterozygous, and they are at risk for having a homozygous child with two copies of the mutated gene. Infants with homozygous achondroplasia are either stillborn or die shortly after birth. The counselor recommended prenatal diagnosis via ultrasounds at various stages of development. In addition, a DNA test is available to detect the homozygous condition prenatally. What if the couple wanted prenatal testing so that a normal fetus could be aborted?arrow_forwardGeneration a. What is the genotype of the mother? b. What is the genotype of the father? c. What are the genotypes of the five children" 41. What is/are the possible inheritance pattern(s) for the characteristic in the following pedigree? 11 a. Autosomal recessive only i b. Autosomal dominant only) c. X-linked recessive only d. X-linked dominant only e. All of the above are possible. 42. What is/are the possible inheritance pattern(s) for the characteristic in the following pedigree? 11 a Autosomal recessive only b. Autosomal dominant only c. X-linked recessive only d X-linked dominant only e. All of them are possible. 43. If the phenotype followed in the pedigree below is X-linked recessive, then the genotype of 11-2 is HI a homozygous dominant b heterozygous chomozygous recessive d hemuzygous dominant e bemizygous recessivearrow_forwardA. Identify the pattern of inheritance in the pedigree below. B. Provide two pieces of evidence that you used to come to this conclusion. C. Identify the genotypes of individuals II-1 and III-2 (at the arrows)arrow_forward
- Webbed fingers is inherited as an X-linked disease An unaffected male marries an affected female. a. Draw a Punnett square of the possible offspring. b. List the phenotypes of the possible children c. Draw a pedigree that displays the inheritance in you Punnett squarearrow_forwardthe pedigree below shows the inheritance of a newly identified eye color gene. Assume 100% penetrance and expressivity. Use the pedigree to find: 1. Identify the mode of inheritance (either autosomal dominant, or autosomal recessive) 2. Argue why your mode of inheritance must be correct. Your argument should cite specific individuals from the pedigree. (For example, the top left individual is person I-1).arrow_forwardGiven the following pedigree added. What questions are true and false?arrow_forward
- question is attachedarrow_forwardPEDIGREE: Shaded individuals in the pedigree have a genetic disease. Individuals marrying into the family, that is individuals II–1, II–4 and II–6, have no history of the disease in their families.1. Determine the mode of inheritance ______________________________2. Give the genotypes of the following individualsarrow_forwardBy looking at the following pedigree can you conclude why is it an X-linked recessive? If yes, why not dominant, Sex influenced, or Autosomal. Please provide sufficient reasoning, Thank you.arrow_forward
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