Human Heredity: Principles and Issues (MindTap Course List)
11th Edition
ISBN: 9781305251052
Author: Michael Cummings
Publisher: Cengage Learning
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Textbook Question
Chapter 4, Problem 28QP
Variations in
Explain how camptodactyly is an example of expressivity.
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In rare instances, B cells can be found that have two immunoglobulin light chain alleles, both of which are rearranged in frame, and can encode functional light chain proteins. Yet, on the surface of the B cell, only one of the two light chain proteins is detected in the membrane-bound immunoglobulin receptor. The reason these rare cells have two functional light chain rearrangements but only express one of the two light chains as part of the B-cell receptor is:
One of the two light chains is formed from rearrangement of a V gene segment that is a pseudogene.
One of the two light chain proteins doesn’t form a stable complex with the heavy chain expressed in this cell.
One of the two light chain alleles is not transcribed efficiently, and produces only low levels of protein.
One of the two light chain alleles uses a V gene segment that is not targeted very often by the RAG recombinase.
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1)
using at least one named example discuss the implication of allelic heterogeneity in single gene disorder for the presentation and progession of the disorder and its treatment
2)
discuss the importance of understanding epigenetics in improving people health
Alpha-1 antitrypsin has codominant inheritance. M genes express normal levels. S
and Z genes have low expression. Which of the following is most likely to develop
emphyema? A person with:
1) two M genes who does smoke
2) two S genes who does smoke
3) one M and one S gene who does not smoke
4) one M gene and one S gene who does smoke
5) two M genes who does not smoke
6) two S genes who does not smoke
Chapter 4 Solutions
Human Heredity: Principles and Issues (MindTap Course List)
Ch. 4.3 - Does a pedigree drawn from the available...Ch. 4.3 - Prob. 2EGCh. 4.7 - Did the fact that Prince Albert and Queen Victoria...Ch. 4.7 - Which members of the pedigree could have been...Ch. 4 - Pedigree analysis is a fundamental tool for...Ch. 4 - Pedigree analysis is a fundamental tool for...Ch. 4 - Pedigree analysis is a fundamental tool for...Ch. 4 - Pedigree Analysis Is a Basic Method in Human...Ch. 4 - Pedigree Analysis Is a Basic Method in Human...Ch. 4 - Pedigree Analysis Is a Basic Method in Human...
Ch. 4 - Pedigree Analysis Is a Basic Method in Human...Ch. 4 - Analysis of Autosomal Recessive and Dominant...Ch. 4 - Analysis of Autosomal Recessive and Dominant...Ch. 4 - Use the following information to respond to the...Ch. 4 - Analysis of Autosomal Recessive and Dominant...Ch. 4 - Analysis of Autosomal Recessive and Dominant...Ch. 4 - A proband female with an unidentified disease...Ch. 4 - Analysis of Autosomal Recessive and Dominant...Ch. 4 - Prob. 12QPCh. 4 - Analysis of Autosomal Recessive and Dominant...Ch. 4 - Analysis of Autosomal Recessive and Dominant...Ch. 4 - Analysis of X-Linked Dominant and Recessive Traits...Ch. 4 - Prob. 16QPCh. 4 - Analysis of X-Linked Dominant and Recessive Traits...Ch. 4 - Analysis of Autosomal Recessive and Dominant...Ch. 4 - Analysis of X-Linked Dominant and Recessive Traits...Ch. 4 - Analysis of X-Linked Dominant and Recessive Traits...Ch. 4 - Analysis of X-Linked Dominant and Recessive Traits...Ch. 4 - Analysis of X-Linked Dominant and Recessive Traits...Ch. 4 - Prob. 23QPCh. 4 - Prob. 24QPCh. 4 - Variations in Phenotype Expression Define...Ch. 4 - Prob. 26QPCh. 4 - Variations in Phenotype Expression A genetic...Ch. 4 - Variations in Phenotype Expression Explain how...
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