Biology 2e
2nd Edition
ISBN: 9781947172517
Author: Matthew Douglas, Jung Choi, Mary Ann Clark
Publisher: OpenStax
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Textbook Question
Chapter 12, Problem 29CTQ
Why is it more efficient to perform a test cross with a homozygous recessive donor than a homozygous dominant donor? How could the same information still he found with a homozygous dominant donor?
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Students have asked these similar questions
The table below shows the progeny of a test cross of a heterozygote (HhFfGg). Each row
shows the number of progeny that inherited each combination of alleles from the
heterozygous parent. You've already determined the gene order (G is in the middle) and
labeled each type of progeny. Using this information, what is the recombination frequency
between H and G?
Alleles: Type:
HGF
hgf
HgF
h Gf
Hgf
h GF
HGf
hg F
O 0.543
0.302
O 0.241
O 0.23
0.139
Parental
Parental
DCO
DCO
SCO (H-G)
SCO (H-G)
SCO (G-F)
SCO (G-F)
Count:
124
119
15
18
51
55
38
40
O The correct answer is not available.
Two linked loci have a recombination frequency of 5%. A series of crosses is performed. The P generation includes an individual that is homozygous dominant for trait 1 and homozygous recessive for trait 2. The second individual is homozygous recessive for trait 1 and homozygous dominant for trait 2. The F1 generation is crossed with individuals that are homozygous recessive for both traits. If 400 F2 offspring are produced, how many offspring with each phenotype are expected? Fill in the table below with your answers.
Phenotype
Number of Offspring Predicted
Recessive 1, Recessive 2
Dominant 1, Dominant 2
Recessive 1, Dominant 2
Dominant 1, Recessive 2
Total offspring
400
For the results above, determine which phenotypes are parental and which are recombinant.
Phenotype
Parental or Recombinant?
Dominant 1, Dominant 2
Recessive 1, Dominant 2
Recessive 1, Recessive 2
Dominant 1, Recessive 2
in three points mapping one parent has the A+C/+b+ genotype that was crossed to a homozygous recessive second parent.
a)what is the genotype of this second parent?
b)what are the genotypes of the double cross over offspring?
Chapter 12 Solutions
Biology 2e
Ch. 12 - Figure 12.5 In pea plants, round peas (R) are...Ch. 12 - Figure 12.6 What are the genotypes of the...Ch. 12 - Figure 12.12 What ratio of offspring would result...Ch. 12 - Figure 12.16 In pea plants, purple flowers (P) are...Ch. 12 - Mendel performed hybridizations by transferring...Ch. 12 - Which is one of the seven characteristics that...Ch. 12 - Imagine you are performing a cross involving seed...Ch. 12 - Consider a cross to investigate the pea pod...Ch. 12 - A scientist pollinates a true-breeding pea plant...Ch. 12 - The observable traits expressed by an organism are...
Ch. 12 - A recessive trait will be observed in individuals...Ch. 12 - If black and white true-breeding mice are mated...Ch. 12 - The ABO blood groups in humans are expressed as...Ch. 12 - In a mating between two individuals that are...Ch. 12 - If the allele encoding polydactyly (six fingers)...Ch. 12 - A farmer raises black and white chickens. To his...Ch. 12 - Assuming no gene linkage, in a dihybrid cross of...Ch. 12 - The forked line and probability methods make use...Ch. 12 - How many different offspring genotypes are...Ch. 12 - Labrador retriever's fur color is controlled by...Ch. 12 - Which of the following situations does not follow...Ch. 12 - Describe one of the reasons why the garden pea was...Ch. 12 - How would you perform a reciprocal cross for the...Ch. 12 - Mendel performs a cross using a true-breeding pea...Ch. 12 - Calculate the probability of selecting a heart or...Ch. 12 - The gene for flower position in pea plants exists...Ch. 12 - Use a Punnett square to predict the offspring in a...Ch. 12 - Can a human male be a carrier of red-green color...Ch. 12 - Why is it more efficient to perform a test cross...Ch. 12 - Use the probability method to calculate the...Ch. 12 - Explain epistatis in terms of its Greek-language...Ch. 12 - In Section 12.3, ''Laws of Inheritance," an...Ch. 12 - People with trisomy 21 develop Down’s syndrome....Ch. 12 - A heterozygous pea plant produces violet flowers...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Given the karyotype shown at right, is this a male or a female? Normal or abnormal? What would the phenotype of this individual be?arrow_forwardIndividuals of genotype AaBb were mated to individuals of genotype aabb. One thousand offspring were counted, with the following results: 474 Aabb, 480 aaBb, 20 AaBb, and 26 aabb. What type of cross is it? Are these loci linked? What are the two parental classes and the two recombinant classes of offspring? What is the percentage of recombination between these two loci? How many map units apart are they?arrow_forwardThree linked loci are evaluated to determine the recombination frequency of the loci. To set up the test cross, an individual that is true breeding dominant for all three phenotypes is crossed with an individual that is true breeding recessive for all three phenotypes. F1 offspring are crossed with individuals that are recessive for all phenotypes. The phenotypic results are shown in the table below. Phenotype Number of Offspring Dominant 1, Dominant 2, Dominant 3 322 Dominant 1, Dominant 2, Recessive 3 82 Recessive 1, Dominant 2, Recessive 3 5 Dominant 1, Recessive 2, Dominant 3 2 Recessive 1, Dominant 2, Dominant 3 28 Recessive 1, Recessive 2, Dominant 3 89 Recessive 1, Recessive 2, Recessive 3 312 Dominant 1, Recessive 2, Recessive 3 25 1. Which two phenotypes are parental? 2. What is the map distance between locus 1 and locus 2? 3. What is the map distance between locus 1 and locus 3? 4. What is the map distance between…arrow_forward
- Could someone please help me with this grade 11 bio dihybrid cross problem in detail and how to solve this question, using a strategy? Assume that curly hair (C) is dominant to straight hair. Albinism (P ) is recessive to normal skin pigmentation. A woman who is heterozygous for curly hair and albinism has a child. The father is homozygous dominant for curly hair and has albinism. (a) Determine the possible phenotypes for their child. (double-crossing, Puneet square)(b) Calculate the four different probabilities of a child beingboth a male and of each phenotype.(c) What is the probability that the child will expressalbinism and have curly hair like his father?arrow_forwardFor linkage analysis, a test cross is used rather than a hybrid cross. Why is this essential? Why would a hybrid cross result in incorrect estimates of genetic distance?arrow_forwardHere is the URL: https://media.saplinglearning.com/priv/he/bio/punnett-squares/lab.html Thank you!arrow_forward
- Assignment 1 A pure strain of Mendel's peas, dominant for all seven of his independently assorting genes, was testcrossed. a) How many different kinds of gametes could each of the parents produce? b) How many different gametes could the F, produce? Assignments Assignment 1 c) If the F, was testcrossed, how many phenotypes would be expected in the offspring and in what proportion? d) How many genotypes would be expected in the F,?arrow_forwardThe table below shows the progeny of a test cross of a heterozygote (JjBbRr). Each row shows the number of progeny that inherited each combination of alleles from the heterozygous parent. You've already determined the gene order (B is in the middle) and labeled each type of progeny. Using this information, what is the recombination frequency between J and B? Alleles: Type: Count: J B R Parental 132 j b r Parental 135 J b R DCO 15 j B r DCO 11 J b r SCO (J-B) 59 j B R SCO (J-B) 55 J B r SCO (B-R) 38 j b R SCO (B-R) 40 Group of answer choices 0.214 0.235 0.289 the correct answer is not available. 0.503 0.14arrow_forwardWhat happens if a karyotype test is not normal?arrow_forward
- Cougar coat color and eye color are determined by two genes on the same chromosome, gene C and gene E. Gene C has two alleles: the dominant allele C produces wild type (tan) coats and the recessive allele c produces white coats. Gene E has two alleles: the dominant allele E produces wild type (brown eyes) and the recessive allele e confers blue eyes. To determine the recombination rate between these two loci you cross a wild-type cougar (CCEE) to a white-coated, blue-eyed cougar to produce a diheterozygous male cougar (CcEe). You then mate F1 male to a series of white-coated, blue-eyed female cougars to produce a panel of F2 offspring in the table below. What is the recombination rate between the two loci? Express your answer in map units, rounded to the nearest integer. phenotype number of F1 offspring tan coat, brown eyes 200 tan coat, blue eyes 50 white coat, blue eyes 201 white coat, brown eyes 55arrow_forwardIn Mendel's experiments, he obtained the following results: Which phenotypes can be said to be dominant?arrow_forwardThe following table provides results (petal colour) of 4 different F1 X F1 crosses. The genes involved in the 4 crosses are unrelated. Complete the table by indicating the phenotype of the testers and what would be the phenotypic ratios if the each F1 (indicated in the F1 phenotype column) were testcrossed.arrow_forward
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