Biology 2e
2nd Edition
ISBN: 9781947172517
Author: Matthew Douglas, Jung Choi, Mary Ann Clark
Publisher: OpenStax
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Textbook Question
Chapter 12, Problem 18RQ
The forked line and probability methods make use of what probability rule?
- test cross
- product rule
- monohybrid rule
- sum rule
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Chapter 12 Solutions
Biology 2e
Ch. 12 - Figure 12.5 In pea plants, round peas (R) are...Ch. 12 - Figure 12.6 What are the genotypes of the...Ch. 12 - Figure 12.12 What ratio of offspring would result...Ch. 12 - Figure 12.16 In pea plants, purple flowers (P) are...Ch. 12 - Mendel performed hybridizations by transferring...Ch. 12 - Which is one of the seven characteristics that...Ch. 12 - Imagine you are performing a cross involving seed...Ch. 12 - Consider a cross to investigate the pea pod...Ch. 12 - A scientist pollinates a true-breeding pea plant...Ch. 12 - The observable traits expressed by an organism are...
Ch. 12 - A recessive trait will be observed in individuals...Ch. 12 - If black and white true-breeding mice are mated...Ch. 12 - The ABO blood groups in humans are expressed as...Ch. 12 - In a mating between two individuals that are...Ch. 12 - If the allele encoding polydactyly (six fingers)...Ch. 12 - A farmer raises black and white chickens. To his...Ch. 12 - Assuming no gene linkage, in a dihybrid cross of...Ch. 12 - The forked line and probability methods make use...Ch. 12 - How many different offspring genotypes are...Ch. 12 - Labrador retriever's fur color is controlled by...Ch. 12 - Which of the following situations does not follow...Ch. 12 - Describe one of the reasons why the garden pea was...Ch. 12 - How would you perform a reciprocal cross for the...Ch. 12 - Mendel performs a cross using a true-breeding pea...Ch. 12 - Calculate the probability of selecting a heart or...Ch. 12 - The gene for flower position in pea plants exists...Ch. 12 - Use a Punnett square to predict the offspring in a...Ch. 12 - Can a human male be a carrier of red-green color...Ch. 12 - Why is it more efficient to perform a test cross...Ch. 12 - Use the probability method to calculate the...Ch. 12 - Explain epistatis in terms of its Greek-language...Ch. 12 - In Section 12.3, ''Laws of Inheritance," an...Ch. 12 - People with trisomy 21 develop Down’s syndrome....Ch. 12 - A heterozygous pea plant produces violet flowers...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- When a chi square test is applied to solve a linkage problem, explain why an independent assortment hypothesis is proposed.arrow_forwardGive typing answer with explanation and conclusion Directions: For the following problem, calculate the probability of the offspring between the cross using the sum and product rule. The parent generation has genotypes of Aa Bb Cc and AA Bb CC. What is the probability the F1 generation would be AA bb cc?arrow_forwardUse the forkline method to derive the gametic ratio of cross AabbDD x AABbDd. The cross are segregated independently.arrow_forward
- You have determined that the gene order for three linked genes being studied is A B C. The number of recombinants resulting from crossover between genes A and BC are 44 and 48, respectively, while the double-crossover progeny total 4 and 6. What is the recombination frequency between genes A and B if the total progeny from the cross is 1000? Show all of your work.arrow_forwardIn a monohybrid cross of two heterozygous parents (Pp), what would the expected genotypes of the offspring be? show your solutionarrow_forwardIn a series of three experiments, M. G. Addo sought to use chi-square test to determine the goodness of fit at 5% for each of his results below. Carry out the calculations and determine whether the results obtained in each case are consistent with the 3:1 or 1:1:1:1 ratio he predicted in his hypothesis. Comment on your results. CROSS Tall x short Purple x white Round yellow (F1) x Wrinkled green (F1) RESULTS HΥΡΟΤHESIS 712:352 3:1 705 : 224 3:1 31:26:27:26 1:1:1:1arrow_forward
- What would justify the following ratio appearing after phenotyping the outcome of a crossing trial: 8.9: 2.9: 3.2:1? Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a b C d Obviously this represents independent assortment based on crossing dihybrid heterozygotes. Obviously this represents gene linkage based on test crossing a dihybrid heterozygote. Obviously this represents the results of a trihybrid test cross. Obviously this represents independent assortment based on crossing monohybrid heterozygotes.arrow_forwardFOR THIS QUESTION, EXCEL *MUST* BE USED TO CALCULATE THE P-VALUE FOR CHI SQUARED! Here is a link to the Khan Academy page on dihybrid crosses and gene mapping. Here is a link to the Math Bench web page on performing chi-squared tests. There are two alleles for the arr gene, A and a. There are also two alleles for bee gene, B and b. The two genes are on a chromosome that is 1.5 micrometers in length, but it has yet to be determined if the two genes are linked. Below is data from a study to determine if the genes are linked, and if so, how far apart the genes are on the chromosome. An organism that is heterozygous for both the arr gene and the bee gene is crossed with an organism that is homozygous recessive for both genes. Using this information, it is possible to calculate the expected phenotypic ratio of the offspring of the two organisms, assuming the two genes are "NOT" linked. If the genes are linked, the offspring will not exhibit the expected phenotypic ratio. 1. The arr and bee…arrow_forwardThe gel image above shows 7 alleles, let's call them 1-7 in order of size, with 1 being the largest and 7 being the smallest. What is the approximate size in Kbp of allele 4? Please type your answer as a number, please do not add units. ANSWER: The approximate size of allele 4 in the gel image below is Blank 1 Kbp Photograph of UV illuminated 1 % agarose TBE gel run for 40 minutes at 120 V, showing the result of PCR from a variable number tandem repeat region in 11 different individuals (A-K) 2000 1650 1000 850 600 500 Key: Lane 1: Lanes 2-12: A B C D E F G H I J K DNA ladder, see image for fragment sizes in base pairs (bp) PCR Products from the same variable number tandem repeat (VNTR) autosomal region of DNA from 11 different individuals (A-K)arrow_forward
- What disorder is shown in the following karyotype? Explain your reasoning and describe any other information that the karyotype shows. %3D 2 3 4 5 11 6 7 8 9 10 %3D %3D 11 12 13 14 15 16 17 18 19 20 21 22arrow_forwardA three point testcross is carried out between three linked genes. The resulting nonrecombinant progeny are d+b+k+ and dbk and the double-crossover progeny are dbk+ and d+b+k. Which is the middle locus? Show all your work. Show all possible progeny.arrow_forwardGenotype HA На hA ha НА НН АА НН Аа Hh AA Hh Aa На НН Аa НН аa Hh Aa Hh aa hA Hh AA Hh Aa hh AA hh Aa ha Hh Aa Hh aa hh Aa hh aa Кey: H = long hair h = short hair A = brown a = green What is the probability that among the first two offspring, one will be short-haired and green- eyed, and the other will be short-haired and brown-eyed? 3/256 3/128 O 1/16 О 3/16arrow_forward
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