Biology 2e
2nd Edition
ISBN: 9781947172517
Author: Matthew Douglas, Jung Choi, Mary Ann Clark
Publisher: OpenStax
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Chapter 12, Problem 32CTQ
In Section 12.3, ''Laws of Inheritance," an example of epistasis was given for the summer squash. Cross white WAvYy heterozygotes to prove the
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If a homozygous tall pea plant is crossed with a homozygous shortpea plant, what are the possible genotype and phenotype of theoffspring? Legend:
T- tall pea plant
t- short pea plant
Genotypes of the parents:
TT x tt
Question to answer ff:
1. What is the genotypic ratio?
2. What are the possible phenotypes of the offspring?
3. What is the phenotypic ratio?
A mapping experiment in strawberries shows that the genes for color and plant height are separated by 16cM. In a cross between a heterozygous plant (CcHh) and a homozygous recessive plant, what percent of offspring would inherit a chromosome carrying cH from the heterozygous parent....
1. if the heterozygous parent’s alleles are in repulsion? _________________
2. if the heterozygous parent’s alleles are in coupling? _________________
“Laws of Inheritance,” an example of epistasis was given for the summer squash. Cross white WwYy heterozygotes to prove the phenotypic ratio of 12 white:3 yellow:1 green that was given in the text.
Chapter 12 Solutions
Biology 2e
Ch. 12 - Figure 12.5 In pea plants, round peas (R) are...Ch. 12 - Figure 12.6 What are the genotypes of the...Ch. 12 - Figure 12.12 What ratio of offspring would result...Ch. 12 - Figure 12.16 In pea plants, purple flowers (P) are...Ch. 12 - Mendel performed hybridizations by transferring...Ch. 12 - Which is one of the seven characteristics that...Ch. 12 - Imagine you are performing a cross involving seed...Ch. 12 - Consider a cross to investigate the pea pod...Ch. 12 - A scientist pollinates a true-breeding pea plant...Ch. 12 - The observable traits expressed by an organism are...
Ch. 12 - A recessive trait will be observed in individuals...Ch. 12 - If black and white true-breeding mice are mated...Ch. 12 - The ABO blood groups in humans are expressed as...Ch. 12 - In a mating between two individuals that are...Ch. 12 - If the allele encoding polydactyly (six fingers)...Ch. 12 - A farmer raises black and white chickens. To his...Ch. 12 - Assuming no gene linkage, in a dihybrid cross of...Ch. 12 - The forked line and probability methods make use...Ch. 12 - How many different offspring genotypes are...Ch. 12 - Labrador retriever's fur color is controlled by...Ch. 12 - Which of the following situations does not follow...Ch. 12 - Describe one of the reasons why the garden pea was...Ch. 12 - How would you perform a reciprocal cross for the...Ch. 12 - Mendel performs a cross using a true-breeding pea...Ch. 12 - Calculate the probability of selecting a heart or...Ch. 12 - The gene for flower position in pea plants exists...Ch. 12 - Use a Punnett square to predict the offspring in a...Ch. 12 - Can a human male be a carrier of red-green color...Ch. 12 - Why is it more efficient to perform a test cross...Ch. 12 - Use the probability method to calculate the...Ch. 12 - Explain epistatis in terms of its Greek-language...Ch. 12 - In Section 12.3, ''Laws of Inheritance," an...Ch. 12 - People with trisomy 21 develop Down’s syndrome....Ch. 12 - A heterozygous pea plant produces violet flowers...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- The following pedigree shows the pattern of inheritance of red-green color blindness in a family. Females are shown as circles and males as squares; the squares or circles of individuals affected by the trait are filled in black. What is the chance that a son of the third-generation female indicated by the arrow will be color blind if the father is not color blind? If he is color blind?arrow_forwardThe text outlines some of the problems Frederick William I encountered in his attempt to breed tall Potsdam Guards. a. Why were the results he obtained so different from those obtained by Mendel with short and tall pea plants? b. Why were most of the children shorter than their tall parents?arrow_forwardA pea plant of unknown genotype is test-crossed (one parent is recessive). Of the total progenies, 477 have wrinkled seed and 507 have round seed. What is the genotype of the unknown parent?arrow_forward
- Mendelian ratios are modified in crosses involving autotetraploids.Assume that one plant expresses the dominant trait greenseeds and is homozygous (WWWW). This plant is crossed to onewith white seeds that is also homozygous (wwww). If only onedominant allele is sufficient to produce green seeds, predict theF1 and F2 results of such a cross. Assume that synapsis betweenchromosome pairs is random during meiosis.arrow_forwardConsider this cross in pea plants: Tt Rr yy Aa × Tt rr Yy Aa, whereT = tall, t = dwarf, R = round, r = wrinkled, Y = yellow, y = green,A = axial, a = terminal. What is the expected phenotypic outcomeof this cross? Have one group of students solve this problem bymaking one big Punnett square, and have another group solve it bymaking four single-gene Punnett squares and using the multiplication method. Time each other to see who gets done first.arrow_forwardTwo mice with gray fur are crossed. They produce 15 gray, 8 black, and 6 white offspring. In one paragraph, using your own words, explain the inheritance of these colors in the mice. What phenotypes would you expect in the offspring of a cross between a gray mouse and a white mouse? Be sure to include proper spelling, grammar, and punctuation.arrow_forward
- In Figure 2-11, assume (as in corn plants) that allele Aencodes an allele that produces starch in pollen and allele a does not. Iodine solution stains starch black. Howwould you demonstrate Mendel’s first law directly withsuch a system?arrow_forwardCan you please help find how many black leaves there are?arrow_forwardIn the following cross, imagine that you have a female fly that has two Xs and one Y due to a nondisjunction event in her mother's germ cells. Draw out what the possible gametes are for both the female and the male and also a Punnett square showing the genotypes, phenotypes, and sex of the possible flies as a result of this cross. You do not need to provide the probabilities of each of these. Red-eyed wi C Ở Red-eyed wt XX Y X Y Meiosisarrow_forward
- In watermelons, bitter fruit (B) is dominant over sweet fruit (b), and yellow spots (S) are dominant over no spots (s). The genes for these two characteristics assort independently. A homozygous plant that has bitter fruit and yellow spots is crossed with a homozygous plant that has sweet fruit and no spots. The F1 are intercrossed to produce the F2. What will be the phenotypic ratios in the F2? 2. If an F1 plant is backcrossed with the bitter, yellow-spotted parent, what phenotypes and proportions are expected in the offspring? 3. If an F1 plant is backcrossed with the sweet, non-spotted parent, what phenotypes and proportions are expected in the offspring? 4. In cats, curled ears (Cu) result from an allele that is dominant over an allele for normal ears (cu). Black color results from an independently assorting allele (G) that is dominant over an allele for gray (g). A gray cat homozygous for curled ears is mated with a homozygous black cat with normal ears. All the F1…arrow_forwardTwo pure-breeding lines of petunia plants are crossed. Line 1 plants grow to a height of 54 cm, and Line 2 plants grow to a height of 18 cm. Petunia plant height is controlled by three genes, A, B and C. Line 1 has the genotype A₁A₁B₁B₁C₁C₁, and line 2 has the genotype A2A2B₂B₂C₂C₂. Assume that genotype alone determines plant height under ideal growth conditions and that the alleles of the three genes are additive. If the F1 plants are self crossed, what is the expected proportion of F2 plants with the genotype A₁A₁B₁B₁C₁C₁ 1/8 1/32 1/16 1/4 1/64arrow_forwardIn this case a family history revealed a genetic basis for the disorder. The pedigree is shown in Fig. 1 Below. Key Ø Female: affected Female: unaffected || IV V 5600 orize 077808 15 10 9 10 CHO વ Male: affected Male: unaffected Deceased Disease status not given Dizygotic twins Monozygotic twins Fig. 1 Disease pedigree. Five generations I, II, III, IV, V are shown. Females are represented by circles, males by squares, dizygotic (non-identical) twins by diagonal lines originating from the same point, Monozygotic (identical) twins by diagonal lines originating from the same point and joined symbols and deceased by a diagonal line through the symbol. Filled symbols indicate that the individual displays the disease phenotype. Unfilled symbols indicate that the individual does not display the disease phenotype. Carriers of the disease are not indicated. Information on disease status is not known for generation I and is omitted for the individuals represented by a symbol with an asterisk.…arrow_forward
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