For the 3-phase, 3 wire system below. Compute for the line currents, total real power, total reactive power, total apparent power, and power factor of the load if V 20020 V. V 2002240 V, V 2002-240 V 120 160 10 €200 40 Figure 1. Question number 2. You can use the sample problem below as guide answering the problem, please use 3 decimal points for the final answer! Sample Problem solution for guide (the given from this problem is different from the problem above) Z₁-122-/16-2022-53.13°, Z₂-32+√402=552 253.13⁰ Z₁-2012 20⁰ EAR-200 V20°, Eac-200 V Z-120°, Ec-200 V Z120⁰ Z₁ Z₁ Z₂ +Z₁Z+ZaZa -(20 2 2-53.13°) (5 2 253.13%) + (202-53.13°) (200°) +(52 253.13°)(20 220°) - 100 £220° +400 22-53.13° +100 52 253.13⁰ -100 2+(240 2-/320 2) + (60 2+/80 (2) = 400 Ω -- /240 Ω = 466.48 22-30.96⁰ E ‚µ‚Z, – Ec¿Z₂ – (200 V ≤0°)(2012 20°) - (200 V <120°)(52 253.139) 4000 A 20-1000 A 2173.13° 10.71 A 229.59 466.482-30.96 EcZ-EZ (200 VZ-120°)(202Z-53.13º) - (200 V 20°)(2012 20°) ZA ZA 4000 A 2-173.13°-4000 A 20⁰ -17.12 A Z-145.61 466.48 Z-30.96° Eczy-Enz (200 V Z120°)(5 £253.13º) – (200 VZ-120°)(202-53.13°) ZA ZA 1000 A 2173.13°-4000 AZ-173.13° --6.51 A 242.32 466.482-30.96 Pr=11202+1242 +12002 1376.45 W +1172.38 W+847.60 W-3396.43 W Qr=121602+1 32-1835.27 VAR(C)+879.28 VAR(L)-955.99 VAR(C) S-√√P+Q-3508.40 VA 3396.43 W P Sq 3508.40 VA -0.968 (leading)
For the 3-phase, 3 wire system below. Compute for the line currents, total real power, total reactive power, total apparent power, and power factor of the load if V 20020 V. V 2002240 V, V 2002-240 V 120 160 10 €200 40 Figure 1. Question number 2. You can use the sample problem below as guide answering the problem, please use 3 decimal points for the final answer! Sample Problem solution for guide (the given from this problem is different from the problem above) Z₁-122-/16-2022-53.13°, Z₂-32+√402=552 253.13⁰ Z₁-2012 20⁰ EAR-200 V20°, Eac-200 V Z-120°, Ec-200 V Z120⁰ Z₁ Z₁ Z₂ +Z₁Z+ZaZa -(20 2 2-53.13°) (5 2 253.13%) + (202-53.13°) (200°) +(52 253.13°)(20 220°) - 100 £220° +400 22-53.13° +100 52 253.13⁰ -100 2+(240 2-/320 2) + (60 2+/80 (2) = 400 Ω -- /240 Ω = 466.48 22-30.96⁰ E ‚µ‚Z, – Ec¿Z₂ – (200 V ≤0°)(2012 20°) - (200 V <120°)(52 253.139) 4000 A 20-1000 A 2173.13° 10.71 A 229.59 466.482-30.96 EcZ-EZ (200 VZ-120°)(202Z-53.13º) - (200 V 20°)(2012 20°) ZA ZA 4000 A 2-173.13°-4000 A 20⁰ -17.12 A Z-145.61 466.48 Z-30.96° Eczy-Enz (200 V Z120°)(5 £253.13º) – (200 VZ-120°)(202-53.13°) ZA ZA 1000 A 2173.13°-4000 AZ-173.13° --6.51 A 242.32 466.482-30.96 Pr=11202+1242 +12002 1376.45 W +1172.38 W+847.60 W-3396.43 W Qr=121602+1 32-1835.27 VAR(C)+879.28 VAR(L)-955.99 VAR(C) S-√√P+Q-3508.40 VA 3396.43 W P Sq 3508.40 VA -0.968 (leading)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
Related questions
Concept explainers
Load flow analysis
Load flow analysis is a study or numerical calculation of the power flow of power in steady-state conditions in any electrical system. It is used to determine the flow of power (real and reactive), voltage, or current in a system under any load conditions.
Nodal Matrix
The nodal matrix or simply known as admittance matrix, generally in engineering term it is called Y Matrix or Y bus, since it involve matrices so it is also referred as a n into n order matrix that represents a power system with n number of buses. It shows the buses' nodal admittance in a power system. The Y matrix is rather sparse in actual systems with thousands of buses. In the power system the transmission cables connect each bus to only a few other buses. Also the important data that one needs for have a power flow study is the Y Matrix.
Types of Buses
A bus is a type of system of communication that transfers data between the components inside a computer or between two or more computers. With multiple hardware connections, the earlier buses were parallel electrical wires but the term "bus" is now used for any type of physical arrangement which provides the same type of logical functions similar to the parallel electrical bus. Both parallel and bit connections are used by modern buses. They can be wired either electrical parallel or daisy chain topology or are connected by hubs which are switched same as in the case of Universal Serial Bus or USB.
Question
Transcribed Image Text:For the 3-phase, 3 wire system below. Compute for the line currents, total real power, total
reactive power, total apparent power, and power factor of the load if V 20020 V, Vi=
2002240° V, V 2002-240° V
120
160
30
2002
40
Figure 1. Question number 2.
You can use the sample problem below as guide answering the problem, please use 3 decimal points
for the final answer!
Sample Problem solution for guide (the given from this problem is different from the problem above)
Z₁ =1222-/1622=2022-53.13°, Z₂ = 3+j4N2=592 253.13⁰
Z₂-2012 20⁰
EAB= 200 V20°, Esc-200 V Z-120°, Ec=200 V <120°
Z₁ = Z₁ Z₂ +Z₁Z₁ + Z₂Zs
= (20 22-53.13°) (5 52 253.13°) + (20 2 2-53.13°) (20 2200)
+(52 253.13°) (20 5220°)
= 100 £2 20° +400 2 Z-53.13° +100 52 253.13⁰
= 100 2+(240 2-/320 2) + (60 2+j80 (2)
= 400 Ω - j240 Ω
= 466.48 2 Z-30.96°
L
EZ, - EcZ₂ (200 V Z0°)(205220°) – (200 V Z120°)(52 253.13°)
ZA
Z₂
4000 A 20°-1000 A 2173.13°
10.71 A 229.59⁰
466.482-30.96
EncZ₂-EAZY (200 VZ-120°)(202Z-53.13°) - (200 V Z0°)(2012 20°)
Zo
ZA
4000 A 2-173.13°-4000 A 20°
-17.12 A Z-145.61°
466.482-30.96º
Ecizy-Ecz (200 V <120°)(5 £253.13°) - (200 VZ-120°)(20£2-53.130)
Z₂
ZA
1000 A 2173.13°-4000 A Z-173.13°
-=6.51 A 242.32°
466.482-30.96
Pr=11202 +1242 +12052
=1376.45 W +1172.38 W +847.60 W = 3396.43 W
Qr=1162+1 32-1835.27 VAR(C)+879.28 VAR(L) = 955.99 VAR(C)
S₁-√√P+Q-3508.40 VA
PL-
3396.43 W
F,-
= 0.968 (leading)
ST 3508.40 VA
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 2 steps
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.Recommended textbooks for you
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:
9780133923605
Author:
Robert L. Boylestad
Publisher:
PEARSON
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:
9781337900348
Author:
Stephen L. Herman
Publisher:
Cengage Learning
Programmable Logic Controllers
Electrical Engineering
ISBN:
9780073373843
Author:
Frank D. Petruzella
Publisher:
McGraw-Hill Education
Introductory Circuit Analysis (13th Edition)
Electrical Engineering
ISBN:
9780133923605
Author:
Robert L. Boylestad
Publisher:
PEARSON
Delmar's Standard Textbook Of Electricity
Electrical Engineering
ISBN:
9781337900348
Author:
Stephen L. Herman
Publisher:
Cengage Learning
Programmable Logic Controllers
Electrical Engineering
ISBN:
9780073373843
Author:
Frank D. Petruzella
Publisher:
McGraw-Hill Education
Fundamentals of Electric Circuits
Electrical Engineering
ISBN:
9780078028229
Author:
Charles K Alexander, Matthew Sadiku
Publisher:
McGraw-Hill Education
Electric Circuits. (11th Edition)
Electrical Engineering
ISBN:
9780134746968
Author:
James W. Nilsson, Susan Riedel
Publisher:
PEARSON
Engineering Electromagnetics
Electrical Engineering
ISBN:
9780078028151
Author:
Hayt, William H. (william Hart), Jr, BUCK, John A.
Publisher:
Mcgraw-hill Education,