Q5 The single-line diagram of a three-phase power system is shown in Figure Q5a, with equipment ratings given in Table Q5a. (a) (b) G₁ G₂ G3 G4 T₁ T₂ T3 TA Draw the zero, positive and negative-sequence reactance diagrams using 1000 MVA, 765 kV base in the zone of Line 1-2, neglect the (A-Y) transformer phase shifts. Calculate the short circuit current as a result of three-phase bolted fault occurred at bus 1. Line 1-2 Line 1-3 Line 2-3 bus 1 0 Υ ΔΕ Line 1-3 Line 1-2 G₂ Line 2-3 bus 2 Da Figure 05a bus 3 Table Q5a T₂ KEY YE my 1000 MVA, 15 kV, X₁-X₂-0.18 p.u., Xo = 0.07, p.u. 1000 MVA, 15 kV, X₁-X2-0.20 p.u., Xo = 0.10, p.u. 500 MVA, 13.8 kV, X₁-X₂-0.15 p.u., Xo = 0.05, p.u. X₂ = 0.05 p.u. 750 MVA, 13.8 kV, X₁-0.3 p.u., X₂-0.4 p.u., Xo = 0.1, p.u. 1000 MVA, 15 kV (A) / 765 kV (Y), XTI = 0.10 p.u. 1000 MVA, 15 kV (A)/ 765 kV (Y), XT2 = 0.10 p.u. 500MVA, 15 kV (Y) / 765 kV (Y), XT3 = 0.12 p.u. 750 MVA, 15 kV (Y)/765 kV (Y), XT4 = 0.11 p.u. Χ = 50 Ω, Χρ = 150 Ω. X = 40 Ω, X = 100 Ω. Χρ = 40 Ω, Χρ = 100 Ω.
Q5 The single-line diagram of a three-phase power system is shown in Figure Q5a, with equipment ratings given in Table Q5a. (a) (b) G₁ G₂ G3 G4 T₁ T₂ T3 TA Draw the zero, positive and negative-sequence reactance diagrams using 1000 MVA, 765 kV base in the zone of Line 1-2, neglect the (A-Y) transformer phase shifts. Calculate the short circuit current as a result of three-phase bolted fault occurred at bus 1. Line 1-2 Line 1-3 Line 2-3 bus 1 0 Υ ΔΕ Line 1-3 Line 1-2 G₂ Line 2-3 bus 2 Da Figure 05a bus 3 Table Q5a T₂ KEY YE my 1000 MVA, 15 kV, X₁-X₂-0.18 p.u., Xo = 0.07, p.u. 1000 MVA, 15 kV, X₁-X2-0.20 p.u., Xo = 0.10, p.u. 500 MVA, 13.8 kV, X₁-X₂-0.15 p.u., Xo = 0.05, p.u. X₂ = 0.05 p.u. 750 MVA, 13.8 kV, X₁-0.3 p.u., X₂-0.4 p.u., Xo = 0.1, p.u. 1000 MVA, 15 kV (A) / 765 kV (Y), XTI = 0.10 p.u. 1000 MVA, 15 kV (A)/ 765 kV (Y), XT2 = 0.10 p.u. 500MVA, 15 kV (Y) / 765 kV (Y), XT3 = 0.12 p.u. 750 MVA, 15 kV (Y)/765 kV (Y), XT4 = 0.11 p.u. Χ = 50 Ω, Χρ = 150 Ω. X = 40 Ω, X = 100 Ω. Χρ = 40 Ω, Χρ = 100 Ω.
Introductory Circuit Analysis (13th Edition)
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Publisher:Robert L. Boylestad
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Three-segment transformers are a type of transformer used to transform voltages of electrical systems into three ranges. Two type transformers are shell-type transformer and core type transformer. In brief, it could be described because of the exquisite kinds of configurations.
Transformer
Ever since electricity has been created, people have started using it in its entirety. We see many types of Transformers in the neighborhoods. Some are smaller in size and some are very large. They are used according to their requirements. Many of us have seen the electrical transformer but they do not know what work they are engaged in.
Question
Transcribed Image Text:Q5
The single-line diagram of a three-phase power system is shown in Figure Q5a, with
equipment ratings given in Table Q5a.
(a)
(b)
G₁
G₂
G3
G4
T₁
T₂
T3
TA
Draw the zero, positive and negative-sequence reactance diagrams using
1000 MVA, 765 kV base in the zone of Line 1-2, neglect the (A-Y)
transformer phase shifts.
Calculate the short circuit current as a result of three-phase bolted fault
occurred at bus 1.
Line 1-2
Line 1-3
Line 2-3
bus 1
0
Υ ΔΥ
Line 1-3
Line 1-2
G₂
Line 2-3
bus 2
Da
Figure 05a
bus 3
Table Q5a
T₂
KEY
YE
my
1000 MVA, 15 kV, X₁-X₂-0.18 p.u., Xo = 0.07, p.u.
1000 MVA, 15 kV, X₁-X₂-0.20 p.u., Xo = 0.10, p.u.
500 MVA, 13.8 kV, X₁-X₂-0.15 p.u., Xo = 0.05, p.u. X₂ = 0.05 p.u.
750 MVA, 13.8 kV, X₁-0.3 p.u., X₂-0.4 p.u., Xo = 0.1, p.u.
1000 MVA, 15 kV (A) / 765 kV (Y), XTI = 0.10 p.u.
1000 MVA, 15 kV (A)/ 765 kV (Y), XT2 = 0.10 p.u.
500MVA, 15 kV (Y) / 765 kV (Y), XT3 = 0.12 p.u.
750 MVA, 15 kV (Y)/765 kV (Y), XT4 = 0.11 p.u.
Χ = 50 Ω, X = 150 Ω.
Χ = 40 Ω, Χρ = 100 Ω.
Χρ= 40 Ω, Χρ = 100 Ω.
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