3.9. A 400-MVA, 240-kV/24-KV, three-phase Y-A transformer has an equivalent series impedance of 1.2 + j6 N per phase referred to the high-voltage side. The transformer is supplying a three-phase load of 400-MVA, 0.8 power factor lagging at a terminal voltage of 24 kV (line to line) on its low-voltage side. The primary is supplied from a feeder with an impedance of 0.6 + j1.2 N per phase. Deter- mine the line-to-line voltage at the high-voltage teminals of the transformer and the sending-end of the feeder. The per phase equivalent circuit referred to the primary is is shown in Figure 25. The load complex power is Z¡ = 0.6 + j1.2 Zel = 1.2 + j6 %3D Vs V1 V, = 138.564 kV %3D

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Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Solve Problem 3.9 with the same given data except that the
connection is Delta-Wye

3.9. A 400-MVA, 240-kV/24-KV, three-phase Y-A transformer has an equivalent
series impedance of 1.2 + j6 N per phase referred to the high-voltage side. The
transformer is supplying a three-phase load of 400-MVA, 0.8 power factor lagging
at a terminal voltage of 24 kV (line to line) on its low-voltage side. The primary
is supplied from a feeder with an impedance of 0.6 + j1.2 N per phase. Deter-
mine the line-to-line voltage at the high-voltage teminals of the transformer and
the sending-end of the feeder.
The per phase equivalent circuit referred to the primary is is shown in Figure 25.
The load complex power is
Zf = 0.6+ j1.2
Zel = 1.2 + j6
wwm
Vs
V1
V, = 138.564 kV
%3D
Transcribed Image Text:3.9. A 400-MVA, 240-kV/24-KV, three-phase Y-A transformer has an equivalent series impedance of 1.2 + j6 N per phase referred to the high-voltage side. The transformer is supplying a three-phase load of 400-MVA, 0.8 power factor lagging at a terminal voltage of 24 kV (line to line) on its low-voltage side. The primary is supplied from a feeder with an impedance of 0.6 + j1.2 N per phase. Deter- mine the line-to-line voltage at the high-voltage teminals of the transformer and the sending-end of the feeder. The per phase equivalent circuit referred to the primary is is shown in Figure 25. The load complex power is Zf = 0.6+ j1.2 Zel = 1.2 + j6 wwm Vs V1 V, = 138.564 kV %3D
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