b) A fault occurs at bus 2 of the network shown in Figure Q3. Pre-fault nodalvoltages throughout the network are of 1 p.u. and the impedance of theelectric arc is neglected. Sequence impedance parameters of the generator,transmission lines, and transformer are given in Figure Q3, where X and Y arethe last two digits of your student number.JX20 /0.1X p.u.jXa2) 0.1X p.u.JX20 j0.2Y p.u.V,= 120° p.u. V, 120° p.u.V, 120° p.u.jX4-70.2X p.u.jX2 j0.2X p.u.jX o 0.2Y p.u.jXncay J0.25 p.u.jXna J0.25 p.u. 3jXno0.3 p.u.jXTu) /0.2Y p.u.jXra j0.2Y p.u.- j0.2Y p.u.Xp-10.1X p.u.jXa j0.1X p.u.jXp0)- j0.05 p.u.0Figure Q3. Circuit for problem 3b).For example, if your student number is c1700123, then:jXac1) = j0.22 p.u., jXac2) = j0.22 p.u., and jXaco) = j0.23 p. u.X-2Y=8(iv) Determine the short-circuit fault current for the case when a phase-to-phase fault occurs at bus 2.

Answered: Image /qna-images/answer/4c9b19b6-6e77-470b-b5eb-97e4f49ffdb1.jpg

b) A fault occurs at bus 2 of the network shown in Figure Q3. Pre-fault nodal voltages throughout the network are of 1 p.u. and the impedance of the electric arc is neglected. Sequence impedance parameters of the generator, transmission lines, and transformer are given in Figure Q3, where X and Y are the last two digits of your student number. jXa0) J0.1X p.u. jXaa-j0.1X p.u. jX 20 j0.2Y p.u. !3! %3D V = 120° p.u. V 120° p.u. V,-120° p.u. jXa)= j0.2X p.u. JX42-J0.2X p.u. JX40 J0.2Y p.u. !! jXaa)= j0.25 p.u.. A Ma- 70.25 p.u. 3 jXno-J0.3 p.u. %3! jXr j0.2Y p.u. jXra /0.2Y p.u. jXro /0.2Y p.u. jX- /0.1X p.u. jXe= j0.1X p.u. X0) = 10.05 p.u. 0 %3D %3D 0. Figure Q3. Circuit for problem 3b). For example, if your student number is c1700123, then: jXa(1) = j0.22 p. u., jXa(2) = j0.22 p.u., and jXaco)= j0.23 p.u. %3D %3D X=2 Y=8 (iv) Determine the short-circuit fault current for the case when a phase-to- phase fault occurs at bus 2.

b) A fault occurs at bus 2 of the network shown in Figure Q3. Pre-fault nodal voltages throughout the network are of 1 p.u. and the impedance of the electric arc is neglected. Sequence impedance parameters of the generator, transmission lines, and transformer are given in Figure Q3, where X and Y are the last two digits of your student number. jXa0) J0.1X p.u. jXaa-j0.1X p.u. jX 20 j0.2Y p.u. !3! %3D V = 120° p.u. V 120° p.u. V,-120° p.u. jXa)= j0.2X p.u. JX42-J0.2X p.u. JX40 J0.2Y p.u. !! jXaa)= j0.25 p.u.. A Ma- 70.25 p.u. 3 jXno-J0.3 p.u. %3! jXr j0.2Y p.u. jXra /0.2Y p.u. jXro /0.2Y p.u. jX- /0.1X p.u. jXe= j0.1X p.u. X0) = 10.05 p.u. 0 %3D %3D 0. Figure Q3. Circuit for problem 3b). For example, if your student number is c1700123, then: jXa(1) = j0.22 p. u., jXa(2) = j0.22 p.u., and jXaco)= j0.23 p.u. %3D %3D X=2 Y=8 (iv) Determine the short-circuit fault current for the case when a phase-to- phase fault occurs at bus 2.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Concept explainers

Single Phase Transformer

A single-phase transformer is a type of power transformer. It is an electrical device that accepts converts the single phase alternating power into single phase alternating power. In this power conversion the voltage is stepped up or down. If the voltage is stepped up, the current will be stepped down and if the voltage is stepped down, the current will be stepped up.

Question

b) A fault occurs at bus 2 of the network shown in Figure Q3. Pre-fault nodal
voltages throughout the network are of 1 p.u. and the impedance of the
electric arc is neglected. Sequence impedance parameters of the generator,
transmission lines, and transformer are given in Figure Q3, where X and Y are
the last two digits of your student number.
JX20 /0.1X p.u.
jXa2) 0.1X p.u.
JX20 j0.2Y p.u.
V,= 120° p.u. V, 120° p.u.
V, 120° p.u.
jX4-70.2X p.u.
jX2 j0.2X p.u.
jX o 0.2Y p.u.
jXncay J0.25 p.u.
jXna J0.25 p.u. 3
jXno0.3 p.u.
jXTu) /0.2Y p.u.
jXra j0.2Y p.u.
- j0.2Y p.u.
Xp-10.1X p.u.
jXa j0.1X p.u.
jXp0)- j0.05 p.u.
0
Figure Q3. Circuit for problem 3b).
For example, if your student number is c1700123, then:
jXac1) = j0.22 p.u., jXac2) = j0.22 p.u., and jXaco) = j0.23 p. u.
X-2
Y=8
(iv) Determine the short-circuit fault current for the case when a phase-to-
phase fault occurs at bus 2.

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