Explain why you chose this mutation. Begin by transcribing and translating BOTH the normal and abnormal DNA sequences. The genetic code below is for your reference. SECOND BASE OF CODON כ FIRST BASE OF CODON O THIRD BASE OF CODON SCAGUCAGUGAGUCAG UUU UUC UCU UAU UGU Phenylalanine (F) Tyrosine (Y) Cysteine (C) UCC UAC UGC Serine (S) UUA UUG Leucine (L) UCA UCG_ UAA UGA Stop codon -Stop codon UAG UGG -Tryptophan (W) CUU CUC CCU CAU CGU Histidine (H) CCC CAC CGC -Leucine (L) Proline (P) CUA CCA CAA CUG CCG CAG-Glutamine (Q) -Arginine (R) CGA CGG AUU ACU AAU AGU AUC Isoleucine (1) Asparagine (N) ACC AAC Threonine (T) AUA ACA AAA Methionine (M) Lysine (K) AUG ACG Start codon AAG AGC-Serine (S) -Arginine (R) AGA AGG GUU GCU GAU GUC GUA GUG GCC Valine (V) -Alanine (A) GCA GCG GAC GAA GAG Aspartic acid (D) GGU Glutamic acid (E) GGC GGA GGG Glycine (G) In order to provide a complete answer to the question stated above, fill in the mRNA bases and amino acid sequences by using the Genetic Code shown in the chart above. Normal sequence: DNA: mRNA: Amino Acids: Abnormal sequence: DNA: mRNA: Amino Acids: GGA CTC CTC GGA CAC CTC Claim: Answer Question • What type of mutation occurred with the hemoglobin?

Biology: The Dynamic Science (MindTap Course List)
4th Edition
ISBN:9781305389892
Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan
Publisher:Peter J. Russell, Paul E. Hertz, Beverly McMillan
Chapter19: Genomes And Proteomes
Section: Chapter Questions
Problem 1ITD: Below is a sequence of 540 bases from a genome. What information would you use to find the...
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Explain why you chose this mutation. Begin by transcribing and translating BOTH the
normal and abnormal DNA sequences. The genetic code below is for your reference.
SECOND BASE OF CODON
כ
FIRST BASE OF CODON
O
THIRD BASE OF CODON
SCAGUCAGUGAGUCAG
UUU
UUC
UCU
UAU
UGU
Phenylalanine
(F)
Tyrosine (Y)
Cysteine (C)
UCC
UAC
UGC
Serine (S)
UUA
UUG
Leucine (L)
UCA
UCG_
UAA
UGA
Stop codon
-Stop codon
UAG
UGG -Tryptophan (W)
CUU
CUC
CCU
CAU
CGU
Histidine (H)
CCC
CAC
CGC
-Leucine (L)
Proline (P)
CUA
CCA
CAA
CUG
CCG
CAG-Glutamine (Q)
-Arginine (R)
CGA
CGG
AUU
ACU
AAU
AGU
AUC
Isoleucine (1)
Asparagine (N)
ACC
AAC
Threonine (T)
AUA
ACA
AAA
Methionine (M)
Lysine (K)
AUG
ACG
Start codon
AAG
AGC-Serine (S)
-Arginine (R)
AGA
AGG
GUU
GCU
GAU
GUC
GUA
GUG
GCC
Valine (V)
-Alanine (A)
GCA
GCG
GAC
GAA
GAG
Aspartic acid
(D)
GGU
Glutamic acid
(E)
GGC
GGA
GGG
Glycine (G)
In order to provide a complete answer to the question stated above, fill in the mRNA bases
and amino acid sequences by using the Genetic Code shown in the chart above.
Normal sequence:
DNA:
mRNA:
Amino Acids:
Abnormal sequence:
DNA:
mRNA:
Amino Acids:
GGA
CTC
CTC
GGA
CAC
CTC
Claim: Answer Question
• What type of mutation occurred with the hemoglobin?
Transcribed Image Text:Explain why you chose this mutation. Begin by transcribing and translating BOTH the normal and abnormal DNA sequences. The genetic code below is for your reference. SECOND BASE OF CODON כ FIRST BASE OF CODON O THIRD BASE OF CODON SCAGUCAGUGAGUCAG UUU UUC UCU UAU UGU Phenylalanine (F) Tyrosine (Y) Cysteine (C) UCC UAC UGC Serine (S) UUA UUG Leucine (L) UCA UCG_ UAA UGA Stop codon -Stop codon UAG UGG -Tryptophan (W) CUU CUC CCU CAU CGU Histidine (H) CCC CAC CGC -Leucine (L) Proline (P) CUA CCA CAA CUG CCG CAG-Glutamine (Q) -Arginine (R) CGA CGG AUU ACU AAU AGU AUC Isoleucine (1) Asparagine (N) ACC AAC Threonine (T) AUA ACA AAA Methionine (M) Lysine (K) AUG ACG Start codon AAG AGC-Serine (S) -Arginine (R) AGA AGG GUU GCU GAU GUC GUA GUG GCC Valine (V) -Alanine (A) GCA GCG GAC GAA GAG Aspartic acid (D) GGU Glutamic acid (E) GGC GGA GGG Glycine (G) In order to provide a complete answer to the question stated above, fill in the mRNA bases and amino acid sequences by using the Genetic Code shown in the chart above. Normal sequence: DNA: mRNA: Amino Acids: Abnormal sequence: DNA: mRNA: Amino Acids: GGA CTC CTC GGA CAC CTC Claim: Answer Question • What type of mutation occurred with the hemoglobin?
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