Based on the Hill Plot below, this protein-ligand interaction displayslogY1-Y52.50-2.5-2.5nH<10log[L]Uncooperative bindingnH>12.5Binding that obeys the Law of Mass ActionNegative cooperativity5

Hill equation developed by Archibald Hill in 1910 quantitatively describing cooperative ligand…

Answered: Based on the Hill Plot below, this…

Biochemistry

9th Edition

ISBN:9781319114671

Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.

Chapter1: Biochemistry: An Evolving Science

Section: Chapter Questions

Problem 1P

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Give Explanation Detailed Solution of sub parts..(no need handwritten answer)
The Graph below shows the binding curves of two proteins (A and B) for the same ligand (L). Use this Graph and determine the dissociation constant, K, for both proteins. Which protein (A or B) has a greater affinity for ligand L? Which of the two proteins would be more easily inhibited by an antagonist? 1.0 Y 0.5 2 A 4 6 B 8 [L] (μM) 10 12 14 16
Sketch a plot that shows a typical binding curve for the interactions between a ligand, L (in terms of concentration), and a protein, P.
In the Bradford protein determination, the color of a dye changes from brown to blue when it binds to a protein. The intensity of blue color (measured by absorbance of light at a wavelength of 595nm) is proportional to protein concentration. Protein (ug) Absorbance at 595nm 0.00 0.466 9.36 0.676 18.72 0.883 28.08 1.086 37.44 1.280 Use Excel to determine the equation of the line in the format of y = mx + b. (I tried y=0.0218x+0.4706 and it was wrong) Using the calibration curve for the Bradford protein determination in the previous question, determine the number of micrograms of protein in an unknown if it gave an absorbance of 0.973. I tried 23.505 and it was wrong
I’m having hard time drawing the graph to answer these questions can you show how to approach them?
In a molecular disease of hemoglobin, Hemoglobin Rainier, Tyr 145β is replaced by Cys, which forms a disulfide bond with another Cysresidue in the same subunit. This prevents the formation of ion pairs that normally stabilize the T state. How does hemoglobin Rainier differ from normal hemoglobin with respect to the Hill coefficient
The bioactive conformation of lead compound I was confirmed when a crystal structure was r. obtained showing I bound to its target (an enzyme). Ala-312 in His-42 Val-307 CI Asp-305 Phe-47 H. Ser-254 I bound to target protein Using the information shown above, draw the structure of an analog that you predict will exhibit improved binding to the target. Explain how you arrived at this proposed analog structure.
For a binding protein to show positive cooperativity…. Choice 1 of 4:the protein must be able to adopt at least 2 different conformations each with different affinities for the ligand Choice 2 of 4:the protein must be able to bind to at least 2 different types of ligand Choice 3 of 4:the protein must bind to one molecule of ligand fast and one molecule of ligand slowly Choice 4 of 4:the Kd must be in the micromolar range
What is the isoelectric point of the following peptide molecule? Asp-His-Glu-Gly-Lys-Tyr-Leu-Phe-Arg-Ser-Cys Relevant pKa values are; 2.2, 3.8, 4.3, 6.0, 8.3, 9.8, 10.1, 10.5, 12.5 and 13.1 3.0 9.1 7.2 5.2 4.1 ONLY one correct answer
1.0.1 mL of a protein solution of concentration of 11 mg/mL was diluted to a total volume of 4.0 mL with water (i.e. 0.1 mL of the solution was added to 3.9 mL of water). 2 mL of this solution was then mixed with 18 mL of water. What is the concentration of the diluted protein solution? Space to show your workings:
17 Peptides can be separated using an ion-exchange column based on their isoelectric (pl) values. At which pH values would two different peptides, one with a pl of 5.6 and the other with a pl of 8.9, bind to a cation- and anion-exchange column? Each peptide may be capable of binding to each column at more than one pH value. anion-exchange column at pH = 3.5 cation-exchange column at Answer Bank pH = 3.5 peptide A pf = 5.6 peptide A peptide B pl = 89 pl= 5.6 peptide B pl = 8,9 pH= 7.4 pH = 7,4 peptide A pl= 5.6 peptide A pl= 5.6 pH = 10.1 pH = 10.1 peptide B V oppdad pl=56 pl= 89
A one-to-one protein (P)-ligand (L) complexation (P + L PL) has a dissociation equilibrium constant (Kd) value of 100 nM at 25°C, and the Kd remains the same at 37°C. 1) What is AS of binding at 25°C? Assume ACp of the binding is 0 over the temperature range. AS = 1.34E2 kJ/(mol*K) (note the unit!!) (sig. fig =3) 2) What is the concentration of the PL complex formed at equilibrium when you mix 0.20 uM (microM) of Protein and 1.0 uM of Ligand together at 37°C? PL at equilibrium = 8.1E-1 uM (note the unit!!) (sig. fig =2)

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Based on the Hill Plot below, this protein-ligand interaction displays log Y 1-Y 2.5 0 -2.5 -2.5 Uncooperative binding nH<1 0 log[L] OnH>1 Binding that obeys the Law of Mass Action 2.5 Negative cooperativity 5