(a) The diagram below on the right-hand side illustrates the polar Asp(a94)... Asn (102) interaction that stabilizes the R (oxy) conformation of human hemoglobin (HbA). This sidechain inter- action underlies the allosteric, structural transition of hemoglobin and helps to maintain its tetramer structure. In the table below the properties of several mutants of hemoglobin involving the a94 position are compared at pH ~ 7.4.
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- Classify the symmetrical arrangement ofthe subunits (e.g., C2 , C3 , D 2 , helical, icosahedral). 1. Proteobacterial nitrite sensor (3PNS):2. Pseudomonad oligosaccharide receptor (7POR):3. Adenoviral structural protein (8ASP)The figure shows interaction of various amino acids (Phe, Arg, and Asn) present in Hb with 2,3-DPG. The side chains of these amino acids and 2,3-DPG interactions are circled in red. HO Но Phe HN Asn H2N NH Arg You identify a mutant version of the globin chain where the Arg in circle 2 is replaced with aspartic acid in a patient. Would the Hb protein in this patient be able to transport oxygen even in the presence of 2,3-DPG? ASPARTIC ACID (asp) No, because the mutant Hb version will bind 2,3 DPG, and not oxygen Yes, because the mutant Hb version will bind 2,3 DPG, and not oxygen Yes, because the mutant Hb version will bind oxygen and not 2,3 DPGThe peptlde bradykinln is a nonapeptlde. Give the name of the peptide (shown below) by namlng the amlno aclds from the N-terminal to the C- terminal. Use the long name, the 3-letter abbreviation and the 1-letter abbreviation. What is the pl of this peptide? Name Compositon Fxnction LOcalizatio Bradykinl Inflammatio Different n and H N vasodilation Cells HNH n Animal H. HNH H NH он HN N HO
- I. A protein, X, was Isolated from a pathogenlc mlcroorganism. The proteln Is a vlrulence factor whose path0genlclty lies In a heptapeptide of unknown sequence. After trypsin cleavage of the heptapeptide from protein X, the peptlde's compOsition and sequence was determined. The fOllowing were the results of the sequenclng process: 1. When the peptide was treated with dinitrofluorobenzene (DNFB), DNP-asp and a mixture of amino acids were produced. 2. When the same Intact peptide was treated with streptococcal protease, a pentapeptide of composition asp, asN, cys, gly and ser and 2 amlno acids were released. 3. When the heptapeptlde was also treated with hydrOxylamine HCI, a tripeptide and a tetrapeptide were obtained. The C-terminal amino acid of the tripeptide was asN. 1) What is the sequence of the heptapeptide if it is composed of cys, asp, lys, asN, gly and ser only? 2) What is the pl of the heptapeptide?Certain individuals with mild forms ofβ-thalassemia produce, in addition to normal adulthemoglobin with two α chains and two β chains,lower levels of an unusual, so-called Leporehemoglobin with two α chains and two chains ineach of which the N-terminal half comes from anormal δ chain and the C-terminal half comesfrom a normal β chain. Certain other individualswho are asymptomatic produce a different, unusualanti-Lepore hemoglobin that contains two α chainsand two chains in which the N-terminal half comesfrom a normal β chain and the C-terminal halfcomes from a normal δ chain.a. Describe an event that could give rise to bothLepore and anti-Lepore hemoglobins.b. Are the mildly thalassemic individuals with Leporehemoglobin homozygotes or heterozygotes for theunusual allele?c. Why might these mildly thalassemic people produce less Lepore hemoglobin than normal adulthemoglobin?9. The T conformation of the hemoglobin tetramer is stabilized (in part) by a salt linkage between the side chain of the lysine residue at position 40 in the a-chain of one aß dimer and the C-terminal carboxylate group of the ß-chain of the opposing aß dimer. Draw a diagram of this salt linkage (show complete side chains).
- In a molecular disease of hemoglobin, Hemoglobin Rainier, Tyr 145β is replaced by Cys, which forms a disulfide bond with another Cysresidue in the same subunit. This prevents the formation of ion pairs that normally stabilize the T state. How does hemoglobin Rainier differ from normal hemoglobin with respect to the Hill coefficientThe following amino acids that are often found inside globulin molecules are () A, Tyr B, Phe C, Asn D, Glu True of false 1. In the de novo synthesis of purine nucleotides and pyrimidine nucleotides, base rings are first synthesized and then corresponding nucleotides are formed with phosphoribose. () 2. Transcription is the process of transferring genetic information from DNA to RNA. DNA is synthesized under the catalysis of RNA polymerase, and the direction of synthesis is from the 5 'end to the 3' end. () 3. The change of protein conformation is caused by the breaking of covalent bonds within the molecule. () 4. In very high and very low pH solutions, amino acids exist mainly in non-ionic form. () 5. The active center of an enzyme usually consists of several amino acid residues adjacent to each other in the primary structure. ()2B. S. aureus hemolysin B attacks the RBC cell membrane by hydrolyzing the sphingomyelin headgroup: ОН HN .R hemolysin B cuts this bond i) Draw a plausible mechanism of hydrolysis for this lipid headgroup. Let B- and BH be general base and general acid. 00-P-O LOR2 OR, ii) Why is this damaging to the overall membrane architecture of the RBC?
- Based on the structure of CBB G-250, explain why it can bind to proteins having basic and hydrophobic amino acid residues.In oxygenated hemoglobin, pKa 5 6.6 forthe histidines at position 146 on the -chain. In deoxygenated hemoglobin, the pKa of these residues is 8.2. How can this piece ofinformation be correlated with the Bohr effect?The a and ß subunits of hemoglobin bear a remarkable structural similarity to myoglobin. However, certain residues that are hydrophilic in myoglobin are hydrophobic in the subunits of hemoglobin. Why might this be the case? O Hydrophilic residues on the surface of myoglobin form ionic interactions with similar regions on other myoglobin molecules. O Hydrophobic residues on the surface of hemoglobin subunits interact with similar regions on the other subunits through van der Waals interactions. Hemoglobin forms long, extended structures that feature repeated sequences, whereas myoglobin forms globular structures. Myoglobin is a water-soluble protein, whereas hemoglobin is found in the hydrophobic environment of membranes.