As a graduate student, you join a lab and you are looking through some old notebooks. You find a linkage map someone has drawn. G----15 mu-- -T----10 mu-------B If you plan to complete a test cross with a GtB/gTb male, A) What are all of the expected progeny genotypes? B.) How many of each genotype would you expect if you collected 1000 progeny?

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---

### Understanding Genetic Linkage Maps and Test Crosses

#### Introduction
As a graduate student, you join a lab and you are looking through some old notebooks. You find a linkage map someone has drawn:

```
G-------15 mu-------T-------10 mu-------B
```

#### Genetic Linkage Map Explanation
- **G, T, B**: These are genes.
- **15 mu, 10 mu**: These represent map units (mu), indicating the distance between the genes. One map unit usually correlates to a 1% recombination frequency between genes.

If you plan to complete a test cross with a GtB/gTb male:

A) **What are all of the expected progeny genotypes?**
  
B) **How many of each genotype would you expect if you collected 1000 progeny?**

#### Detailed Analysis

- **Parental Genotypes**: GtB and gTb.
- **Expected Progeny Genotypes**: Given the distances, you will get recombinants and non-recombinants. Use the map units to predict the frequencies:

  1. **Non-recombinants** (GtB and gTb)
  2. **Single Crossovers** (at two regions: G-T and T-B)
  3. **Double Crossovers** 

- **Expected Genotype Rates Based on Map Units**:
  - **G-T**: 15% single crossover.
  - **T-B**: 10% single crossover.
  - **Double crossover**: Multiply the single crossover frequencies across two regions (0.15 * 0.10 = 0.015 or 1.5%).

#### Calculation for 1000 Progeny:

- Total crossovers in G-T = 15% -> 150 progeny
- Total crossovers in T-B = 10% -> 100 progeny
- Double crossovers = 1.5% -> 15 progeny

Split these crossovers equally and account for both single and double crossovers.

Parental/Non-recombinant Types:
- GtB (42.5%) -> 425
- gTb (42.5%) -> 425

Single Crossovers:
- Gtb (7.5%) -> 75
- gTB (7.5%) -> 75

Double Crossovers:
- gTB (1.5%) ->
Transcribed Image Text:--- ### Understanding Genetic Linkage Maps and Test Crosses #### Introduction As a graduate student, you join a lab and you are looking through some old notebooks. You find a linkage map someone has drawn: ``` G-------15 mu-------T-------10 mu-------B ``` #### Genetic Linkage Map Explanation - **G, T, B**: These are genes. - **15 mu, 10 mu**: These represent map units (mu), indicating the distance between the genes. One map unit usually correlates to a 1% recombination frequency between genes. If you plan to complete a test cross with a GtB/gTb male: A) **What are all of the expected progeny genotypes?** B) **How many of each genotype would you expect if you collected 1000 progeny?** #### Detailed Analysis - **Parental Genotypes**: GtB and gTb. - **Expected Progeny Genotypes**: Given the distances, you will get recombinants and non-recombinants. Use the map units to predict the frequencies: 1. **Non-recombinants** (GtB and gTb) 2. **Single Crossovers** (at two regions: G-T and T-B) 3. **Double Crossovers** - **Expected Genotype Rates Based on Map Units**: - **G-T**: 15% single crossover. - **T-B**: 10% single crossover. - **Double crossover**: Multiply the single crossover frequencies across two regions (0.15 * 0.10 = 0.015 or 1.5%). #### Calculation for 1000 Progeny: - Total crossovers in G-T = 15% -> 150 progeny - Total crossovers in T-B = 10% -> 100 progeny - Double crossovers = 1.5% -> 15 progeny Split these crossovers equally and account for both single and double crossovers. Parental/Non-recombinant Types: - GtB (42.5%) -> 425 - gTb (42.5%) -> 425 Single Crossovers: - Gtb (7.5%) -> 75 - gTB (7.5%) -> 75 Double Crossovers: - gTB (1.5%) ->
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