An electrical engineer wishes to compare the mean lifetimes of two types of transistors in an application involving high-temperatureperformance. A sample of 60 transistors of type A were tested and were found to have a mean lifetime of 1827 hours and a standarddeviation of 174 hours. A sample of 180 transistors of type B were tested and were found to have a mean lifetime of 1658 hours and astandard deviation of 231 hours. Let ux represent the population mean for transistors of type A and µy represent the populationmean for transistors of type B. Find a 95% confidence interval for the difference uy – µy . Round the answers to three decimalplaces.The 95% confidence interval is

Confidence interval: Here, the sample sizes n1and n2 are 60 and 180 respectively. The critical value…

Answered: An electrical engineer wishes to…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Two suppliers manufacture a plastic gear used in a laser printer. The impact strength of these gears measured in foot-pounds is an important characteristic. A random sample of 10 gears from supplier 1 results in x1 = 290 and s1 = 12, and another random sample of 16 gears from the second supplier results in x2 = 310 and s2 = 22. Do the data support the claim that the mean impact strength of gears from supplier 2 is at least 10 foot-pounds higher than that of supplier 1, find the tcalc value? Please report your answer upto 3 decimal places.
The standard z-value of an arbitrary 16-unit sample from the normal-class population with a mean of 60 and a variance of 100 is 2.0.
A physical therapist wanted to know whether the mean step pulse of men was less than the mean step pulse of women. She randomly selected 54 men and 70 women to participate in the study. Each subject was required to step up and down a 6-inch platform. The pulse of each subject was then recorded. The following results were obtained. Two sample T for Men vs Women N Mean StDev SE Mean Men Women 98% CI for mu Men - mu Women (- 12.20, - 1.00) T-Test mu Men = mu Women (vs H2 O C. Ho: H1 = H2; Ha: H1 #H2 (b) Identify the P-value and state the researcher's conclusion if the level of significance was a = 0.01. What is the P-value? P-value =
A company manufactures tonnis balls. When its tennis balls are dropped onto a concrete surface from a height of 100 inches, the company wants the mean height the balls bounce upward to be 54.7 inches. This average is maintained by periodically testing random samples of 25 tennis balls. If the t-value falls between -to ak and t as then the company will be satisfied that it is manufacturing acceptable tennis balls. A sample of 25 balls is randomly selected and tested. The mean bounce height of the sample is 56.8 inches and the standard deviation is 0.25 inch. Assume the bounce heights are approximately normally distributed. Is the company making acceptable tennis balls? Find -th os and to 96- -to.96 = 0.96 = (Round to three decimal places as needed.)
11.3.1
Suppose that a refrigeration process at Coolfood, Ltd. has a normally distributed output with a mean of 27 and a variance of 1.10. If the specifications are 24±3.24, compute Cp.
During the COVID-19 pandemic, drive-up grocery delivery became very popular with customers. Two US retailers that provide this service are Target and Walmart. Many shoppers prefer to order from only one store to save time, but they wonder if they are spending more money shopping at one store rather than both. The data file Snacks has the prices for 20 identical snack items sold at both retailers in Mankato, Minnesota. Assume that µd is the mean difference (Target - Walmart) in the price of the items. Using α = .05, determine whether or not the price of these grocery items differed significantly. Perform your analysis using MegaStat. Download: Snacks a. What type of analysis should you use to analyze this data? Explain the reason for your choice. b. State the hypotheses for this analysis. c. Calculate the degrees of freedom for this analysis. d. State the Decision Rule for this analysis. e. Perform the analysis and identify the mean price of the Target items, the mean price of the…
A study was conducted to examine the difference between the average cholesterol levels in the blood of men and females. It can be assumed that cholesterol levels follow a normal distribution in both populations and that the distribution in the populations is similar (e. Assume that cholesterol levels follow a normal distribution in both populations with similar variances). An equal number of measurements were made on men and women. The results were entered into R and the R code and output can be seen below: t.test(kol$mael-kol$kyn,var.equal = T) %3D Two Sample t-test data: kol$mael by kol$kyn t = 5.7731, df = 18, p-value alternative hypothesis: true difference in means is not equal to 0 95 percent confidence interval: 15.28775 32.78050 = 0.000018 sample estimates: mean in group Men mean in group women 219.2115 195.1774 1. Which statement is best based on the results of the study? Use a=0.05. a. The P-value is lower than a and therefore can be rejected HO b. The P-value is higher than a…
Show that the mean of a random sample of size n from an exponential population is a minimum variance unbiased estimator of the parameter 0.
Water availability is of prime importance in the life cycle of most reptiles. To determine the rate of evaporative water loss of a certain species of lizard at a particular desert site, 34 such lizards were randomly collected, weighed and placed under the appropriate experimental conditions. After 24 hours, each lizard was removed, weighed, and its total water loss was calculated by subtracting its body weight after treatment from its initial body weight. Previous studies have shown that the relative frequency distribution of water loss for this species of lizard has a mean of 3.1 grams and a s.d. of 0.8 gram. a) What is the approximate sampling distribution of x , the mean water loss of the 34 lizards
The World Bank Group suggests that a minimum of 6 GB of internet data per month per user is needed for online activities to ensure better life quality (accessing news, health and educational information, social media, and other online activities). Considering the costs and poor internet connectivity, a researcher wanted to estimate the mean monthly data consumption of students in rural areas. She calculated a mean of 3.4 GB of monthly data from a random sample of 25 students. • Sub ● daia (GB) are normally disipe eviation of Complete the statement: If we consider all possible samples of the same size and a 95% confidence interval is obtained from each sample, ther ✓ [Select] Neither A nor B A. 95% of these intervals would contain 3.4 GB. Both A and B B. 5% of these intervals would not contain the true mean monthly data of students
Tardigrades, or water bears, are a type of micro-animal famous for their resilience. In examining the effects of radiation on arganisms, an expert claimed that the amount of gamma radiation needed to sterilize a colany of tardigrades no longer has a mean of 1200 Gy (grays). (For comparison, humans cannot withstand more than 10 Gy.) A study was conducted on a sample of 21 randomly selected tardigrade colonies, finding that the amount of gamma radiation needed to sterilize a colony had a sample mean af 1225 Gy, with a sample standard deviation of 65 Gy. Assume that the population of amounts of gamma radiation needed to sterilize a colony of tardigrades is approximately normally distributed. Complete the parts below to perform a hypothesis test to see if there is enough evidence, at the 0.10 level af significance, to support the claim that H, the mean amount of gamma radiation needed to sterilize a colony of tardigrades, is nat equal to 1200 Gy. (a) State the null hypothesis and the…

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