An experiment is conducted to compare the maximum load capacity in tons (the maximum weight that can be tolerated without breaking) for two alloys A and B. It is known that the two standard deviations in load capacity are equal at 6 tons each. The experiment is conducted on 40 specimens of each alloy (A and B) and the results are XA = 62.5, XB = 58.5, and XA-XB=4. The manufacturers of alloy A are convinced that this evidence shows conclusively that HA > HB and strongly supports the claim that their alloy is superior. Manufacturers of alloy B claim that the experiment could easily have given XA -XB = 4 even if the two population means are equal. Complete parts (a) and (b) below. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. (a) Make an argument that manufacturers of alloy B are wrong. Do it by computing P(XA-XB >4 | HA=HB). P(XA-XB > 4) =
An experiment is conducted to compare the maximum load capacity in tons (the maximum weight that can be tolerated without breaking) for two alloys A and B. It is known that the two standard deviations in load capacity are equal at 6 tons each. The experiment is conducted on 40 specimens of each alloy (A and B) and the results are XA = 62.5, XB = 58.5, and XA-XB=4. The manufacturers of alloy A are convinced that this evidence shows conclusively that HA > HB and strongly supports the claim that their alloy is superior. Manufacturers of alloy B claim that the experiment could easily have given XA -XB = 4 even if the two population means are equal. Complete parts (a) and (b) below. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. (a) Make an argument that manufacturers of alloy B are wrong. Do it by computing P(XA-XB >4 | HA=HB). P(XA-XB > 4) =
MATLAB: An Introduction with Applications
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Author:Amos Gilat
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![An experiment is conducted to compare the maximum load capacity in tons (the maximum weight that can be tolerated
without breaking) for two alloys A and B. It is known that the two standard deviations in load capacity are equal at 6 tons each. The
experiment is conducted on 40 specimens of each alloy (A and B) and the results are XA = 62.5, XB = 58.5, and XA -XB = 4. The
manufacturers of alloy A are convinced that this evidence shows conclusively that μA HB and strongly supports the claim that their
alloy is superior. Manufacturers of alloy B claim that the experiment could easily have given XA -XB = 4 even if the two population
means are equal. Complete parts (a) and (b) below.
Click here to view page 1 of the standard normal distribution table.
Click here to view page 2 of the standard normal distribution table.
(a) Make an argument that manufacturers of alloy B are wrong. Do it by computing P(XA -XB >4 | μA = HB
P(XA-XB > 4) =
4](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F1c30dcb3-aca7-4fbb-bdb2-37223d346cfd%2F2936cff5-aa8c-4d2e-a7c4-0fb1e4ed7d7a%2Fr89gani_processed.jpeg&w=3840&q=75)
Transcribed Image Text:An experiment is conducted to compare the maximum load capacity in tons (the maximum weight that can be tolerated
without breaking) for two alloys A and B. It is known that the two standard deviations in load capacity are equal at 6 tons each. The
experiment is conducted on 40 specimens of each alloy (A and B) and the results are XA = 62.5, XB = 58.5, and XA -XB = 4. The
manufacturers of alloy A are convinced that this evidence shows conclusively that μA HB and strongly supports the claim that their
alloy is superior. Manufacturers of alloy B claim that the experiment could easily have given XA -XB = 4 even if the two population
means are equal. Complete parts (a) and (b) below.
Click here to view page 1 of the standard normal distribution table.
Click here to view page 2 of the standard normal distribution table.
(a) Make an argument that manufacturers of alloy B are wrong. Do it by computing P(XA -XB >4 | μA = HB
P(XA-XB > 4) =
4
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