An experiment is conducted to compare the maximum load capacity in tons (the maximum weight that can be tolerated without breaking) for two alloys A and B. It is known that the two standard deviations in load capacity are equal at 6 tons each. The experiment is conducted on 40 specimens of each alloy (A and B) and the results are XA = 62.5, XB = 58.5, and XA-XB=4. The manufacturers of alloy A are convinced that this evidence shows conclusively that HA > HB and strongly supports the claim that their alloy is superior. Manufacturers of alloy B claim that the experiment could easily have given XA -XB = 4 even if the two population means are equal. Complete parts (a) and (b) below. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. (a) Make an argument that manufacturers of alloy B are wrong. Do it by computing P(XA-XB >4 | HA=HB). P(XA-XB > 4) =
An experiment is conducted to compare the maximum load capacity in tons (the maximum weight that can be tolerated without breaking) for two alloys A and B. It is known that the two standard deviations in load capacity are equal at 6 tons each. The experiment is conducted on 40 specimens of each alloy (A and B) and the results are XA = 62.5, XB = 58.5, and XA-XB=4. The manufacturers of alloy A are convinced that this evidence shows conclusively that HA > HB and strongly supports the claim that their alloy is superior. Manufacturers of alloy B claim that the experiment could easily have given XA -XB = 4 even if the two population means are equal. Complete parts (a) and (b) below. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. (a) Make an argument that manufacturers of alloy B are wrong. Do it by computing P(XA-XB >4 | HA=HB). P(XA-XB > 4) =
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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