An experiment is conducted to compare the maximum load capacity in tons (the maximum weight that can be toleratedwithout breaking) for two alloys A and B. It is known that the two standard deviations in load capacity are equal at 6 tons each. Theexperiment is conducted on 40 specimens of each alloy (A and B) and the results are XA = 62.5, XB = 58.5, and XA -XB = 4. Themanufacturers of alloy A are convinced that this evidence shows conclusively that μA HB and strongly supports the claim that theiralloy is superior. Manufacturers of alloy B claim that the experiment could easily have given XA -XB = 4 even if the two populationmeans are equal. Complete parts (a) and (b) below.Click here to view page 1 of the standard normal distribution table.Click here to view page 2 of the standard normal distribution table.(a) Make an argument that manufacturers of alloy B are wrong. Do it by computing P(XA -XB >4 | μA = HBP(XA-XB > 4) =4

Sample sizes are: nA=40nB=40 Sample means are: x¯A=62.5x¯B=58.5 So, x¯A-x¯B=4 Population standard…

Answered: An experiment is conducted to compare…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A sample of n = 16 scores is selected from a population with μ = 100 and σ = 32. If the sample mean is M = 104, what is the z-score for this sample mean?
A population has a mean of u = 50 and a standard deviation of a = 10. If 3 points were added to every score in the population, what would be the new values for the mean and standard deviation? O The new mean is u = 47, and the new standard deviation is a = 13. The new mean is u = 47, and the standard deviation is still a = 10. O The new mean is u = 53, and the standard deviation is still o = 10. O The mean is still u = 50, and the new standard deviation is a = 13. If every score in the population were multiplied by 2, what would be the new values for the mean and standard deviation? The new mean is µ = 100, and the new standard deviation is still a = 10. The new mean is u = 52, and the new standard deviation is o = 20. The new mean is u = 100, and the new standard deviation is a = 20. The mean is still u = 50, and the new standard deviation is o = 20.
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A sample of n = 16 scores is obtained from a population with μ = 70 and σ = 20. If the sample mean is M = 80, what is the z -score for the sample mean?
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The ratio of the lengths of the second and the fourth fingers, denoted 2D:4D, is an indicator of the level of prenatal testosterone. It is known that higher prenatal testosterone levels are associated with a lower 2D:4D value. Since testosterone levels are known to be related to behavioural traits, it has been conjectured that certain types of aggressive and dominant behaviours may be associated with lower 2D:4D values. van der Meij et al. (2012) conducted a study that investigated the possible relationship between 2D:4D and so-called "sociable" and "aggressive" dominance. For the study, 84 male students completed two questionnaires, measuring sociable and aggressive dominance respectively, on which high scores related to increased aggression. After some adjustments, a score between 1 and 6 was recorded for each subject on each questionnaire. The participants' hands were scanned and measurements taken, on which a 2D:4D measure could be recorded per subject by averaging the ratio for…

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