EXERCISE 1. A random sample of six steel beams has mean compressive strength of 58.392 psi (pounds per square inch) with a standard deviation of s 648 psi. Test the null hypothesis H, -H = 58,000 psi against the alternative hypothesis H; H> 58,000 psi at 5% level of significance (value for t at 5 degree of freedom and 5% significance level is 2.0157). Here u denotes the population mean. (AMLE, Summer 2000)

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1. A random sample of six steel beams has mean compressive strength of 58.392 psi (pounds per
square inch) with a standard deviation of s = 648 psi. Test the null hypothesis
H, =H = 58,000 psi against the alternative hypothesis H,: H > 58,000 psi at 5% level of significance
(value for t at 5 degree of freedom and 5% significance level is 2.0157). Here µ denotes the population
mean
(A.M.IE., Summer 2000)
Transcribed Image Text:EXERCISE 1. A random sample of six steel beams has mean compressive strength of 58.392 psi (pounds per square inch) with a standard deviation of s = 648 psi. Test the null hypothesis H, =H = 58,000 psi against the alternative hypothesis H,: H > 58,000 psi at 5% level of significance (value for t at 5 degree of freedom and 5% significance level is 2.0157). Here µ denotes the population mean (A.M.IE., Summer 2000)
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