A nutritionist daims that the mean tuna consumption by a person is 3.7 pounds per year. A sample of 80 people shows that the mean tuna consumption by a person is 3.3 pounds per year. Assume the population standard deviation is 1.04 pounds. At a=0.06, can you reject the claim? (a) Identify the null hypothesis and alternative hypothesis. OA Ho: >3.7 H us3.7 O B. Ho: =3.7 H:u#3.7 OC. Ho: u#3.3 H=33 OF. H: us3.7 OD. Ho: us3.3 H:p>3.3 O E. Ho: >3.3 H: us3.3 Hi u> 3.7 (b) Identify the standardized test statistic. z= (Round to two decimal places as needed.) (c) Find the P-value. (Round to three decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. O A. Fail to reject Ho. There is not sufficient evidence to reject the claim that mean tuna consumption is equal to 3.7 pounds. O B. Reject Ho. There is sufficient evidence to reject the claim that mean tuna consumption is equal to 3.7 pounds. O C. Fail to reject Ho. There is sufficient evidence to reject the claim that mean tuna consumption is equal to OD. Reject Ho. There is not sufficient evidence to reject the claim that mean tuna consumption 3.7 pounds. equal to 3.7 pounds.

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A nutritionist claims that the mean tuna consumption by a person is 3.7 pounds per year. A sample of 80 people shows that the mean tuna consumption by a person is 3.3 pounds per year. Assume the population standard
deviation is 1.04 pounds. At a = 0.06, can you reject the claim?
(a) Identify the null hypothesis and alternative hypothesis.
OC. Ho: H#3.3
Hgiµ =3.3
OF. Ho: u53.7
Ha: H> 3.7
OA Ho: H> 3.7
O B. Ho: H=3.7
Hg: u53.7
Ha: u#3.7
O D. Ho: us3.3
O E. Ho: >3.3
Ha:H>3.3
Hiu53.3
(b) Identify the standardized test statistic.
z= (Round to two decimal places as needed.)
(c) Find the P-value.
(Round to three decimal places as needed.)
(d) Decide whether to reject or fail to reject the null hypothesis.
O B. Reject Ho. There is sufficient evidence to reject the claim that mean tuna consumption is equal to 3.7
O A. Fail to reject Hn. There is not sufficient evidence to reject the claim that mean tuna consumption is
pounds.
equal to 3.7 pounds.
O C. Fail to reject Ho. There is sufficient evidence to reject the claim that mean tuna consumption is equal to O D. Reject Ho. There is not sufficient evidence to reject the claim that mean tuna consumption is equal to
3.7 pounds.
3.7 pounds.
O Time Remaining: 00:53:03
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Transcribed Image Text:A nutritionist claims that the mean tuna consumption by a person is 3.7 pounds per year. A sample of 80 people shows that the mean tuna consumption by a person is 3.3 pounds per year. Assume the population standard deviation is 1.04 pounds. At a = 0.06, can you reject the claim? (a) Identify the null hypothesis and alternative hypothesis. OC. Ho: H#3.3 Hgiµ =3.3 OF. Ho: u53.7 Ha: H> 3.7 OA Ho: H> 3.7 O B. Ho: H=3.7 Hg: u53.7 Ha: u#3.7 O D. Ho: us3.3 O E. Ho: >3.3 Ha:H>3.3 Hiu53.3 (b) Identify the standardized test statistic. z= (Round to two decimal places as needed.) (c) Find the P-value. (Round to three decimal places as needed.) (d) Decide whether to reject or fail to reject the null hypothesis. O B. Reject Ho. There is sufficient evidence to reject the claim that mean tuna consumption is equal to 3.7 O A. Fail to reject Hn. There is not sufficient evidence to reject the claim that mean tuna consumption is pounds. equal to 3.7 pounds. O C. Fail to reject Ho. There is sufficient evidence to reject the claim that mean tuna consumption is equal to O D. Reject Ho. There is not sufficient evidence to reject the claim that mean tuna consumption is equal to 3.7 pounds. 3.7 pounds. O Time Remaining: 00:53:03 Next ONE MacBook Air DII DD 80 F10 FB F6 F7 F5 esc F3 F4 F2 F1 @ 23 $ % %3D 3 4 5 7 8 1 Q W E R T Y tab
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